Electrode potentials Flashcards

1
Q

Standard hydrogen electrode
diagram and conditions

A

100KPa
298K

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2
Q

What metal do you use in half cells when no metal solid is in the equation and why?

A

Platinum

because it is inert
conducts electricity

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3
Q

Features of a cell (4)

A

Voltmeter- Measures potential pushing power of electrons though the circuit but keeps the current at 0
Wire- Allows the movement of electrons
Electrodes- Where the half equations take place (half-cells)
Salt bridge- Filter paper soaked in KNO3, this completes the circuit and allows for the movement of ions to compensate concentration change in the half-cells
KNO3 is suitable because it doesn’t react with ions in solution

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4
Q

How to measure potential of an electrode

A

can’t measure a half-cell on its own

connect to a cell of known potential and find the difference
here you can tell if it is positive or negative

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5
Q

risks of using cells

A

Cells- waste

H fuel- needs constantly to be fuelled
Hydrogen is flammable and explosive
hydrogen usually from fossil fuels
high cost of fuel cells

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6
Q

benefits of using cells

A

portable source of electrical energy
non rechargeable is cheap
rechargeable less waste, cheaper in the long run and has a lower environmental impact

h fuel cells- only waste is water, no recharging and is very efficient

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7
Q

rechargeable batteries

A

current can be forced back in the opposite direction
dont decompose

half equations are reversed

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8
Q
A
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9
Q
A

porous separator allows the movement of ions

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10
Q

how to remember what happens when concentration changes to electrode potential value

A

forward shift (Right shift)
going forward is positive
electrode potential increases

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11
Q

Cu2+,+2e-,<->Cu+ E=o.15

what happens if the concentration of Cu2+ is raised

A

equilibrium opposes the increase in concentration so shifts right the decrease the concentration of Cu2+

equilibrium shows greater potential to gain electrons so less free electrons

electrode potential is more positive

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12
Q

electrode cell calculations

A

electrode=E,reduction-E,oxidation

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