ES almn: Risks & benefits of chlorine; iodine-thiosulfate titrations; hydrogen halides Flashcards
What specific risks does chlorine pose to humans?
Toxic:
- Irritation of eyes, skin, respiratory system
- Reacts in lungs to form HCl, causing drowning
Chlorine is transported in pressurised tanks which are usually lined with steel. Why is it essential that the interior of a tank is dry?
Chlorine reacts with water to produce corrosive acids.
What are the 2 main uses of chlorine?
- Sterilising water by killing bacteria
- Making bleach
What is the formula of sodium thiosulfate?
Na2S2O3
2 Na+ ionically bonded to S2O32-
An iodine-thiosulfate titration involves what type of reaction?
Redox
What are iodine-thiosulfate titrations used for?
Finding the concentration of a chemical which is a strong enough oxidising agent to oxidise iodide ions.
The equilibrium below was investigated:
H2(g) + I2 (g) ⇌ 2HI(g)
Mixtures of known masses of hydrogen and iodine were allowed to react in sealed tubes until equilibrium was established. The tubes were rapidly cooled. The iodine present was analysed.
- Suggest why the flasks are cooled
- Describe how a sealed tube could be investigated to measure the mass of iodine it contained
- To preserve equilibrium position
- Titrate with thiosulfate of known concentration. Mass I2 = 0.5 x mol thiosulfate x 253.8
What equation is used to work out atom economy?
(Mr of desired product x 100) / total Mr of reactants/products
Explain the difference between a co-product and by-product.
- Co-product: from intended reaction. Useful
- By-product: from side reactions. Not useful
How is hydrogen chloride produced industrially?
- Done at plants producing Cl2 and H2 from brine by electrolysis
- H2 (g) + Cl2 (g) → 2HCl(g)
What is the strongest oxidising agent in group 7?
Fluorine
Give equations, with state symbols, to show how the following halides react with sulfuric acid.
- Sodium fluoride
- Sodium chloride
- Sodium bromide
- Sodium iodide
Sodium fluoride + chloride:
Sodium fluoride/chloride + sulfuric acid → hydrogen fluoride/chloride + sodium hydrogen sulfate
NaF(s) + H2SO4(aq)→ HF(aq) + NaHSO4(aq)
NaCl(s) + H2SO4(aq)→ HCl(aq) + NaHSO4(aq)
Sodium bromide:
Br- ions are strong enough reducing agents to reduce sulfuric acid to sulfur dioxide:
2NaBr(s) + H2SO4(aq) + 2H+(aq) → Br2(l) + SO2(g) + 2H2O(l) + 2Na+(aq)
This reaction occurs, but only to a small extent: NaBr(s) + H2SO4(aq) → HBr(g) + NaHSO4
Sodium iodide:
I- ions are strong enough reducing agents to reduce sulfuric acid to hydrogen sulfide:
8NaI(s) + H2SO4(aq) + 8H+(aq) → 4I2(s) + H2S(g) + 4H2O(l) + 8Na+(aq)
This reaction occurs, but only to a small extent: NaI(s) + H2SO4(aq) → HI(g) + NaHSO4
- Why is adding concentrated sulfuric acid to sodium bromide not a good way to produce hydrogen bromide?
- What is used instead?
- They react to produce some HBr, but Br- ions reduce sulfuric acid to sulfur dioxide. Gas produced is an impure mixture of HBr, SO2 + Br2
- Phosphoric acid
- Why is adding concentrated sulfuric acid to sodium iodide not a good way to produce hydrogen iodide?
- What is used instead?
- They react to produce some HI, but I- ions reduce sulfuric acid to hydrogen sulfide. Gas produced is an impure mixture of HI + H2S
- Phosphoric acid
I2 is produced in the reactions, but is a solid so isn’t part of the gas mixture
State and explain the trend in thermal stability of the hydrogen halides, observing down the group.
- Thermal stability decreases down group
- Bond enthalpies decrease because:
- Halide ion becomes larger
- Outermost bonding electrons become further from nucleus
- Weaker electrostatic attraction