Energetics-Physical chemistry Flashcards

1
Q

What are the differences between endothermic and exothermic reactions?

A

Endothermic reactions absorb heat energy from the surroundings.

Temperature decreases in the surroundings.

∆H is positive (heat is taken in).

Example: Photosynthesis

Exothermic reactions release heat energy to the surroundings.

Temperature increases in the surroundings.

∆H is negative (heat is released).

Example: Combustion of fuels

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

What is enthalpy change (∆H)?

A

Enthalpy change (∆H) is the heat energy change during a reaction, measured at constant pressure.
∆H can be either positive (endothermic) or negative (exothermic).
Formula:Δ𝐻=𝐻products−𝐻reactants

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

What are standard enthalpy changes?

A

Standard enthalpy change refers to the enthalpy change under standard conditions:

Pressure = 100 kPa

Temperature = 298 K (25°C)
✔ Standard enthalpy changes are measured in kJ/mol.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

What is the standard enthalpy of combustion (∆cHƟ)?

A

What is the standard enthalpy of combustion (∆cHƟ)?
A:
Standard enthalpy of combustion (∆cHƟ) is the enthalpy change when 1 mole of a substance is completely burned in oxygen under standard conditions.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

What is the standard enthalpy of formation (∆fHƟ)?

A

tandard enthalpy of formation (∆fHƟ) is the enthalpy change when 1 mole of a compound is formed from its elements in their standard states under standard conditions.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

What is the equation to calculate heat change (q) in a reaction?

A

The heat change
𝑞
q is given by the equation:
𝑞=𝑚𝑐Δ𝑇
q=mcΔT
Where:

q = heat change in Joules (J)

m = mass of the substance in grams (g)

c = specific heat capacity in J/g°C

ΔT = temperature change (final temperature - initial temperature) in °C

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

How do you use the equation
𝑞=𝑚𝑐Δ𝑇
q=mcΔT in calculations?

A

Step 1: Measure the mass of the substance (m) that is undergoing a temperature change.
Step 2: Measure the initial and final temperature to calculate ΔT.
Step 3: Use the substance’s specific heat capacity (c).
Step 4: Plug values into the equation and solve for q (the heat change).

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

How do you calculate the molar enthalpy change from the heat change?

A

After calculating the total heat change q, to find the molar enthalpy change (ΔH), use the formula:

Δ𝐻=𝑞/n

Where:

q = total heat change in Joules (J)

n = number of moles of the substance reacting

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

What types of related calculations can be done using the equation 𝑞=𝑚𝑐ΔT?

A

You can use this equation to calculate:

The amount of heat required to change the temperature of a substance.

The molar enthalpy change for reactions, given the moles of reactants or products involved.

The temperature change when a known amount of heat is supplied to a substance.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

What is Hess’s Law?

A

Hess’s Law states that the total enthalpy change of a reaction is independent of the path taken, as long as the initial and final conditions are the same.

This means that enthalpy changes can be calculated by summing the enthalpy changes of individual steps of a reaction.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

How can Hess’s Law be used to calculate enthalpy changes?

A

Hess’s Law allows us to calculate the total enthalpy change (∆H) by adding or subtracting the enthalpy changes of reactions, typically using either:

Enthalpies of combustion

Enthalpies of formation

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

How do you use Hess’s Law with enthalpies of combustion?

A

If you are given the enthalpies of combustion for reactants and products, you can apply Hess’s Law by:

Writing combustion reactions for all substances involved.

Combining these reactions to find the enthalpy change for the target reaction.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

How do you use Hess’s Law with enthalpies of formation?

A

Write the balanced chemical equation for the reaction.

Enthalpy change of reaction (∆H) is calculated as:

ΔfHƟ values are the standard enthalpies of formation for each substance.

Standard enthalpy of formation is the enthalpy change when 1 mole of a compound is formed from its elements in their standard states.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

What is the definition of mean bond enthalpy?

A

Mean bond enthalpy is the average enthalpy change required to break one mole of a specific type of bond in the gaseous state, averaged over a range of different molecules.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

How does bond breaking and bond making affect enthalpy change?

A

Breaking bonds = Endothermic (+∆H) (energy absorbed)

Making bonds = Exothermic (-∆H) (energy released)

The overall enthalpy change of a reaction is determined by the difference between the energy required to break bonds and the energy released when new bonds form.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

How do you calculate ∆H using mean bond enthalpies?

A

Use the equation:
Δ𝐻=∑BondEnthalpiesofBondsBroken− ∑BondEnthalpiesofBondsFormed

17
Q

Why do values from mean bond enthalpy calculations differ from those determined using Hess’s Law?

A

Mean bond enthalpies are averages from different molecules, whereas Hess’s Law uses precise enthalpy values for specific compounds.

