ELECTRICITY AND MAGNETISM Flashcards
e=elementart charge= charge of a single atomic particle= 1.6x10^-19
e= 1.6x10^-19 COLOUMBS e-= -1.6x10^-19 COLOUMBS p+= +1.6x10^-19 COLOUMBS
1 coulomb = ?
6.24x10^18 atomic particle
# of electron = # of protons = called? # of electron ≠ # of protons = called? more protons = called? more electron = called?
neutral atom
charged atom/ ION
cation
anion
when 1 coloumbs charge or 6.24x10^18 electrons passes through an imaginary cross section drifting in the same velocity, the flow of charge or current is said to be?
1 AMPERE
1 ELECTRON PASSING THROUGH A CONDUCTOR HAS A CHARGE OF?
1.6X10^-19
CURRENT FORMULA? IN TERMS OF CHARGE.
I= Q/A= COULOMBS / SECOND
identify the current equivalent of the ff.
considered dangerous, can cause temporal paralysis ______
severe shock _______
fatal_______
> 10mA
> 50mA
> 100mA
what are the two types of electricity
static and dynamic electricity
difference of STATIC AND DYNAMIC ELECTROCITY
STATIC IS: STATIONARY TRANSFER OF ELECTRICITY IS ONE AT A TIME TRAVELS IS AIR OCCURS ON OPEN CIRCUIT ALSO CALLED, ELECTRIC FLUX
DYNAMIC: MOVING TRANSFER IS CONTINUOUS. "CYCLE" TRAVELS THROUGH CONDUCTORS OCCURS IN CLOSED CIRCUIT ALSO CALLED CURRENT
FORULA OF COULOMBS LAW THAT IS SIMILAR TO THE GRAVITATIONAL LAW OF NEWTON
Fs=k(q1q2)/r^2 = electrostatic law = electrostatic force
q= charges
k=proportionality constant) = 9X10^9 Nm^2/C^2 (newton, meter, coulomb)
ε0= 8.854x10^-12 F/m (Farahd per meter)
ε0= vaccum permittivity
states that: The net outward normal electric flux through any closed surface is proportional to the total electric charge enclosed within that closed surface divided by the permittivity.
gauss law, gauss’ flux theorem
Φelectric or = Ψ = Q/ε0 = electric flux
electrostatic force VS electric field strength/intensity
electric field strength/intensity is the electrostatic force felt by a test charge from a source charge at a certain distance.
{Q= source charge | q= point charge}
electric field strength/intensity
electric field strength = E = ξ = (Fs/q)
can also be derived to;
ξ= kQ/r^2
ξ= N/C or V/m (voltage over meter/ newton over coulomb)
units of the following k=? Q or q = ? ξ = ? voltage = V = (by joules) =? I = current by time= ?
k=Nm^2/C^2 Q = coulomb r = meter ξ = N/C or V/m V= J/C I= Q/t
prove that ξ is N/C or V/m
ξ = kQ/r^2 = [(Nm^2/C^2)(C)/ (m^2)] = Nm/Cm = J/Cm
[since J = Nm = ((Kgxm)/s^2) X m = Kgm^2/s^2 ]
and since, V= J/C then,
J/Cm = V/m
V/m = N/C