Engineering Economy Flashcards
Find the interest on P6800.00 for 3 years at 11% simple interest. a. P1,875.00 b. P1,987.00 c. P2,144.00 d. P2,244.00
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How many years will it take the principal amount to double if it is invested in an account that gives 10% ordinary simple interest? a. 5 b. 8 c. 10 d. 16
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A man borrows Php 800.00 from Pikachu and promised to repay him Php 850.00 after 1.5 years. What is the interest rate assuming ordinary simple interest? a. 3.7% b. 4.2% c. 2.1% d. 5.6%
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From August 22, 2011 to February 22, 2012, determine the exact simple interest of the principal Php 5000.00 for 8%. a. Php 201.49 b. Php 721.21 c. Php 124.22 d. Php 219.89
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Pakito borrowed Php 2000 from a bank and promised to pay after 1 year. The bank deducted the interest of Php 80.00 in advance. What is the interest rate? a. 4% b. 2% c. 4.2% d. 7%
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Pakito borrowed Php 2000 from a bank and promised to pay after 1 year. The bank deducted the interest of Php 80.00 in advance. What is the rate of discount? a. 4% b. 2% c. 4.2% d. 7%
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Pakito borrows Php 8000.00 from a bank that has an interest rate of 2% compounded quarterly. How much is the money after 8 years? a. Php 9384.34 b. Php 9348.34 c. Php 8523.66 d. Php 8325.66
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Pakito borrows Php 8000.00 from a bank that has an interest rate of 2% compounded quarterly. How much is the money after 8 quarters? a. Php 9384.34 b. Php 9348.34 c. Php 8523.66 d. Php 8325.66
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A businessman borrows money from a bank and promised to pay Php 5000.00 after 12 months. How much money did he borrow if: Money is worth 8% compounded monthly? a. Php 6414.81 b. Php 1985.57 c. Php 4616.81 d. Php 1895.57
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A businessman borrows money from a bank and promised to pay Php 5000.00 after 12 months. How much money did he borrow if: Money is worth 8% monthly? a. Php 6414.81 b. Php 1985.57 c. Php 4616.81 d. Php 1895.57
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How long (in years) will it take for an investment to fivefold its amount if money is worth 14% compounded semi-annually? a. 11 b. 12 c. 13 d. 14
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What is the nominal rate of 4% compounded quarterly if compounded: Monthly? a. 3.987% b. 4.02% c. 4.06% d. 4%
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What is the nominal rate of 4% compounded quarterly if compounded: Semi – annually? a. 3.987% b. 4.02% c. 4.06% d. 4%
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What is the nominal rate of 4% compounded quarterly if compounded: Annually? a. 3.987% b. 4.02% c. 4.06% d. 4%
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Tsupul borrows P10,000 at an interest rate of 8% compounded annually and wishes to repay the loan over a 4 year period with annual payments such that the second is P500 greater than the first payment, the third payment is P1000 greater than the second payment and the fourth payment is P2000 greater than the third payment. The amount of first payments is: a. P1854 b. P1574 c. P1474 d. P1754
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A sum of P1000 is invested now and left for eight years at which time the principal is withdrawn. The interest that has accrued is left for another eight years. If the effective annual interest rate is 5%, what will be the withdrawal amount at the end of the 16th year? a. P706 b. P500 c. P774 d. P799
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Determine the present worth of an annual payment of Php 2500.00 at the end of each year for 12 years at 8% compounded annually. a. P 32, 225.52 b. P 18, 840.20 c. P 47, 442.82 d. P 20, 288.21
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A contractor bought a concrete mixer at Php 120,000 if paid in cash. The mixer may also be purchased by installment to be paid within 5 years. If money is worth 8%, the amount of each annual payment, if all payments are made at the beginning of the year is: a. P 27, 828.50 b. P 29, 568.00 c. P 31, 005.00 d. P 32, 555.00
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A man wishes to establish a fund for his son’s education. He did this so that his son will receive Php 5000.00 every year, for 5 years, starting his son’s 18th birthday. If this fund is established by series of annual payments for 5 years, determine the annual payment if money is worth 8%. a. P 1351.34 b. P 3151.34 c. P3251.34 d. P 3521.34
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Find the annual equivalent worth for the following infinite cash flow series at an interest rate of 10%. Net Cash Flow: 0 0, 1 - 10 Php 400, 11 - ∞ Php 500 a. P 461.20 b. P 438.60 c. P 445.10 d. P 985.40
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An arithmetic gradient with series of end of period payments of P 10,000 on the 1st year, P 8,000 on the 2nd year, P 6,000 on the 3rd year, P 4,000 on the 4th year and P 2.000 on the 5th year. If interest rate is 12%, what is its present worth? a. P 12,125 b. P 23,007 c. P 22,565 d. P 23,254
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A newly acquired machine requires an annual maintenance cost of 10,000 pesos. If the annual maintenance cost increases by 20% each year for 10 years, what is the estimated present worth of the maintenance costs if money is worth 15%? a. P 106,100 b. P 126,100 c. P 116,100 d. P 136,100
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A Php 100,000, 6% bond pays dividends semi-annually and will be redeemed at 110% after 3 years. Find the bond value if money is worth 4% compounded semi-annually. a. Php 114,481.14 b. Php 412,481.14 c. Php 141,814.14 d. Php 142,481.14
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A machine costs P 300,000 new, and must be replaced at the end of each 15 years. If the annual maintenance required is P 5,000, find the capitalized cost, if money is worth 5% and the final salvage value is P 50,000. a. P 631,711.44 b. P 316,171.44 c. P 613,171.44 d. P 613,711.44
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What is the present worth of money if Php 8000.00 is paid after 3 years? The money is worth 8% compounded continuously. a. Php 6293.02 b. Php 2963.02 c. Php 2693.02 d. Php 3296.02
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Determine the effective rate of 8% compounded continuously. a. 8.22% b. 7.95% c. 8.33% d. 7.23%
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A machine cost P 8,850 has a life of 8 years. Determine the depreciation at the end of the third year using double declining balance method. a. P 1,070 b. P 1,244 c. P 1,370 d. P 1,422
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A machine cost P 4,850 has a life of 10 years and a salvage value of P 500. Using straight line method: Determine the book value at the end of the fourth year. a. P 3,110 b. P 435 c. P 1,305 d. P 2,321
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