Exam 1 Flashcards

1
Q

Optimistic method

A

pick the best number to represent an option and choose the the best option based on those numbers

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2
Q

Pessimistic method

A

pick the worst number to represent an option and choose the best option based on those numbers

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3
Q

Harwitz method

A
alpha x (best) + (1 - alpha) x worst
use equation for each option and chose option with best outcome based on the equation
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4
Q

Minimax Regret

A

create a table based on original table given, find the best option per situation not option assign a value of 0, calculate difference between value of best situation and the other situations, choose the option that presents the least amount of regret

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5
Q

Equal likelyhood

A

Find the average of the outcomes for each option. Choose the option with the highest average.

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6
Q

Decision Tree

A

composed of two nodes: Decision nodes and Chance nodes. When evaluating always start at the end and work back ward. Final answer should be the option not the expected value

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7
Q

Decision node

A

choices of options

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8
Q

Chance node

A

probability

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9
Q

Expected value of Perfect Information

A

EV(w/ PI) - EV(w/o PI)

• Note: the quality of decision with PI should be better or equal to never worse than decision w/o PI

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10
Q

Discrete problem

A

The choice of locations are pre determined

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11
Q

Continuous problem

A

Infinite possible locations to choose from. 2 options Minisum and minimax

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12
Q

Minisum discrete problems

A

Minimize total travel time. Sum of demand x distance for each option. Must check each quantity of possibilities. Ex copier example, have to check 1 copier vs 2 copiers vs 3 copiers…etc. The number of options for each number of copiers is:
x! / (y! * (x - y)!)

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13
Q

Minimax discrete problems

A

Minimize the maximum travel time. This is more related to service like fire stations

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14
Q

straight line distance equation

A

sqrt((x1 - x)^2 + (y1 - y)^2)

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15
Q

rectilinear distance equation

A

x1 - x | + | y1 - y |

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16
Q

Minisum straight line distance

A
Objective Function: Min ∑ wi * di^2
di = sqrt((x1 - x)^2 + (y1 - y)^2)
x* = ( ∑ xi * wi ) / ( ∑ wi )
y* = ( ∑ yi * wi ) / ( ∑ wi )
best location: (x*, y*)
17
Q

Minisum rectilinear distance

A

Objective Function: Min ∑ wi * di
di = | x1 - x | + | y1 - y |
• find 1/2 ∑ wi
• create a number line for x and y coordinate sorting from left to right in increasing order
• assign weights below each location
• choose x or y coordinate where to sum of weights to the left and right of the chosen coordinate are less than 1/2 ∑ wi
best location: (x, y)

18
Q

Minimax rectilinear distance (algorithm)

A
• Note: no demand information is needed
• Create table with xi, yi, xi + yi, and -xi + yi columns
• find the following
C1 = min (xi + yi)
C2 = max (xi + yi)
C3 = min (-xi + yi)