Egypt and Mesopotamia Flashcards

1
Q

the gift of the Nile

A

Egypt

Fertile banks of Nile and sea and dessert protect Civillisation

Without the Nile Agriculture and Civilisation couldn’t thrive
flooding allowed for this to happen

Upper and Lower egypt 3100 BC until conquest by Alexander the Great

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2
Q

pyramids

A

The Great Pyramids were built around 2500 BC the height of the Egyptian culture

people were aware of the culture but not sure on meaning of hieroglyphics

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3
Q

Hieroglyphs

A

Egyptian script, originally used all-purpose then only in religious contexts and monumental stone carving

The art of reading ancient E scripts was lost:
the key to these was the discovery in 1799 of the Rosetta Stone

read from left to right or right to left depending on the facing of the symbols

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4
Q

Hieratic

A

script developed after hieroglyphs more fluid and better suited for writing with pen on papyrus

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5
Q

Herodotus

A

about 450 BCE Herodotus, the inveterate Greek traveler and narrative
historian, visited Egypt

“father of history”

recorded the customs of many peoples

observed the majesty of the Nile and the achievements of those working along its banks.

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6
Q

ROSETTA STONE

A

Found near Rosetta. Rosetta Stone, a trilingual basalt slab with inscriptions in hieroglyphic, demotic, and Greek writings that had been found by members of Napoleon’s Egyptian expedition in 1799

  • Rosetta on the Nile delta
  • most viewed exhibit in the british museum
  • contains decree of 196 BC three times in hiero,dem and greek
  • unable to read hieroglyphs at the top but many read greek and tells it has the same info in three languages

*By 1822, Champollion was able to announce a substantive
portion of his translations
Earning title Father of Egyptology

by using cartouches?

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7
Q

hieroglyphs

A

French scholar Jean-Franc¸ois Champollion, working with multilingual tablets, was able to slowly translate a number of hieroglyphs

phonetical and alphabetical

*because of variability of hieratic and demotic scripts Egyptologists transcribe all texts into more standardized hieroglyphic they dep on the scribe

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8
Q

papyri and sources

A
  • rhind papyrus
  • moscow papyrus
  • MLR(hieratic?)
  • the royal mace (hieroglyph)
  • Rosetta stone (demotic)
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9
Q

rhind papyrus

on exam
RMP

A

1858, the Scottish antiquary Henry Rhind purchased a papyrus roll in Luxor that is about one foot high and some eighteen feet long. Except for a few fragments in the Brooklyn Museum, this papyrus is now in the British Museum. It is known as the Rhind or the Ahmes Papyrus, in honor of the scribe by whose hand it had been copied in about 1650 BCE. The scribe tells us that the material is derived from a prototype from the Middle Kingdom of about 2000 to 1800 BCE. Written in the hieratic script,
it became the major source of our knowledge of ancient Egyptian mathematics

  • 84 hieratic problems
  • 18ft x 1 ftm 84 Hieratic problems
  • Rhind mathematical papyrus 1675 BC?
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10
Q

Moscow papyrus

MMP

A

Moscow Papyrus, was purchased in 1893 and is now in the Pushkin Museum of Fine Arts in Moscow. It, too, is about eighteen feet long but is only one-fourth as wide as the Ahmes Papyrus (3 inch) . It was written less carefully than the work of Ahmes was, by an unknown scribe of circa. 1890 BCE. It contains twenty-five examples, mostly from practical life and not differing greatly from those of Ahmes, except for two that will be discussed further
on

18ft x 3 inch 25 problems in hieratic

practical problems

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11
Q

mathematical leather roll

A

a leather roll containing a list of fractions.

The only leather roll

10 in x 17 in 26 HIERATIC fractions

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12
Q

Royal mace

A

A museum at Oxford has a royal mace more than 5,000 years old, on which a record of 120,000 prisoners and 1,422,000 captive goats appears.
These figures may have been exaggerated, but from other considerations it is clear that the Egyptians were commendably accurate in counting and measuring.

Primary source and largest number mention in ancient Egypt

HIEROGLYPHIC NUMERALS

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13
Q

demotic

A

script 7th century BC cursive script, mad doctors handwriting at the end of a bad day

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14
Q

ON EXAM

A

Q1 part a) Egyptian mathematics, Rhind papyrus (not leather roll)
nothing on pyramids and seqts nor on the 3 classical problems

need dates:
Rhind 1675
Egyptian? 1546
beg egypt 3500BC
know order they came in aswell as dates
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15
Q

three ancient Egyptian scripts are in chronological order

A

hieroglyphic 3500BC pictorial carved on monuments

hieratic 2500BC
flowing ink on papyrus, religious

demotic 1850 BC
cursive, everyday

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16
Q

scripts in egypt occur on:

A

hieroglyphic - Narmer Royal Mace
hieratic- MLeatherR
demotic-
Rosetta stone

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17
Q

Hieroglyph notation fractions

A

ALL fractions, except 2/3 are reduced to sums of unit fractions ie numerator 1.

