Example Questions Unit 6

Question 1

how much heat is needed to raise the temperature of 500g water from 20 to 100 degrees

Answer 1

q=m x c◇t

(500) (4.18J/g°c) (80°c)

=167,000

Question 2

if 200J heat is added to 25g of iron at a temp of 15°c what will be the final temperature

Answer 2

1st need to find specific heat of iron on the table

then solve for temperature

◇T = Q/ c x m

200J/0.45 (25g)

18°C 15+18=33

Question 3

calculate quantity of heat required to raise temp of 9.25L water from 22°C to 29.4°C

Answer 3

9250g (4.18)(29.4°C-22°C) = 286121

Question 4

when 2.1J heat was added to 40.0g of PB the temp rose from 20°C to 423°c what was the specific heat of lead?

Answer 4

C=Q/m ◇ T 2100J/40g (423-20) = 0.130J