Exam 2 Flashcards
Aqueous solution: solvent = ?
water = solvent
Dissociation
species break apart;
A –> B + C
Ionization
dissociation into 2 ionic species;
A –> B- + C+
M =
mol/L
Cm^3 =
mL
Equilibrium constant for dissociation in water @ 25°C (Kw) =
1.0 x 10^(-14)
[H+] > 1 x 10^(-7) M =
acidic!
(implies [OH-] < 1 x 10^(-7) M)
[H+] < 1 x 10^(-7) M =
basic!
(implies [OH-] > 1 x 10^(-7) M)
[H+] = 1 x 10^(-7) M =
neutral!
(implies [OH-] = 1 x 10^(-7) M)
pH
calculated w/ equilibrium concentration of H+ and OH-
↑ acidity = ____ pH
↓ pH
↑ basic = _____pOH
↓pOH
↑ pH = _____ pOH
↓ pOH (inverse)
pOH + pH =
14 (at 298 K)
pH < 7 =
acidic
pH = 7
neutral
pH > 7
basic
strong acids (list):
HCl, HBr, HI, HNO3, HClO4, H2SO4
strong bases (list):
Group 1: LiOH, NaOH, KOH
Group 2: Ca(OH)2, Sr(OH)2, Ba(OH)2
Strong acids (SA):
- completely ionize in water
- Release 1 mol H+ / 1 mole of strong acid in water
Group 1A (alkali metals) strong bases:
Release 1 mol OH- / 1 mol strong base in water
Group 2A (alkaline earth metals) strong bases:
Release 2 mol OH- / 1 mol strong base in water
Weak acid:
partially dissociate in water
- Holds onto proton
- Smaller dissociation constants
Ka =
(products) / (reactants)
Cations behave like ___ ____ except strong bases (Li+, Na+, Ca2+, Sr2+, Ba2+)
weak acids
Weaker acid =
↓ Ka = ↑ pKa
Stronger acid =
↑ Ka = ↓ pKa
the acid dissociation constant of a weak acid will be…
much smaller than 1
Calculating H+ concentration due to a weak acid will invariably involve _____ ______
equilibrium tables!
cation
positively charged ion
anion
negatively charged ion
M =
mol/L (molarity)
x =
extent of hydroxide ionization
WGJ equation: x =
x = [OH-] = sqrt (KbMb) = (KbMb)^(1/2)
Weaker acid =
↓ Ka = ↑ pKa
Stronger acid =
↑ Ka = ↓ pKa
Weaker base =
↓ Kb = ↑ pKb
Stronger base =
↑ Kb = ↓ pKb