Exam III - Equations Flashcards
Average Value = (Equation)
1/b-a b—-a f(x)dx
Area Between Two Curves = (Equation)
Top Curve - Bottom Curve
What do you do if asked “Find Area Between Two Curves with no [a,b] values?”
f(x) = g(x), set equal to 0 and solve for X values
Integrate using substitution means using?
U Sub
How do you set up U-Sub for: 8x/(4x^2+1) dx
Let U = 4x^2+1
du = 8xdx dx = du/8x
\_\_\_\_\_\_\_\_\_\_ 8x/u^2 x du/8x = 1/u^2 du =u^-2du *Integrate* = u^-1/-1 + C = -u^-1 + C *sub back in* = -(4x^2+1)^-1 + C
infty ——- -3 =
lim b –> infity
3 —— -infty
lim a –> -infty
r =
Rate
t or T =
Years
R(t) =
Yearly Amount
s =
Constant Amount
FV =
Future Value ($)
D =
Constant Money Deposit Annually
To find Equilibrium Point for Consumer & Producer Surpluses you?
Set D(x) = S(x)
Consumer Surplus = (Equation)
X. ——- 0 D(x)dx - (P. x X.)
Producer Surplus = (Equation)
(P. x X.) - X. —– 0 S(x)dx