Equations of motion with constant acceleration Flashcards
First equation of motion with constant acceleration
v = v_0 + a*t
Second equation of motion with constant acceleration
x - x_0 = (v + v_0)*t/2
Third equation of motion with constant acceleration
x = x_0 + v_0t + (at^2)/2
Fourth equation of motion with constant acceleration
v^2 = v_0^2 + 2a(x - x_0)
How to derive first equation
Since acceleration is constant, average acceleration = instantaneous acceleration. Rearrange average acceleration formula.
How to derive second equation
Equate two different formulae for average velocity.
How to derive third equation
Substitute first equation into second equation.
How to derive fourth equation
Rearrange first equation in terms of t, substitute into second equation and rearrange.
What does the first equation say?
Velocity is initial velocity plus constant acceleration times time
What does the second equation say?
Position is initial position plus average velocity times time
What does the third equation say?
Position is initial position plus initial velocity times time plus half of constant accelerations times time squared
What does the fourth equation say?
Velocity squared is initial velocity squared plus two times constant acceleration times displacement between final and initial position