Electrode Potentials Flashcards
Voltaic cell def
Type of electrochemical cell which converts chemical energy to electrical energy
What are electode potentials used for
Electrode potentials compare the ease of which a metal gives up its electrons to form positive hydrated ions
Electrode potentials of Mg and Cu.
Explain what happens
Give half equations
Mg loses 2e- to become Mg2+
Mg2+ attracted to negative strip
Picks up e- again to become Mg(s)
More reactive so equilibrium lies to LHS
Mg2+ + 2e- = Mg(s)
Cu less reactive than Mg Less readily forms ions So Cu2+ more likely to pick up e- Equilibrium lies to RHS Cu2+ + 2e- = Cu(s)
Half cell def
Contains the chemical species present in a redox half equation
Metal/metal ion half cell def
Consists of a metal rod dipped in a solution of aqueous ions
What is the convention for writing half cell equations
Reduction reaction is the forward reaction
Electrons and cations are written on the left hand side
What type of reactions are half cell reaction
Reversible
So they form a DYNAMIC EQUILIBRIUM
Ion/ion half cell def
Contains ions of the same element in different oxidation states
Why is platinum used as an electrode?
It is inert (unreactive)
Means there is no transfer of electrons between the electrode, and the two metals added to solution
Electron transfer therefore only occurs between two added metals
Standard electrode potential def
E (standard state symbol)
The electron motive force of a half cell compared with a standard hydrogen half cell, under standard conditions:
Measured at 298K
With solution conc. of 1moldm-3
With a gas pressure of 100kPa
Electron motive force def
The tendency for a substance to lose or gain electrons
How to measure the electrode potential of a substance
Connect the half cell to a hydrogen half cell
Electrode potential values are relative to electrode potential of a hydrogen half cell
E^o of hydrogen half cell = 0 Volts
What is a salt bridge used for?
Give example of a salt bridge
Allows ions to flow
But contains a solution that doesnt react with the half cell solutions
E.g. filter paper soaked in KNO3
Positive and negative electrodes in a cell
In an operating cell, the electrode with the more reactive element/metal loses electrons and is (more) negative
More likely to be oxidised
The less reactive element/metal gains electrons, so is (less) negative
So the element is more likely to be reduced
Equtaion to calculate cell potentials
E^o(cell) = E^o(+ve electrode) - E^o(-ve electrode)