They are indicated by placing an elongated oval over its denominator , except 1/2 and 2/3

eg
1/3 = “eye shape”over”111”

1/12= “eye shape” over “11n”

if we write over-lined n as 1/n

we write 2/3 by oval above one and a half vertical strokes, overlineoverline3

The RMP opens with a table expressing fractions of the form 2/n as sums of unit fractions for odd values of n from 5 to 101

eg 2/25 = overline15 overline75

adding= written in juxtaposition

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18
Q

Egyptian multiplication 13 x 11

need to know

A

they multiplied by doubling and then addition

\1 11
2 22
\4 44
\8 88

add the lines marked with a backslash to deduce that these are the ones you add:
(1+4+8)11= (13)11 = 11+44+88=143
division is performed by reversing the multiplication process.

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19
Q

Chronology

A

(Egypt was split)
3100 BC
Upper and Lower Egypt united into one country- Egypt

2500 BC Great Pyramids
1850 BC Moscow Papyrus
1650 BC Rhind Papyrus

332 BC Alexander’s conquest invaded Egypt

1799 AD Rosetta Stone
1822 AD translated by Champoliion
1858 RHIND papyrus purchased
1865 AD comes to british museum
1877 AD maths translated by Eisenlohr
(he numbered the problems on the papyrus, still used now)
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20
Q

hieroglyphic numerals

A

1 is |
10 “n”/yoke

100 swirl/coil

1000 looks like moon / lotus flower/balloon with weight

10,000 boomerang/finger

100,000 face? animal tadpole

1,000,000 man with arms up/kneeling

ie number system based on powers of ten

Decimals. Repetitions of symbols for powers of ten

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21
Q

RMP ALGEBRA

A

There is no algebraic notation but in RMP problem 28 2 legs walking left to right indicate addition
right to left are subtraction

in MMP problem 14 two legs walking left to right indicate squaring

problems 24-27 aha or heap problems are single linear eq in one unknown could be classed as algebraic

They are solved by method of false position, in which an initial guess is made and then adjusted to yield the answer . This is then checked by substitution back into original eq.

aha or heap is the unknown, stated verbally

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22
Q

RMP 25

A

the heap and it’s half is 16, what is the heap
x+0.5x=16

a) guess x=2. Setting in LHS the eq yields 3, not 16.
b) dividing 16 by 3 gives 5 and 1/3. This is what 2 must be multiplied by to give the answer
c) multiply the initial guess of 2 by 5 and 1/3 to obtain answer 10 and 2/3

d) final check 10 and 2/3 + 0.5(10 and 2/3) = 16

Note initial guess 2 was likely chosen because its half is an integer ,1.

Assume 2 \1 2
\0.5 1
sum 3

as many times as 3 must be multiplied to give 16, so many times 2 must be multiplied
       \1  3
        2   6
       \4   12
      2/3   2
       \1/3  1
sum  5  1/3
     1  5 1/3
   \2  10 2/3

Do it so: heap is 10 2/3
0.5 is 5 1/3
sum is 16

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23
Q

PRIMARY SOURCES

ancient egypt

A

3100 BC Royal Mace, ashmolean Museum , Oxford. High valued, hieroglyphic numerals

NOT***

1850 BC Moscow papyrus, Moscow museum of fine arts. 25 hieratic problems

1650 BC RHIND papyrus British Museum 10057/8 in two parts, 84 hieratic problems
***

1650 BC MLR British museum 26 sums of hieratic unit fractions twice

1799 Rosetta Stone- hieroglyph demotic greek (primary source)

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24
Q

Area of a circle RMP problems

REVISE WELL

A

RMP problems 48 and 50 both take the area of a circle

(also 41,42,43 concern finding the volumes of cylindrical granaries diameters 9,10,9 and 10,10,6 areas of bases times Heights. Area of circular base of diameter d is always
(d-(d/9))^2 = ((8/9)d)^2)

both problems take the area of a circle of diameter 9 to be that of a square of side 8, ie 64

the equation pi(9/2)^2=64 shows both give an implicit value of Pi of 256/81 . The units of measurement using the problems show their concern circular areas of land.

(effectively found by taking 8/9 of diameter and square it- they squared by doubling )

*the Egyptian circle area that is not an integer is that of the circle of diameter 10-in problem 42 which by the Egyptian method is 6400/81 = 79 1/81

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25
Q

IMPORTANT

A

7 marks question on Egypt

need to be able to write a paragraph on the rhind papyrus:
Henry Rhind felt ill, doctor told him to take holidays further and further away. Winter in egypt.

