Exam questions Statistics (sample/real) Flashcards
e) comment on the assumption that the mass of the contents of the packets is normally distributed
a)
-rectangle wdth/ class wdth
=0.4
-wdth= 0.4 x 5 = 2cm
area= 12
fre= 15
therefore 1cm^2 = 5/4 pacet
fre= 9
9/ 5/4 = 7.2 cm^2
7.2/ 2 = 3.6 cm heght
b)
Lower class end + (how much in/ frequency) * class width
c)
use calculator
show method
d)
H0: mew= 250 H1: mew > 250
X~ N (250, 4^2)
then do mean version
250.4 from part c
P(Xbar > 250.4)= 0.171
LE = 250.4
UE= 999
0.171> 0.05 dont reject Ho
e) valid for normal distribution, as mean is close to median
7) find z values
1.2<1.3
Female relatively taller higher standard deviation above mean
Another way of representing PMCC
r value
critical region def
region where null hypothesis is rejected