Exam 1 Flashcards

1
Q

vmp

A

most probable speed.
occurs at the maximum in the distribution
the speed that has the greatest number of molecules

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2
Q

vave

A

there are more molecules with high speed than low speed

vave>vmp

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3
Q

vrms

A

speed is squared before taking average
More weight to high speeds
vrms>vave

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4
Q

What happens as a reaction proceeds?

A

rate decreases as reactants are used up

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5
Q

Why is a random walk a good model for behavior of gases?

A

Each collision causes a gas molecules to go in a new random direction

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6
Q

What behavior is equivalent to taking a step?

A

A collision is equivalent to taking a step.

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7
Q

What is the equivalent of the length of the step?

A

The length is the distance traveled between collisions and is equal to the mean free path

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8
Q

What is the equivalent of the number of steps in the walk?

A

Collision frequency

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9
Q

What does the steady state approximation assume about the concentration of I during a reaction?

A

d[I]/dt = 0

[I] is constant

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10
Q

What must be true about the relative magnitudes of the two rate constants for the steady state approximation to be true?

A

k2»k1
[I] will be low and fairly constant

if k1»k2 [I] will be a maximum then decrease => never constant

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11
Q

Does the viscocity of a liquid increase, decrease, or stay constant as the temp is increased?

A

Decrease
Viscosity in liquids is due to attractive forces between molecules
higher temp => greater KE => easier to overcome attractive forces

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12
Q

Does the viscosity of a gas increase, decrease of stay constant as the temp is increased?

A

Increase
Viscosity in gases is due to transfer of momentum due to molecular collisions
higher temp => greater speed => more momentum to transfer

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13
Q

Consider a mixture of helium and CO2. Which type of collision will occur with the greatest total collision frequency?

A

Between small fast ‘bullets’ (He) and big slow ‘targets’ (CO2)

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14
Q

km

A

measures binding of enzyme to substrate

larger km=> worse binding

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15
Q

kcat

A

measures how effective enzyme is at creating product and ‘turning over’ free enzyme once enzyme and substrate are bound

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16
Q

vmax (enzyme)

A

fastest rate possible
Occurs at very high substrate concentration
proportional to kcat

17
Q

I vmax is unchanged by inhibitor concentration, would you expect the inhibitor to bind to the same binding site on the enzyme as the substrate of to a different size?

A

Inhibitor must be interfering with binding => binding at same site
vmax unchanged => enzyme’s ability to convert enzyme to product once bound is unaffected
with enough substrate, rate is as fast as without inhibitor