Electric Fields U4 Flashcards
Why are field lines pointing away from a positively charged particle
Because these lines show the direction a test positive charge would move
Define an electric field
Force acting per init charge
Uniform field : E=
V/d
F/Q
If you double the distance between two plates in a uniform field what happens to the V? Why?
The v=1/2 because of E=V/d ,
They’re inversely proportional
What happens to E when you increase the potential difference between two plates in a uniform field
E increases
What direction do you draw any electric field lines
Away from a positive charge
Towards a negative charge
Why does the E field for a radial field get weaker as you get further away from the charged particle?
Because the field lines are further apart as you move further away from the charged particle therefore the E field is weaker
What is the surface area of a sphere
4(pi)r^2
If you double the radius of a sphere what happens to the surface area? What is this called?
4X larger
Inverse square law
What is E proportional to for a radial field?
1/r^2
Q/r^2
If E is proportional to Q/r^2 then what does E equal?
E=k(Q/r^2)
Where k is a given constant
When does Coulomb’s law apply?
When there are two charged particles in an electric field
If the force Squire’s from Coulomb’s law is negative what does this mean?
It’s an attractive force because the charges are opposite
E=? (Coulomb’s law) and therefore derive F
F=EQ2
KQ1/r^2=F/Q2
KQ1Q2/r^2=F
The Coulomb’s law equation is
F = k Q1Q2/r^2