exam 2 notes Flashcards
Chain rule
f(x) = cos(x
^2)
-sin(x^2)*2x
Chain rule
g(x) = e^x2+3x−1
(2x+3)e^x^2 + 3x-1
Chain rule:h(x) = √
5x^2 − 1
1
/ *10
2square5x^2-1
Chain rule
j(x) = sin^3
(4x + 1)
12sin^2(4x+1)cos(4x+1)
chain rule:
k(x) = tan(xe^sin x
)
sec^2(xe^sinx)[xe^sin x down cos x+e^sinx
Chain rule:
5^x
ln(5)*5^x
chain rule:
3^sinx
ln(3)*3 ^sin(x) down cos(x)
chain rule:
sec(π^x)
sec(pi ^x)tan(pi^x)*(ln pi)pi^x
implicit differentiation:
y^3 + 2x^3 − y = x^2
2x-6x^2/3y^2 -1
implicit differentaition:
x + sin(y) = xy
y-1/cos(y)x
implicit differentiation:Determine all points where the tangent line to x^4 + y^2 = 3 is horizontal or vertical.
Horizontal:(0,+_3
Vertical:(+-4 square 3,0
Implicit differentiation:
Before the development of the Calculus, Fermat had developed a method of finding tangents. When Descartes was informed of Fermat’s method, he didn’t believe it and challenging Fermat to find the
tangent to the curve x^3 + y
^3 = 2xy, predicting that he would fail. Descartes was unable to solve the
problem himself and was intensely irritated when Fermat solved it easily.
-Given x^3 + y^3 = 2xy determine the equation of the tangent line at the point (1, 1)
-A normal line is defined to be the line perpendicular to the tangent line at the point of tangency. Find
the normal line to x^3 + y
^3 = 2xy at the point (1, 1).
a.-x+2
b.y=x
Differentiation of Log, Inverse Trig
ln(x^2 + 1) =
2x/x^2+1
Differentiation of Log, Inverse Trig
log down 5(x^3 − tan(x)) =
3x^2-sec^2(x)/ln(5)(x^3-tanx)
Differentiation of Log, Inverse Trig
ln(x^2sin(x)) =
2xsin(x)+z^2cosx/x^2sin(x)
Differentiation of Log, Inverse Trig
squarex^2−1/
x cos(x) =
[x/x^2-1 - 1/2x -sinx/2cosx] [square x2-1/xcos(x)
Differentiation of Log, Inverse Trig
x^sin x =
[sinx/x + cosxlnx]x^sinx