Enzyme Kinetics Flashcards
Why is the knowledge of enzyme kinetics useful
can quantify and enzymes speed, specificity (towards different substrates) and can be used to study how the activity of an enzyme is affected by other substances (like regulation via inhibitors)
V naught
The initial velocity rate,
= the concentration of substrate disappearing// product produced per unit of time (mol/L*s)
Why does the velocity of an enzyme decrease over time
Product inhibition can slow down the reaction, substrate decreases and thus the enzyme may no longer be saturated?
First-order kinetics
rate is proportional to the substrate concentration
Zero-order kinetics
rate is constant and independent of the substrate concentration
Enzyme activity
measure of the quantity of active enzyme present and is thus dependent on conditions
the practical unit we use is U=enzyme units milimol/min`
Specific activity
The activity of an enzyme per milligram of total protein
this help to give an indication of how pure an enzyme is
units= U/mg
k1
rate of ES formation
k2
rate of product formation
k-1
rate of ES degradaaton
When can k2 be ignored
during inital conditions, V naught
Michealis-Menton equation assumptions
the equilibrium assumptions
Steady state assumptions
The Equilibrium Assumption
assuume equilibrium between E and S and ES, such that, the equilibrium of formation and dissociation is only slightly disturbed by product formation
k2 «_space;k-1
gives us the value Ks, the dissociation constant of the ES complex
this assumption is generally not correct lol
Ks
The dissociation constant of the ES complex.
Tells us how tightly and enzyme binds its substrate
Steady state assumption
assume that the ES complex is in steady state, thus the rate of formation of the ES complex equals that of the ES dissociaiton/ breakdown
Km
Km is the Michaelis-Complex
under assumptions of equilibrium, Km=Ks, and is thus a good way to estimate Ks
How can Km be used
can be thought of a smaller [S] to reach V50% has a greater affinity, thus the smaller the Km, the more specific/ tightly and enzyme can bind a given substrate
For example, glucose Km «_space;Km for Fructose with the enzyme hexokinase. Thus Hexokinase has a higher affinity for glucose over fructose
Kcat
Kcat when [S] -> infinity
Kcat is the turnover number when the enzyme is saturated
-> kcat= overall rate constant
Kcat/Km
Used because the magnitude of Km is often equal to of slightly above the physiological concentration of substrates in pathway that operate at full capacity
And because kcat is defined at saturating levels of the enzyme ie [S]-> infinity
kcat/km is a good indicator of catalytic efficiency, in which the maximum value is 10^8/9 which is a perfect enzyme and means that every collision results in a reaction
rate at which enzyme and substrate collide
Important of the Lineweaver-Burke Double Reciprocal Plot
Because it can be hard to get Vmax when the curve never reaches Vmax, then we cant get Km
Data may be linearized to find Km, however, our worst data contributes the most to the slope :(
still useful today for recognition of enzyme inhibition
What factors does Enzyme concentration have on kinetics
increased enzyme concentration can increase the rate of the reaction, however it DOES NOT affect the Km
that is, the Km for any given enzyme is independent of enzyme concentration when enzyme concentration is limiting for the reaction. (ie// [S] is not limiting)
Why may pH affect enzyme activity
Amino acids in the active site may need to be either protonated/ deprotonated in order to catalzyme the reaction
at super high or low pH enz could denature
Why might Temperature affect enzyme activity
Increase of kineticv energy but at hight temp could denature
Non-MM enzymes
Allosteric enzymes do not follow MM kinetics
-=> exhibit a sigmoidal binding curve (Unless conditions are adjusted)
Regulation by availability of substrate or cofactor
recall that a low [s] ([s] ~km or less) Vo is linearly dependent upon [s]
if [s]»_space; km then an increase in [s] will not affect Vo
need to consider [s] in subcellular compartments where the enzyme is located because [s] can vary between organelles