Electrical Flashcards
What are copper losses
How to show them
Power loss due to reisstance in windings + leakage of inductance in windings
Series resistor Inductor (draw diagram)
What are iron losses
Losses due to hysterics , eddy currents, and loss in flux
Parallels inductor and resistor
How to measure copper loss
How to measure iron loss
Shirt circuit test, impedance federal and the. Use the rated current and powers (disregard the iron loss )
Open circuit test , (disregards copper loss) and use rated voltage along with power
Why cmos better than nmos 2 points
Only consumes power when switching stats
But only transistors, no need to use any resistors so much smaller
thevinin theroem
as far as load is concerened, a linear circuit may be represented by an ideal voltage source Vth in series with a resistor Rth,
where VTh is Voc and RTH is Voc/ Isc
norton theroem
as far as load is concerned, a linear circuit can be replaced by an ideal current source IN in parallel with a resistor RN
where IN is given by Isc and RN Voc/ Isc
no load = not possible + can do thev / norton to the entire circuit at once
ideal opamp assumptions (3)
- infinite open loop gain A
- infinite input impedance
- 0 output impedance
why is it assumed for metallic conductors that there any net charge is distributed on the surface only
by gauss law, if there were any charge inside the conductor there would be an electric field, which would casue such charges to surface of the conductor , such that the internal net electric field would become zero
self inductance defined
fluz linked of cicuit / current
method for capacitance
1) make inner circle a +q, and +v, outer -q and ground, then its really easy
purpose of source follower
high input impedance low output impedance and drives high current, so expect r2 to be much smaller
assumptions for flux conservation
no fringing effects , distance too small
virtual work derivation
in order to maintain electrostatic equilibroum a force is acted on the two charged objects
moving a charged object
- attractive force F is balanced by restoring force -F which we want to find.
- this does mech work -Fdx
- requires work from battery v dq ( use voltage equation is w/q)
- and results in a change of electrostatic energy 0.5 VQ (area under qv grah)
- equate and differntiate
why does virtual work show that only the force depends on mutual inductance
this becasue the self inductance terms are definitely constant, so it must depend on the Mi1i2 term only
the only change in energy as vf is dw/dx is due to M which changes with x
max power output transfer thereom for amplifiers
is v out sqaured/ rL, or better I sqaured RLdifferentiate wrt to Rl set to 0, happens when RL= R total output impedance