Exam Questions Flashcards
Q 16
sentence correction practice questions packet 1
each other is for 2 things
one another is for 3 or more things
Q 15 sentence correction
sentence correction practice questions packet 1
had been plu perfect something that had happened before, past the past
this should be has been
Q. 7 sentence correction practice questions packet 1
Like X, Y the Y and X are what you are comparing!
Q. 1 sentence correction practice questions packet 1
- they is too ambigious for B so B is wrong
E clarifies the ambiguity
they has to be a population of people has to be specific
THOSE the GMAT loves those is not a pronoun it is a purely gramatical construction that can be used
those can be used to refer to anything it is a noun replacement versus they has to be people or things, has to refer to a specific subect!!! so have to be careful when you use they!!!!
Exam 5 Q23
x=2 vertical line infant slope, undefined infinity over dover x=2
y= 4 horizontal line slope 0,
vertical line x=2 undefined slope, anything else is a numerical slope
Consider the equation:
y=mx+c ———— Equation (1)
Now, given is that slope is 0, so, m=0
If you substitute in Equation (1), you get
y=3
Now, y=3 is a horizontal line on the xy-plane, which has a slope ZERO.
Also,
consider x=2,
x=2 is a vertical line, and slope of a vertical line is undefined,
As the points on a vertical line would have same x-coordinate value.
slope = m = (y2-y1)/(x2-x1)
Option III, you have y=-x, so slope = -1.
Exam 5 Q 11
Exam 5 Q27
WHENEVER you are given a systems of equations you must look out for if they are divisible
we want to know 2a+3o= X
here b 6a+9o=80 so just divide by 3 thi sis multiple!!! WATCH OUT FOR IT!!!!!
ANSWER IS B
Exam 5 Q9
Online Exam 5 Q12
Online Exam 5 Q7
Online Exam 5 Q25
Online Exam 5 Q17
active is always better than passive always so comprised of…. c which I did is passive, a is better
ex John threw the ball active
The ball was through by John passive BAD
comprises is active and much better than comprised of which is passive
also for possibility of you need a verb that is ing so the possibility of going to the movies works
not possibility of to go to movies, need possiblity …. of being comprised of an even # of days
Paper test 28 sentence correction Q5
adverbs modify adjectives so you have to have an ly for adverbs has to be seemingly unlimited number of antibodies…..
so has to be seemingly unlimtited number…… and also each targeted specifically bc each is singular
Answer is E
Paper test 28 sentence correction Q10
what is they
army is a singular so it has it or no pronoun
the only one without a pronoun is E why E is correct
All the other answers are incorrect bc they have a they or their, bc army is singular and do not need pronoun
Army singular!!! wrong pronoun no they or their
Paper test 28 sentence correction Q19
E. answer when repeat subject like that tissue, tissue is really clearing up an ambiguity and a good thign for setnences
ex this business was founding on certain principles, principles that….. this is a trick they always do
that is correct !!! you are
Exam 12.13.23
Absolute value IxI<1
1. X^2>1
2. x>-1/2
x^2>1 is synomymous to absolute value of IxI > 1
or IxI<2 and x^2 <4** same thing*
X^2-4<0 x-1<0, what are values for x?
so x-1<0 just means x<1
x^2<4 which does exactly what we just did. X<2 and x>-2
-2<x<2 NO
full thing is -2<x<1
has to be x<1 supersedes x<2 so answer has to be -2<x<1
HAS TO BE AN AND
Ppl list of customers who got perscriptions this month. What is the probability that one of the names is chosen from the group who is allowed refills?
1 the group of ppl with refills is 20% greater than the group without refills
2. 288 ppl have refills on the list
what is the probability of refills is hte same question, what is the probability that a customer gets refills? Same as what percent of customers get refills, same as what is the ratio of those who get refills to total number of customers!
refills/refills+no refills, bc refills over total
refills=1.2(no-refills) = x=1.2y
A do not need 288 already have probability!!!!
all piece of information number 1
1.2y/2.2y
B. IF this was the question not the previous card when had 100 not 288, Ys do not cancel!!!
how it would be different, this odesn’t cancel you cannot simplify
this is really a ratios or percentage question!!!
B and J have 10 dollars do they have enough money to pick their selections ?
1. B’s selection cost 4 dollars more than J’s
2. B’s is twice the price of J’s
so you have to frame this is B+J less than or equal to 10
1. not sufficient- could be anything
2. not sufficient could be anything
now put them together
B=J+4
B=2J
2J=J +4 J=4, B=8 so answer is no and that is sufficient to answer the question
answer is C bc it costs 12, and they dont have enough money
Exam 12. 13. 23
Digits abc and cab are 3 digit numbers, 4 digit number dabd. What is a?
