Exponentials Flashcards
e^(lnx) = x
ln[e(^x)] = x
y=e(^x)
x = lnx
In the graph y = e(^x), what would transforming to y = e(^2x) do?
The curve curves upwards more, steeper
In the graph y = e(^x), what would transforming to y = e(^-x) do?
Reflect the graph in the y axis, curve would go backwards:
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\______ instead of _____/
In the graph y = e(^x), what would transforming to y = 10e(^x) do?
The graph would cross the y axis at (0,10) rather than (0,1). Steeper.
In the graph y = e(^x), what would transforming to y = 3 + 4e(^1/2x) do?
Times y value by 4 so it crosses the y axis at (0,4). Move all values up by 3 so that the y value is (0,7) and the curve tends towards the line x=3 instead of x=0. Draw the curve a lot less steeply as the power is 1/2: half as steep.
How would you draw the graph of y=lnx?
Reflect the graph of y=e(^x) in the line y=x.
Passes through the point (1,0) on x axis rather than crossing y axis.
Tends towards y=0 as opposed to x=0.
Domain is all positive numbers ( y > 0), range is all real numbers.
What is lnx?
The inverse to e(^x), like how 4 and -4 are opposites
What is the range and the domain of the graph y = e(^x) ?
Domain is all real numbers
Range is f(x) > 0