Mean bond enthalpies apply only to gaseous molecules, but reactions in Hess’s Law may involve liquids or solids, which have additional enthalpy changes.

Bond enthalpies vary slightly depending on the environment, so using an average introduces small inaccuracies.

18
Q

What is activation energy?

A

Activation energy (Ea) is the minimum amount of energy that colliding particles must have for a reaction to occur.

19
Q

Why do most collisions not lead to a reaction?

A

For a reaction to occur, two conditions must be met:

Particles must collide with enough energy (equal to or greater than the activation energy).

Particles must collide with the correct orientation to break and form bonds.

20
Q

What factors influence whether a collision leads to a reaction?

A

Temperature → Higher temperature means particles have more kinetic energy, increasing successful collisions.

Concentration/Pressure → More particles in a given volume means more frequent collisions.

Catalysts → Provide an alternative reaction pathway with a lower activation energy.

Surface Area → More exposed particles in solids lead to more collisions.

21
Q

What does the Maxwell-Boltzmann distribution describe?

A

The Maxwell-Boltzmann distribution describes the distribution of molecular energies in a gas. It shows that:

Most particles have a moderate amount of energy.

Some particles have low energy, and some have high energy.

A small proportion of particles have energy equal to or greater than activation energy (Ea), allowing reactions to occur.

22
Q

What are the key features of a Maxwell-Boltzmann distribution curve?

A

No particles have zero energy (the curve starts at the origin).

Most particles have moderate energy (peak of the curve).

Few particles have very high energy (the curve has a long tail that never touches the x-axis).

The area under the curve represents the total number of molecules.

Particles with energy ≥ activation energy (Ea) are found in the high-energy tail.

23
Q

How does increasing temperature affect the Maxwell-Boltzmann distribution?

A

The peak of the curve shifts to the right (higher energy).

The peak is lower (more molecules have higher energy).

More molecules have energy ≥ activation energy (Ea), leading to a higher reaction rate.

The total area under the curve stays the same (number of molecules remains constant).

Conclusion: At higher temperatures, more molecules have sufficient energy to react, increasing the reaction rate.

24
Q

How does a catalyst affect the Maxwell-Boltzmann distribution?

A

A catalyst lowers the activation energy (Ea) by providing an alternative reaction pathway.

The curve itself does not change, but the position of Ea shifts to the left.

Since more molecules now have energy ≥ the new (lower) Ea, the reaction rate increases.

25
What is the definition of rate of reaction?
The rate of reaction is the change in concentration of reactants or products per unit time. It is measured in mol dm⁻³ s⁻¹.
26
How does temperature affect the rate of reaction?
Higher temperature → Faster reaction Lower temperature → Slower reaction
27
What does increasing temperature do to the rate of reaction?
Particles move faster (more kinetic energy). More frequent collisions per second. More particles have energy ≥ activation energy (Ea), meaning more successful collisions.
28
Why does a small temperature increase cause a large increase in reaction rate?
The Maxwell-Boltzmann distribution shifts to the right at higher temperatures. The peak of the curve lowers, meaning more molecules have higher energy. A small increase in temperature causes a significant rise in the number of molecules with energy ≥ activation energy (Ea). Since only particles with energy ≥ Ea can react, even a small temperature rise leads to a large increase in reaction rate.
29
How does increasing concentration affect the rate of reaction?
Higher concentration = more particles per unit volume. More frequent collisions occur between reactant particles. Increases the number of successful collisions per second, leading to a faster reaction. Direct relationship: As concentration increases, rate of reaction increases.
30
How does increasing pressure affect the rate of reaction in gases?
Higher pressure compresses gas molecules into a smaller volume. More frequent collisions occur between particles. More successful collisions per second, increasing reaction rate. Works the same way as increasing concentration in liquids.
31
Why does increasing concentration or pressure increase reaction rate?
More reactant particles in the same space increases collision frequency. More collisions mean more chances for particles to collide with energy ≥ activation energy (Ea). Faster reaction rate due to an increase in successful collisions.
32
What is a catalyst?
A catalyst is a substance that increases the rate of a reaction by providing an alternative pathway with a lower activation energy (Ea). It is not used up or chemically changed in the reaction.
33
How does a catalyst speed up a reaction?
Provides an alternative reaction pathway with a lower activation energy (Ea). More particles have energy ≥ new, lower Ea, meaning more successful collisions. The rate of reaction increases, but the catalyst itself remains unchanged.
34
How does a catalyst affect the Maxwell-Boltzmann distribution?
The curve itself does not change (particle energies remain the same). The activation energy (Ea) moves to the left, meaning more particles now have energy ≥ Ea. Since more particles meet the required energy, the reaction rate increases.
35