Exam 4 Flashcards
Nomencalture
_ always have the double bond in the parent chain
Zusammen (Z)
- Cis
- Priorities are on the same side of the double bond
Entgegen (E)
- Trans
- Priorities are on opposite sides of the double bond
Synthesis of Alkenes
E1, E2
H2, Pd/c, CH3OH
Alkyne to Alkane
H2, Lindlars catalyst
Alkyne to a cis alkene
Na, NH3
Alkyne to trans alkene
H-X
Mark addition of a hydrogen and a halogen
1. H added to the less substituted carbon
2. Hydrid shift available for Br to attack
H-X, H2O2
anti mark addition of a hydrogen and a Br
X2
trans addition of two halogens
1. one br makes a bromonium ion
2. second br attacks below to release the first br up
X2, ROH
Trans and anti-mark (Br) addition of a halogen and a polar protic molecule
1. one br makes a bromonium ion
2. the polar protic molecule attacts the more substituted carbon releasing the Br
3. the second Br removes the extra hydrogen
H2SO4, H2O
mark addition of a hydrogen and a polar protic molecule (OH)
1. Acid donates a hydrogen
2. hydride or methyl shift
3. the polar protic solvent attacks the more substituted side
4. acid comes back to take off the extra hydrogen
- Hg(OAC)2
- NaBH3
Mark addition of a hydrogen and an OH group
- BH3, THF
- H2O2, NaOH
anti-mark addition of a hydrogen and an OH group
- CH2N2, Light
- CH2I2, Zn, CuCl
makes a Carbene (:CH2)