1. Abc+cba=dabd
2. B=9
a can’t be zero
B+C has to be greater than 10 bc carry the 1 that is the only way A+B would be B
so B+C>10
so D has to be 1, bc three digit numbers can’t be greater than 2,000 if added together so D has to be 1 so you should know that
if B+A+1= units digit of B then A+1 must equal 10 only way to get back to units digit of B
Answer A
square root of 0.37
=37/100
turn decimals into fractions
bc square root of 100 is 10
square root of 100 is 10, one number if x squared is 100 you are taking square root of both sides, if you are taking the square root of both sides you have to account for possibility x could be 10 or negative 10
0.54
54/100
Exam 12. 13. 23
Average speed traveled 50 miles for x miles per hour and 10 miles for y miles per hour. What is the average speed?
Total distance 60/total time 50/x + 10/y= weighted average!
from exam 12. 13. 23 again bc so difficult
from exam 12. 13. 23
began review with demmer 12.19.23
M and N are integers, is mn divisible by 16?
1. M is 40% less than n or greater
2. 2. M^2-2m is divisible by 16
between the two of them does mn have 4 2s?
- when combine numbers are just strings or molecules molecules in this case are just prime factors
1. tells us nothing besides n is multiple of 5
2. m has to be divisible by 16 so m has to be even! m could be 8, m has to be a multiple of 8 tells us thats it
answer E
not enough information answer is E
From exam 12. 13. 23
began review with demmer 12.19.23
If N is a number, what is the remainder if N is divided by 3?
1. When N is divided by 6 remainder of 2
2. When N is divided by 4 remainder of 2
strategy almost always plug in!!!
- N could be 8, n could be 14 multiple 6 and add 2 technically translates as piece of information number 1 translates as N = 6x+2
N = 8, 14, 20, 26 all divided by 3 give remainder of 2
all divided by 3 give remainder of 2! 8/3 goes in twice 6 plus 2, 14,/3 so 12 plus 2
- N =4x+2 different remainders for all of them 6/2 has 0 remainder
6/3=2 no remainder, 10/3 remainder 1, 14/3 remainder 2, ALL DIFFERENT
so answer is A, 1 is sufficient
plug in numbers
From exam 12. 13. 23
began review with demmer 12.19.23
If all are integers, is r+s even?
1. R-s is even
2. rs is even
- if R-s is even then R+S has to be even- answer is A sufficient
in ever circumstance where R-S is even R+S is always always even!!!!!! - R even S odd
R od S even
R even S even
2 is insufficient
0 is an even integer
IF R XS is even R+X could be even but R+S could also be odd so in that case it is insufficient
From exam 12. 13. 23
I have 25 cents, 5 ents and 10 cents equals $10 dollars. Same amount of 5 cents and 25 cents, and there is 10 cents 1/3 amount of 5 cents. How many ten cents coins do you have? 10?
answer 10
If p is an integer, is p<700?
1. P is a product of prime numbers between 1 and 15
2. P and 70 do not have any common factor
- is insufficient too many options bc 11X13X7=1001
but 5X7X11=385 so not sufficient - this just tells me p doesn’t have a 2, 7, 5*** because if it did than they would be multiples, not enough by itself
so insufficient
so take out 2, 7, 5
3X11X13= 429 so yes less than 700
Answer is C together sufficient
common multiple= multiple divisible by each of those numbres, which again just means a number that shares prime factors with each of those numbers, lets take 140
common multiple=
if p is an integer, is p<700?
1. P is a product of prime numbers between 1 and 15
2. P and 70 do not have any common factor
multiple divisible by each of those numbres, which again just means a number that shares prime factors with each of those numbers, lets take 140
when talking about multiples and factors all you are talking about is shared prime numbers!! if you are talking about multiples adn factors, all you are talking about is collection of primes in each number signature of primes each number has whether they share that signarture, they don’t share that signature the degree to which they share the signature that is all that is
a common factor is just whatever collection of primes they have in common, common multiple is number with full collection of all their primes***
if x has a 2 or P from previous question, if P has a 2 then that number and 70 have a common multiple somewhere in the ether that has so no matter when they say they
if P and 70 do not have a common multiple they avoid each other always in number line so no number any prime factor divisible by each of them**
a common factor…..
a common factor is just whatever collection of primes they have in common, common multiple is number with full collection of all their primes***
the greatest common factor is the intersection of two sets of prime factors and the least common factor is hte union,
Least common multiple
in world of venn diagrams talking about total equals lcm here
GCF
also known as greatest common disivior
for product multiply all factors together from on top of the circles, smash them together that gets product
LCM smash factors in circles together
exam 12. 13. 23
the exam question was something like this:
Square root of box 600 square inches, volume of smaller boxes inside how many boxes wil fit inside the big box which has a square area of 600
exam 12. 13. 23
Fixed cost $5 dollars for 1 hour then after 1 hour charged h. he paid a total of $8, what was h if he worked for 4 ¾ hours?
More probability equations!
Gmat practice questions packet 1