Exam 3 Flashcards

1
Q

Chloroplast DNA (cpDNA) Heredity

A

maternally inherited

Green (Normal cpDNA) – In healthy plants, chloroplasts contain functional genes for chlorophyll production, resulting in green leaves due to efficient photosynthesis.

White or Yellow (Mutant cpDNA) – Some mutations disrupt chlorophyll biosynthesis, leading to chloroplasts that lack pigmentation, causing white or yellow sectors in leaves.

Variegation (Mixed cpDNA Populations - Heteroplasmy) – Some plants inherit a mix of normal and mutant chloroplasts, leading to patchy green and white/yellow patterns on leaves. This can occur due to random segregation of cpDNA during cell division.

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2
Q

Mitochondrial DNA (mtDNA)

A

inherited maternally

double-stranded circular D N A

A cell can contain a mix of normal and mutated mtDNA

Threshold Effect – Symptoms of mtDNA mutations appear when the percentage of mutated mitochondria crosses a certain threshold

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3
Q

Endosymbiotic theory (Lynn Margulis et al.)

A

Mitochondria and chloroplasts (organelles) arose independently 2 billion years ago from free-living bacteria
Organelles possessed attributes of aerobic respiration and photosynthesis, respectively

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4
Q

m t D N A susceptible to mutations

A

No structural protection from histones

D N A repair mechanism limited

High concentrations of R O S (reactive oxygen species) generated by cell respiration

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5
Q

The Particle Theory of Inheritance

A

states that hereditary traits act like particles, units, or factors as they are passed from generation to generation.

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6
Q

Law of Segregation

A

states that his hereditary factors do not blend but remain distinct during breeding—thus, disproving the blending theory.

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7
Q

Law of Independent Assortment

A

which states that character traits are not connected but are inherited independent of one another

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8
Q

Map distance math

A

(recombinant #)/total X 100

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9
Q

Chi square math

A

(Expected-observed)^2/observed

Add together

Degree of freedom: # of freedom - 1

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10
Q

Three-point

A

Cross two true-breeding strains that differ with regard to three alleles

Perform a testcross by mating F1 female heterozygotes to male flies that are homozygous recessive for all three alleles

Collect and analyze data from F2 offspring (propose a hypothesis, apply the chi square formula and interpret the chi square value)

Calculate the map distance between pairs of genes

Construct the map

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11
Q

Aneuploidy

A

involves a condition where one or a few chromosomes are added or deleted from the normal chromosome number

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12
Q

Euploidy

A

a state where the chromosome number is an exact multiple of the basic chromosome set,

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13
Q

Nondisjunction

A

Paired homologs fail to separate during segregation

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14
Q

monosomy

A

a chromosomal abnormality that occurs when a cell has only one chromosome from a pair, instead of the usual two

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15
Q

trisomy

A

a genetic condition where an individual has an extra copy of a specific chromosome

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16
Q

Chromosomal Deletion

A

a genetic mutation where a portion of a chromosome is missing

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17
Q

Duplications

A

usually caused by abnormal events during recombination

Repetitive sequences can cause misalignment between homologous chromosomes.

If a crossover occurs, nonallelic homologous recombination results

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18
Q

Chromosomal Inversion

A

A chromosome with an inversion has a segment that has been flipped to the opposite orientation

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19
Q

Paracentric inversion heterozygote results in gametes

A

One gamete with normal chromosome

One gamete dicentric (two centromeres; duplication and deletion)

One gamete with inversion

One gamete acentric (no centromere; duplication and deletion)

20
Q

Chromosomal Paracentric inversion

A

a chromosomal rearrangement that occurs when a chromosome breaks in two places on the same arm. The broken segment is then reinserted after a 180° rotation.

21
Q

Pericentric inversion heterozygote results

A

One gamete with normal chromosome
One gamete with inversion
Two gametes with duplications and deletions

22
Q

Chromosomal Pericentric inversion

A

a chromosomal rearrangement where a segment of a chromosome, including the centromere, is inverted, meaning it’s flipped 180 degrees and reinserted into the chromosome.

