Electrophilic Substitution Reactions Of Benzene Flashcards

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1
Q

In benzene, what reactions do they mainly undergo?

A

Electrophilic substitution.

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2
Q

What is an equation for benzene undergoing electrophilic substitution?

A

R: A benzene ring with a curly arrow from the inner ring to the E+.
R: The inner ring loses 1/3 of its structure, the open end facing the electrophile, with a positive charge in the centre and the E and H branching out of benzene with a curly arrow from the H to the positive charge.
P: The benzene inner ring is reformed with the E in the same place branching off of the benzene ring with another product of H+.

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3
Q

What is the overall equation for the general equation for electrophilic substitution?

A

Benzene + E+ = Benzene with electrophile attached + H+.

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4
Q

What are the 3 written steps for the electrophilic substitution of benzene?

A
  1. The positive nature of the electrophile means it is attracted to the electron density of the delocalised pi-ring in benzene.
  2. This intermediate is formed. The electrophile is bonded to the benzene ring, but so still is the H atom. The delocalised pi system is temporarily broken, to leave a partially delocalised electron system and a positive charge.
  3. The intermediate loses a proton, and the electrons from this C-H bond restore the delocalised pi system.
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5
Q

What are 2 features of the delocalised pi system?

A
  • Extemely stable.
  • A region of high electron density.
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6
Q

Why is the electrophilic substitution of benzene tricky?

A

Because electrophiles cannot simply be added into the mixture, there has to be certain reagents and condtions to allow them to be invovled.

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7
Q

What are 2 examples of electrophilic reactions of benzene?

A
  1. Nitration of benzene.
  2. Halogenation of benzene.
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8
Q

What happens in the nitration of benzene?

A

A hydrogen atom is replaced by a nitro (NO2-) group.

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9
Q

What is the overall reaction of the nitration of benzene?

A

Benzene + HNO3 = Benzene with an NO2 group + H2O.

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10
Q

What are the 3 steps in the electrophilic substitution of arenes?

A
  1. Generation of an electrophile.
  2. Electrophilic attack.
  3. Regenerating aromaticy.
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11
Q

What are the steps in the nitration of benzene?

A
  • The electrophile is generated: NO2+ ion is generated by reacting conc. HNO3 and conc. H2SO4.
  • Once the electrophile has been generated, it will carry out an electrophilic attack on the benzene ring: the nitrating mixture of HNO3 and H2SO4 is refluxed with the arene at 25-60C.
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12
Q

What is the equation for the formation of an electrophile in the nitration of benzene?

A

H2SO4 + HNO3 = NO2+ + HSO4- + H2O.
- Where NO2+ is the electrophile.
- Reaction at 50C.
- Acids are both concentrated.

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13
Q

What is the mechanism for the nitration of benzene?

A
  1. A benzene ring with a curly arrow coming off of the inner ring pointing to the NO2+.
  2. This forms a benzene ring with 1/3 of the inner ring removed and a positive charge in the centre. There are two branches crossing over one another to form a whole with H on one and NO2 on the other with a curly arrow coming off of the H branch to the positive charge. THIS HAPPENS BECAUSE NO2+ ACCEPTS A PAIR OF E- FROM THE BENZENE RING TO FORM A DATIVE COVALENT BOND. THE ORGANIC INTERMEDIATE FORMED IS UNSTABLE AND BREAKS DOWN TO FORM NITROBENZENE AND A H+ ION.
  3. This forms a benzene ring with an NO2 group and another product of H+.
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14
Q

What is the equation for the reformation of the catalyst in the nitration of benzene?

A

H2SO4- + H+ = H2SO4 (catalyst).

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15
Q

Why is a water bath used in the nitration of benzene? Or?

A

To maintain a stable temperature. Other wise, if the temperature rises above 50C, further substitution reactions may occur leading to the production of dinitrobenzene.

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16
Q

What else can benzene react with in nitration? To form?

A

An excess nitric acid (2HNO3) above 50C to form 1,3-dinitrobenzene.

17
Q

What needs to be used in order for halogens to react with benzene? Example?

A

Halogen carrier catalysts, e.g. AlBr3.

18
Q

What is the equation for the bromination of benzene?

