Equations of motion with constant acceleration Flashcards

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1
Q

First equation of motion with constant acceleration

A

v = v_0 + a*t

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2
Q

Second equation of motion with constant acceleration

A

x - x_0 = (v + v_0)*t/2

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3
Q

Third equation of motion with constant acceleration

A

x = x_0 + v_0t + (at^2)/2

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4
Q

Fourth equation of motion with constant acceleration

A

v^2 = v_0^2 + 2a(x - x_0)

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5
Q

How to derive first equation

A

Since acceleration is constant, average acceleration = instantaneous acceleration. Rearrange average acceleration formula.

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6
Q

How to derive second equation

A

Equate two different formulae for average velocity.

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7
Q

How to derive third equation

A

Substitute first equation into second equation.

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8
Q

How to derive fourth equation

A

Rearrange first equation in terms of t, substitute into second equation and rearrange.

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9
Q

What does the first equation say?

A

Velocity is initial velocity plus constant acceleration times time

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10
Q

What does the second equation say?

A

Position is initial position plus average velocity times time

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11
Q

What does the third equation say?

A

Position is initial position plus initial velocity times time plus half of constant accelerations times time squared

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12
Q

What does the fourth equation say?

A

Velocity squared is initial velocity squared plus two times constant acceleration times displacement between final and initial position

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