Exam 1 Chapters 19-22 Flashcards
What is the difference between a conductor and an insulator?
Conductor- Usually metal, has 0 electric field, has free charges
Insulator- Usually non metal, has an electric field, has NO free charges
What does Coulomb’s law state?
Where
F= ma (mass x acceleration)
Q and q= Charges
r= Distance between the two charges
k= 8.99 x 10^9 (N x m^2/C^2)
The attractive force between the point charges 8.44E-6C and Q has a magnitude of 0.975N when the separation between the charges is 1.31m Find the sign and magnitude of the charge Q.
Q= 2.2E-5
Given that Q1= +12uC and d= 0.16m, find the direction and magnitude of the net electrostatic force exerted on the point charge q1
F1= F(1,2) + F(1,3)
F1= [k(+q)(2q) / (d^2)] + [k(+q)(3q) / 2(d^2)]
F1= [8.99E9(1 x 12E-6)(-2 x 12E-6) / (0.16^2)] + [8.99E9(1x 12E-6)(3x 12E-6) / (2 x0.16^2)]
F1= -101.13 + 37.89
F1= 63.24 (Would be negative to specify direction)
Suppose that a charge q2 can be moved left or right along the line connecting the charges q1 and q3. Given that q= +12uC, find the distance from q1 where q2 experiences a net electrostatic force of 0. The charges q1 and q3 are separated by a fixed distance of 0.32m.
Distance between 1 and 2= ? (X)
Distance between 1 and 3= (.32m-X)
F2= F(2,1) + F(2,3) BUT where F2=0
0= [k(-2q)(1q) / x^2] + [k(-2q)(3q) / (0.32m-x)^2]
- [k(-2q)(1q) / x^2] = [k(-2q)(3q) / (0.32m-x)^2]
(k’s and -2q’s cancel eachother out)
- [(1q)(0.32m-x)^2] = [(3q)(x^2)] > Do 3q/q= 3 and take square root
- (0.32m-x) = sqrt3(x)
x= (0.32m)/ 1 +- sqrt 3
x= 0.12 and -0.45
Find the orbital radius for which the kinetic energy of the electron in example 19-1 is 1.51 ev.
*1ev = 1 electron volt = 1.6E-19
* F electrical = F centripetal
[k(q1)(q2)/r^2] = ma (centripetal) is equivalent to…
[k(e)^2/r^2] = m (v^2/r) > e is for electron
V^2 = k(e^2)/ (r)(m)
Kinetic energy= (1/2)(m)(v^2)
V^2= (K)(2)/(m) > Set v^2’s equal to each other
k(e^2)/ (r)(m) = (K)(2)/(m)
Where r= k(e^2)/ 2K
r= (8.99E9)(1.6E-19C^2)/ 2(1.51ev)(1.60E-19)
r= 4.76E-10
Four point charges are located at the corners of a square with sides of length a. Two of the charges are +q and two are -q. Find the magnitude and direction of the net electric force exerted on a charge +Q, located t the center of the square, for each of the following 2 arrangements of charge; the charges alternate in sign +q,-q,+q,-q as you go around the square; the two positive charges are on the top corners, and the two negative charges are on the bottom corners.
- The first box has a F(net) of zero because the charges cancel out
- F(net)= 2F(x) + 2F(y) where a= Length
F(net)= 2[KqQ/ (a/sqrt2)^2] x sin(45) + 2[KqQ/ (a/sqrt2)^2] x sin(45)
F(net)= [-4(sqrt2)kqQ/ a^2]
What is the equation when charge Q is distributed over a sphere?
What is the magnitude of the electric field produced by a charge of magnitude 7.5uC at a distance of 1m and 2m?
Equation for electric field: E= kq/r^2
- E= [(8.99E9)(7.5)/(1)^2]= 6.74E10
- E= [(8.99E9)(7.5)/(2)^2]= 1.68E10
What is the equation for electric field?
E= k(q)/(r)^2
For point charges, each of magnitude q are located at the corners of a square with sides of length a. Two of the chargess are +q and two are -q. The charges are alternate in sign as you go around the square. The top 2 corners of the square have positive charges (-q,+q). In which case will the electric field at the center of the square have the greatest magnitude? Calculate the electric field at the center of the square for each of these 2 cases.
E= [kq/(1/2)(a^2)]
E1x + E2x + E3x + E4x= [kq/(1/2r^2) 1/sqrt2 +-1/sqrt2 + 1/sqrt2 +-1/sqrt2 = 0
E1y + E2y + E3xy+ E4y= -1/sqrt2 - 1/sqrt2 - 1/sqrt2 - 1/sqrt2 = [-4sqrt2(k)(q)/(r)^2]
The electric field lines surrounding 3 choices are shown. The center charge is q2= -10uC. What are the signs of q1 and q3? Find q3.
- Charges q1 and q3 must be positive
- The charge q1 has 8 lines leaving it, but q2 has 16 lines entering it. Because 8 is half of 16, and since the number of lines entering or leaving a charge is proportional to the magnitude of the charge, the magnitude of q1, is one-half of q2, or 5uC.
- By the reasoning of part b, the magnitude of q3 is 5uC
A surface encloses the charges q1= 3.2uC, q2= 6.9uC, and q3= -4.1uC. Find the electric flux through this surface.
6.8E-12 Nm^2/C
What is the equation for electric flux?
What is the eqaution of electric field?
E= kq/r^2
The cell membrane of a typical nerve cell consists of an inner and an outter wall separated by a distance of 0.10um. The electric fields within the cell membrane is 7.5E5. Approximating the cell membrane as a parallel-plate capacitator, determine the magnitude of the charge density on an inner and outer cell walls
A uniform electric field of magnitude 4.1E5 N/C points in the positive x-direction. Find the change in electric potential energy of a 4.5uC charge as it moves from the origin to the points (0,6m) (6m,0) (6m,6m)