Electrolysis Flashcards

1
Q

suggest ONE way to remove ions of metal which are LESS REACTIVE than zinc from the zinc sulphate solution before electrolysis

A

Add Zn(s)/ Mg(s)/ Al(s) to DISPLACE ions of less reactive metals

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2
Q

Why it is NOT necessary to remove ions of metals which are MORE REACTIVE than Zn from the solution

A
  1. Zn2+ ions will be preferentially discharged
  2. ions of more reactive metals will remain in the solution
    ( Zn > ↑reactive metal in E.C.S/ Zn is a stronger oxidizing agent)
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3
Q

Y car bumpus coated with a layer of nickel prior to the chromium-planting process

A
  1. As an undercoat
  2. to protect the steel from corrosion
    after the chromium layer has been scratched off
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4
Q

Y H2SO4(aq) is used in the chromium-plating bath

A
  1. To increase electrical conductivity/

2. To provide mobile ions

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4
Q

Y H2SO4(aq) is used in the chromium-plating bath

A
  1. To increase electrical conductivity/

2. To provide mobile ions

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5
Q

Why the volume of chlorine collected is significantly smaller than theoretical volume

A
  1. Chlorine dissolves in water

Cl2(aq) + H2O(I)→ HOCl(aq) + HCl(aq)

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6
Q

Why the volume of chlorine collected is significantly smaller than theoretical volume

A
  1. Chlorine dissolves in water

Cl2(aq) + H2O(I)→ HOCl(aq) + HCl(aq)

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7
Q

Advantages of carrying out experiments in MICROSCALE

A
  1. Reduce chemical waste produced
  2. Shorten the time required for conducting an experiment
  3. Require less working space for carry out an experiment
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8
Q

state what will happen to the bulb
when heating is stopped
and
the molten lead(ll) bromide is allowed to cool down gradually room temperature

A

The light bulb gradually goes out.
1. T°C↓,
→movement of ions slow down
→a smaller current flows through the external circuit
2. When PbBr2 becomes solid,
→Ions are no longer mobile
→no currents flow through the external circuit

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9
Q

Is it possible to deuce the formula of water from the results of the electrolysis
(Cathode: 2H+(aq) +2e- → H2(g))
(Anode: 4OH-(aq)→ O2(g) + 2H2O(l)+ 4e-)

A


1. volume of H2(g) collected : volume of O2(g) collected
= 2:1
2. In water, H & O combine in mole ratio of 2:1
3. The ATOMICITY of H & O both =2
→ the formula of water = H2O

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10
Q

Why is it necessary to coat the handles with copper before they are nickel-plated

A

To make the knobs a conductor of electricity for the nickel-plating process

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11
Q

Nickel Electroplating
Why is it necessary to maintain the pH of the electrolytic bath within a small range
(Add Boric acid to maintain pH: 4~6)

A
  1. At low pH,
    →H+(aq) instead of Ni2+(aq) will be discharged at the cathode.
    →the current efficiency will decrease
  2. At high pH,
    →Ni2+(aq) will be precipitated as Ni(OH)2(s)
    ***It is necessary.
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12
Q

How boric acid functions in the nikel-plating bath

A

H3BO3(aq) is a weak acid.
→the dissociation of H3BO3(aq) can
1. replenish the ions lost by discharge at the cathode
2. maintains the pH of the electrolytic bath

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13
Q

How impure copper can be purified by electrolysis

A
  1. The impure Cu(s) anode becomes Cu2+(aq)

2. Cu2+(aq) in solution discharge on the pure Cu(s) cathode

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14
Q

Why is the concentration of Cu in CuSO4(aq) solution decreases during purification of Cu?

A
  1. At anode,
    → Fe(s) & Zn(s) dissolves as ions(Fe2+(aq) & Zn(aq))
    → they lose e- more readily than Cu
    ∴Cu2+(aq) ions decreases gradually
  2. At cathode, Cu2+(aq) ions are always preferentially discharged
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15
Q

State TWO advantages of
building a factory in which
CONTACT PROCESS is carried out near the chemical plant (electrolysis: purification of Cu)

A
  1. SO2(g) available as resources for Contact process
  2. Prevent air pollution induced by SO2(g)
  3. The cost of transportation of SO2(g) is minimized
16
Q

It is known that only cations can pass through the membrane (~porous device).
Y NaOH solution of higher concentration is eventually obtained
(at anode: ↑[NaCl(aq)])
(at cathode: ↓[NaCl(aq)])
(Higher lower)

A
  1. Unreacted Na+(aq) ions the anode side
    → can pass through the membrane to the cathode side
  2. ∵H+(aq) ions are discharged at the cathode,
    → OH-(aq) remain/ are excess

→→higher concentration of NaOH is obtained

17
Q

Why it is NOT recommended to use

a high current density in electroplating of Cu by electrolysis

A
  1. H2(g) gas bubbles HINDER THE DEPOSITION of Cu(s) in the surface of the metallic object
  2. → a loose spongy Cu deposit can be easily flaked off