A

Benzene + Br2 = Bromobenzene + Hbr.
- (with AlBr3 or FeBr3 used to help).

19
Q

What are the steps of bromination of benzene?

A
  1. Benzene is too stable to react with a non-polar bromine molecule. The electrophile is the bromonium ion, which is generated when the halogen carrier catalyst reacts with bromine in the first stage of the mechanism.
  2. The bromonium ion accepts a pair of electrons from the benzene ring to form a dative covalent bond. The intermediate is unstable and breaks down to form bromobenzene, and an H+ ion.
  3. The H+ ion formed in step 2 reacts with the AlBr4-/FeBr4- ion from step 1 to regenerate the AlBr3/FeBr3 catalyst.
20
Q

What are the 3 written steps of bromination of benzene?

A
  1. Br2 + AlBr3 = AlBr4- + Br+.
  2. Benzene ring with curly arrow from inner ring to Br+. FORMS an intermediate with 2/3 of inner circle with positive charge inside and bonds of H and Br going out and crossing over with a curly arrow from the H branch to the positive charge. FORMS a bromobenzene ring and a H+.
  3. H+ + AlBr4- = AlBr3 + HBr.
21
Q

What are 2 other reactions of substitution?

A

Alkylation and acylation reactions.

22
Q

What is the alkylation of benzene? (Friedel-Crafts alkylation)?

A

The substitution of a hydrogen atom in the benzene ring by an alkyl group.

23
Q

How is an alkylation of benzene reaction carried out?

A

You react benzene with a haloalkane in the presence of AlCl3, which acts as a halogen carrier catalyst, generating the electrophile.

24
Q

What does alkylation form?

A

It increases the number of carbon atoms in a compound by forming C-C bonds.

25
Q

What is the mechanism equation for alkylation?

A

Benzene + C2H5Cl = Ethylbenzene + HCl
- with AlCl3 as a halogen carrier catalyst.

26
Q

What happens in acylation reactions?

A

When a benzene and an acyl chloride are reacted together in the presence of an AlCl3 catalyst, an aromatic ketone is formed. C-C bonds are also formed.

27
Q

What is the mechanism reaction for acetylation?

A

Benzene + Ethanoyl chloride = Phenylethanone + HCl
- with AlCl3 as a halogen carrier catalyst.

28
Q

How can we compare the reactivity between alkenes with arenes?

A

Using the reaction between cyclohexene and bromine (alkenes decolourise bromine by an electrophilic substitution reactions). In ELECTROPHILIC ADDITION.

29
Q

What is the reaction between cyclohexene and bromine?

A

Cyclohexene + Br2 = 1,2-dibromocyclohexane.

30
Q

How does the reaction between cyclohexene and bromine work? Bromine adding across the double bond in cyclohexene? (3)?

A
  1. The pi-bond in the alkene contains localised electrons above and below the plane of the two carbon atoms in the double bond. This produces an area of high electron density.
  2. The localised electrons in the pi-bond induce a dipole in the non-polar bromine molecule making one bromine atom on the Br2 molecule slightly positive and the other bromine atom slightly negative.
  3. The slightly positive bromine atom enables the bromine molecule to act like an electrophile.
31
Q

What is the structural mechanism between cyclohexene and bromine?

A
  1. A curly arrow comes off of the cyclohexene double bond and pointing to the slightly positive Br on the dipole with the slightly negative Br with another curly arrow coming off of the middle bond in between the Br’s to the slightly negative Br.
  2. THIS FORMS an intermediate carbocation of cyclohexane where Br is branched off of the molecule and there is a positive charge on one of the carbons with a curly arrow pointing to it from the Br- lone pairs (must have all electrons around the Br.
  3. THIS FORMS 1,2-dibromocyclohexane.
32
Q

Why does benzene need halogen carrier catalysts to react with bromine but alkenes do not?

A
  • Because benzene has delocalised pi-electrons spread above and below the plane of the carbon atoms in the ring structure. The electron density around any two carbon atoms in the benzene ring is less than that in a C=C double bond in an alkene.
  • When a non-polar molecule such as bromine approaches the benzene ring there is insufficient pi-electron density around any two carbon atoms to polarise the bromine molecule. This prevents the reaction from taking place.