Elements From the Sea Flashcards

1
Q

How do you calculate atom economy?

A

% atom economy = Mr of desired product/ Mr of reactants x 100

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2
Q

Why is a high atom economy desirable?

A

In industrial chemical processes, little to no waste product is desired to make the process economically viable and to preserve raw materials

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3
Q

Define oxidation and reduction

A

Oxidation - Loss of electrons

Reduction - Gain of electrons

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4
Q

What is disproportionation?

A

When a species simultaneously is oxidized and reduced to give two different products.
E.g: 2H2O2 –> 2H2O + O2

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5
Q

What are some rules for calculating oxidation numbers?

A

Oxidation number of an element is 0, in neutral compounds the sum of oxidation states is 0.
Ox. no. of charged compounds add to total charge.
More electronegative elements have a negative oxidation state, and vice versa

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6
Q
What is the oxidation states of:
Group 1 elements
Group 2 elements
Halogens
Oxygen
Hydrogen
A
Group 1: +1
Group 2: +2
Halogens: -1
Oxygen: -2
Hydrogen: +1
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7
Q

What is the oxidation states of:
Hydrogen in metal hydride (HX)
Oxygen with fluorine
Oxygen in peroxides

A

Hydrogen in metal hydride (HX): -1
Oxygen with fluorine: +2
Oxygen in peroxides: -1

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8
Q

What is an oxidizing agent and a reducing agent?

A

Oxidising agent - Accepts electrons and is reduced, and oxidises another species
Reducing agent - Donates electrons and is oxidized, reducing another species

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9
Q

Define electrolysis

A

The decomposition of a molten or aqueous ionic compound (electrolyte) by passing an electric current through it, the solution must contain a cathode (-ve) and an anode (+ve)

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10
Q

What determines the products at the cathode(s) with inert electrodes?

A

If the metal ions are below hydrogen in the electrochemical series, the metal atoms will be produced at the cathode. If they are above hydrogen, H2 will be produced at the cathode

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11
Q

What forms at the anode(s) in an aqueous electrolyte?

A

Oxygen is generally formed at the anode, unless chloride ions are present, in which case Cl2 will form at the anode
E.g: 2H2O –> 4e- + 4H+ + O2
2Cl- –> Cl2 + 2e-

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12
Q

Explain how an ionic compound is named

A

Named first by cation then anion. Oxidation state of cation is stated in Roman numerals, while the net charge of the compound must be zero.
E.g: Iron (II) Sulfate (FeSO4)

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13
Q

List the color and state of each halogen at room temp and pressure

A

Fluorine - pale yellow gas
Chlorine - pale green gas
Bromine - red/brown liquid
Iodine - dark grey solid, sublimes to a purple vapor

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14
Q

How and why does volatility and boiling point change as you go down group 7?

A

Volatility decreases while boiling point increases due to increase in electrons and molecule size and greater London forces requiring more energy to break

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15
Q

Why are halogens more soluble in hexane than water?

A

Halogens and hexane are both non-polar, so are soluble, while water is polar.

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16
Q

How does thermal stability of hydrogen halides change down the group?

A

Thermal stability decreases down the group as bond strength between hydrogen and halogen decreases, requiring less energy to break the bond

17
Q

How and why do HF, HCl, HBr and HI react with concentrated sulphuric acid?

A

HF and HCl do not react
HBr with H2SO4 produce SO2. (S is reduced from +6 to +4)
HI with H2SO4 produce H2S. (S is reduced from +6 to -2)

Increasing strength of halides as reducing agents down group

18
Q

What is another way of representing H+ ion?

A

The oxonium ion H3O+ (aq)

19
Q

Are hydrogen halides acidic or basic?

What is another way of expressing the dissociation of HCl?

A

Apart from HF, all hydrogen halides are strongly acidic, with nearly 100% dissociation
HCl –> Cl- + H+ or HCl + H2O –> H3O+ + Cl-

20
Q

How do sodium halides react with sulphuric acid?

A

NaF/Cl + H2SO4 –> NaHSO4 + HF/Cl (g)
Bromide ions are strong enough reducing agents so undergo above reaction then reduce sulfuric acid further in: 2H+ + 2Br- + H2SO4 –> SO2 (g) + Br2 (l) + 2H2O (l)
Iodide ions are stronger reducing agents so:
8H+ + 8I- + H2SO4 –> H2S (g) + 4I2 (s) + 4H2O (l)

21
Q

How do hydrogen halides react with ammonia?

A

When a glass rod dipped in conc. ammonia solution is then dipped in hydrogen halide, white cloud of ammonium halide is formed, e.g.
NH3 (g) + HCl (g) –> NH4Cl (s)