Energetics Flashcards
Definition: Enthalpy Change
Change in heat energy at constant pressure
The symbol for enthalpy change measured under standard conditions is ∆Hθ
Standard conditions:
100kPa Pressure
298K (25°C)
1.0 mol dm-3 concentration for all solutions
Endothermic reactions absorb energy from the surroundings
Temperature of surroundings decreases
Endothermic reactions:
Products are higher in energy than Reactants
∆H is positive +
Exothermic reactions release energy to the surroundings
Temperature of surroundings increases
Exothermic reactions:
Products lower in energy than reactants
∆H is negative -
BENMEX
Breaking bonds is endo, making bonds is exo
Enthalpy change = Total energy to break bonds - total energy released forming bonds
Reactants - Products
Definition: Activation Energy
Minimum needed energy to start a reaction
Definition: Mean bond enthalpy
Energy required to break one mole of a covalent bond into gaseous atoms averaged over a range of different compounds
Mean bond enthalpies are averaged over a range of compounds, because the exact amount of energy required to break a covalent bond depends upon the molecule that bond is in. For example, the energy required to break a C—H bond in methane (CH4) is different to the energy required to break a a C—H bond in methanol (CH3OH)
Mean bond enthalpies are always endothermic processes and, therefore, have a positive sign. This is because energy is required to break bonds. The more positive the bond enthalpy the larger the amount of energy needed to break the bond and so the stronger the bond
Examples of mean bond enthalpies:
CH4(g) → CH3(g) + H(g)
H2(g) → 2H(g)
CO2(g) → CO(g) + O(g)
HCl(g) → H(g) + Cl(g)
The standard enthalpy of formation Δf Hθ is:
· The enthalpy change when one mole of substance is formed
· from its constituent elements under standard conditions
· with all reactants and products being in their standard states.
Examples of standard enthalpy formation:
H2(g) + ½O2(g) → H2O(l)
N2(g) + 2H2(g) + 3/2O2(g) → NH4NO3(s)
Question: Why does the following reaction NOT show the standard enthalpy of formation of ammonia?
N2 + 3H2 → 2NH3
ΔHθ = −92 kJ mol−1
Answer: This reaction produces TWO moles of ammonia
The standard enthalpy of formation of all elements in their standard states is zero
Question: State why the enthalpy of formation of Na(s) is zero
Answer: Na is an element