exam 3 reagents Flashcards
ch3br/febr3
adds a methyl group
hbr
wont introduce anything OR oxidize. just a strong acid
CH3COCl/AlCl3
acylating agent, introduces an acetyl group
cl2
introduces chlorine to an aromatic ring
ClCH2CH3/AlCl3
introduces an ethyl group to a benzene or negative ion (oh –> o- –> och2ch3)
Zn(Hg)/ hcl
reducing agent, turns a carbonyl (ketone) group into a CH2 (methylene) group
So3/H2SO4
sulfonating agent, introduces sulfuric group
KMnO4
oxidizing agent, benzoic carbon –> carboxylic acid
alkylbenzenes –> carbox. acid derivatives
HCl
wont introduce anything. strong acid. wont oxidize or reduce
K2Cr2O7`
full oxidizer/reducer, turns two OH groups into two ketones
KI
turns N2+ into I
NaNO2/ Hcl
turns Nh2 into N2+ (bondable, not stable and will leave by itself if another atom forms a db to its carbon)
Fe, HCl / NaOH
turns NO2 into NH2
H3PO2
removes N2+ group intirely
CH3I excess
with a NH2 group connected to an alkyl chain
alkyl chain and 3 CH3 groups connected to N (now +), I- is floating
Ag2O, H2O
will add DB to least substituted carbons
NaNH2, NH3 with a benzoic halogen
will make an alkyne with closest benzoic DB
two possible products
H2O2 with a benzylic halogen
will add db to the most substituted carbon in place of the new amino group
CuI, N(CH3)3 with an alkyne
replace original halogen with an alkyne group
NaNH2, NH3
benzyne reagents, pulls off halogen and forms TB
what reagent will turn NH2 into N2+
NaNO2/HCl
what reagent will turn OH into OCH3
(usually on a benzene ring) 2 WAYSSS***
CH3I / OH-
or
CH3OH (CH3O-)
H3PO4
would turn an OH group into a double bond, forming on the most substituted carbons
CH2I2 / Zn(Cu), et
the double bond present will add a carbon and make an isopropyl (triangle) group