23
Q

Translocations

A

a chromosomal abnormality that occurs when parts of two chromosomes are exchanged or fused

24
Q

Mutation

A

a heritable change in the genetic material

Mutations provide allelic variations

25
Q
  1. Chromosome mutations
A

Changes in chromosome structure

Deletions, insertions, duplications, translocations

26
Q
  1. Genome mutations
A

Changes in chromosome number
Euploidy (multiple of all), aneuploidy (multiple of one)

27
Q
  1. Gene mutations
A

Relatively small change in DNA structure that affects a single gene

28
Q

transition base

A

a change of a pyrimidine (C, T) to another pyrimidine or a purine (A, G) to another purine

29
Q

transversion base

A

a change of a pyrimidine to a purine or vice versa

30
Q

Spontaneous mutation:

A

Changes in nucleotide sequence that occur naturally

Arise from normal biological or chemical processes that alter nitrogenous bases

Spontaneous mutation rates vary, but are exceedingly low for all organisms

31
Q

Spontaneous Tautomeric Shifts

A

Enols may form due to tautomeric shifts in which a carbonyl group will be converted into a hydroxy group or an amine group may convert into an imino group.

Changes available donor and acceptors with nitrogenous bases

32
Q

Induced Mutations

A

changes in the number or structure of chromosomes caused by environmental factors or mutagens like chemicals or radiation

33
Q

Alkylating agent mutagens

A

Adding alkyl groups (methyl, ethyl, propyl, etc) to an amino or keto group

Alter base-pairing affinity

34
Q

Intercalating Agents

A

Chemicals with dimensions and shapes that wedge between D N A base pairs

This causes base-pair distortions and D N A unwinding

Forces bulges in DNA so it cannot be unbound

35
Q

Base analogs (mutagenic chemicals)

A

Can substitute for purines or pyrimidines during nucleic acid biosynthesis

Increase tautomeric shifts

Increase sensitivity to U V light—mutagenic

Example: 5-Bromouracil behaves as thymine analog

36
Q

U V Light—Pyrimidine Dimers

A

Two identical pyrimidines that distort D N A conformation
Errors can be introduced during D N A replication

37
Q

Nucleotide Excision Repair

A

This type of system can repair many types of DNA damage, including
Thymine dimers and chemically modified bases missing bases, some types of crosslinks

38
Q

Two types of excision repair

A

Base excision repair (B E R)
Nucleotide excision repair (N E R)

39
Q

Base excision repair (B E R)

A

Corrects D N A containing a damaged D N A base
D N A glycosylase recognizes altered base

40
Q

Nucleotide excision repair (N E R)

A

Repairs bulky lesions that alter/distort double helix

41
Q

Base and nucleotide excision repair steps

A

Recognition of mutation (eg: deamination of cytosine to uracil which uracil DNA glycosylase can immediately detect uracil in DNA)

Excision of mutated base (the strand is broken with AP endonuclease between polypeptide bonds)

Repair (the other strand is used as a template to fill in the gap with Pol and ligase)

42
Q

D N A Repair associated with DNA replication

A

Proofreading and mismatch repair
D N A polymerase “proofreads,” removes and replaces incorrectly inserted nucleotides

Mismatch repair (if proofreading fails) becomes activated

Mismatches are detected, cut, and removed (endonuclease and exonuclease).

Correct nucleotide inserted by D N A polymerase

43
Q

Strand Discrimination

A

Based on D N A methylation

Adenine methylase (enzyme in bacteria) recognizes D N A sequences and adds methyl group to adenine residues

Newly synthesized strand of replication remains unmethylated

Mismatch repair recognizes unmethylated strand and repairs

44
Q

Postreplication Repair

A

Responds after damaged D N A has escaped repair and has failed complete replication

RecA protein directs recombination exchange with corresponding region on undamaged parental strand (donor D N A)

Gap can be filled in by repair synthesis

45
Q

Double-Strand Break Repair - 2

A

Homologous recombination repair pathway

Nonhomologous end joining pathway

46
Q

Homologous recombination repair pathway

A

Recognizes break, digests 5’ end, and leaves 3’ overhang

3’ end aligns with sequence complementary on sister chromatid

Occurs during late S or early G2 phase of cell cycle

47
Q

Nonhomologous end joining pathway

A

Activated in G1 prior to replication

Repairs double-strand breaks

Complex of proteins is involved in end joining

May include kinase and B R C A 1

Proteins bind free ends and ligate ends back together