Experiment V Flashcards

1
Q

mnemonic to remember electrochemistry electron rules

A

LEO is a GERC

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2
Q

spontaneous reaction

A

SOA and SRA are on the left side of the equation

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3
Q

non-spont. reaction

A

SOA and SRA are on the left side of the equation

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4
Q

reduced form of a half reaction

A

(electron on left side)
Ag+ + e- = Ag

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5
Q

oxidized form of a half reaction

A

electron on right side
Ag = Ag+ + e-

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6
Q

galvanic/voltaic cell

A

cell in which current is generated from spontaneous reactions

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7
Q

Electrons flow in what direction

A

negative to positive

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8
Q

salt bridge

A

allows for ion exchange but not wholesale mixing

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9
Q

cell voltage

A

measure of the driving force or the degree of spontaneity of the reaction

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10
Q

Halogen reaction general form

A

X2 + 2e- = 2X-

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11
Q

how does can halogens inform us about the spontaneity of reactions

A

Halogen are highly soluble in Hexane, but not water. (like dissolves like)

Ions are highly soluble in water but not hexane.

If hexane changes colour, it means that there is I2 present in it and thus the reaction proceeded

If it does not change colour, it means that there is still only I- present and thus the reaction did not proceed

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12
Q

Ecell of a spontaneous reaction

A

positive

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13
Q

Ecell of a non spontaneous reaction

A

negative

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14
Q

What colour would iodine change the colour of hexane to

A

reddish purple - purple

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15
Q

What colour would chloring change the colour of hexane to

A

light yellow

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16
Q

voltage

A

difference between the E° of half cells

17
Q

A

concentration of dissolved species = 1M
pressure of gases = 1M

18
Q

if you have a non-standard cell, what do you use

A

use Nernst equation

19
Q

how is E° cell affected by multiplying half-cell by integer

A

it is not, it is an intensive property and thus unaffeced

20
Q

How should you look at the data table if you want to make a spontaneous cell

A

you need a positive final number, so take the cathode below the anode

21
Q

greater positive E

22
Q

greater negative E

23
Q

Lab V part 3 reaction of precipitate

A

2Ag+ + S2O3^2- = (Ag2)S2O3

and then

(Ag2)S2O3 decomposes into Ag2S

24
Q

what colour is (Ag2)S2O3

A

white/cream precipitate

25
Q

what colour is Ag2S

A

black precipitate

26
Q

ICE table rules for 2Ag+ + S2O3^2

A

If ppt forms, reaction goes to 100%
If no ppt forms, ICE table has a stoich shift, then a small change to equilibrium

27
Q

what colour is Ag(S2O3)2^3-

A

colourless and clear. not a precipitate

28
Q

cell shorthand for a cell that produces precipitate

A

Ag(s) | Ag+(? M) ∥ Ag+(1 M) | Ag(s)

29
Q

Why is the Ag+(?M) the anode

A

Because Ag+ is the concentration of of ions after the formation of the complex ion, thus there is a lower concentration of them in the solution

This means the Ag electrode will oxidized, so that Ag+ concentration increases

The extra e- formed during the oxidation, travels to the cathode

29
Q

Why is the Ag+(?M) the anode, when forming

A

Because the Ag+ is the concentration of ions after precipitating, there is a lower concentration in the solution.

That means the Ag electrode will be oxidized, so that Ag+ concentration increases.

The extra e- formed during the oxidation, travel to the cathode