Henry Rhind bought the Papyrus at Luxor in 1858.

Rhind papyrus is in two parts and listed as two numbers in the british museum, found half . Fragments from the break are found by the NY Hisorical society in 1922, now in Brooklyn Museum.

This is a training manual for scribes, copies by Ahmes in 1650 BC comprises

84 worked problems and promises insight into all that exists.

Translated by Eisenlohr, Peet and CHace

Robins and Shute’s Rhinf Mathematical Papyrus has 24 coloured plates of the Papyrus.

red ink for problem and black ink for answer

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26
Q

problems on the RMP

A
  • 24 to 27 aha problems false position, algebra
  • 48,50 area of a circle (implicit pi)
  • 41,42,43 vlumes of cylindrical granaries
  • 56-60 seqts, slopes, pyramids (trigonometry)
    *79 geometric progression (recreation)
    NO PROBLEM ON THE RMP or MMP concerns finding the circumference of a circle
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27
Q

RMP problem 50

A

round field diameter 9. Find its area

subtract 1/9 of diameter, 1. Remainder is 8 X 8 to make 64. This is the area.

Do it thus:      1    9
                      1/9   1
is taken away leaves 8.
1   8
2   16
4   32
\8   64

Area is 64

  • passing from the diameter 9 of the circle to the side 8 of the square is affected by subtracting 1/9 of 9 from itself to leave 8. The Egyptians had no concept of the fractions such as 8/9, operating only with unit fractions, like 1/9 here. The diagram shows a circle enclosing a number 9
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28
Q

SEQTS

not on exam?

A

a cubit is 7 hands
pyramid builders measured vertical distances in cubits and horizontal distances in hands, slopes are measured in seqts.

(the seqt s of a face of a pyramid P is half its base in hands / height in cubits)
the sect of a pyramid is the ratio of the horizontal displacement of a face (half base) enhance to its vertical displacement (height) in qubits, and is an inverse measure of steepness with gentler slopes having higher seqts.

Seqt of a pyramid with height h cubits and base b cubits is 7(0.5b)/h hands per cubit

The angle of slope theta of P is the angle between one of its faces P and its horizontal base, tan theta=2h/b = 7/s and s =7cot theta.

RMP problems 56/59 concerning the seqts of pyramids, lie one below each other at the end of the recto of BM10057. Each is accompanied by a sketch of the pyramid, the numerical values of its base and height written alongside.

RMP problem 57 the seqt of a pyramid is 5 hands and one finger per cubit, the side of its space is 140 cubits. What is it height? A finger is a quarter of a hand.

Solution in modern Let pyramid have height hqbutts. Then the sect is 7(140/2)/h = 21/4 whence h=(7x140x4)/(2 x 21)=93 1/3

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29
Q

RMP 48

most important of the problems

A

48:ONLY PROBLEM WITH NO RED INK, NO STATEMENT OF PROBLEM

compare the area of a circle and that of its circumscribing Square

circle diameter 9 
1   8
2    16
4   32
\8  64

Square side 9

\1   9
2    18
4   36
\8   72
sum 81

Area circle ~octagon = 63~64
taking the area of the circle to be 64

  • only RMP problem with no statement - no red ink

Diagram is square circumscribing irregular polygon , octagon? with a nine drawn inside. Beneath, 2 multiplications are set out : 9x9 =81 and 8x8=64 by doubling and edition with check marks

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30
Q

Geometric series

A

RMP problem 79:concerns the geometric series. It is unclear what the problem is (as there is no red ink??? only 48??) describe sets out in a column: 7 houses, 49 cats, 343 mice, 2401 ears of Grain, 16807 hekats of grain, total 19607. another column shows 19607 was found as 7(1+7+49+343+2401), so the Egyptians knew something of geometric progressions. the problem may just be a diversion, perhaps a precursor of the nursery rhyme: as I was going to St Ives, I met a man with seven wives; each wife had seven sacks, each sack had seven cats, each cat had 7 kits; kits, cats, sacks and wives, how many we’re going to St Ives?

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31
Q

MMP problem 14

MOSCOW

A

coined the greatest Egyptian pyramid by ET Bell. This problem calculates the exact volume V = 56 of the frustum of a square pyramid of height h = 6, side of an upper face a = 2, and side of lower face b = 4, using the equivalent of the correct formula:

V= (h/3)(a^2+ab+b^2)

a diagram is given along with the full details of all the sub calculations performed, written both in and around it. On two occasions, a pair of legs walking from left to right indicates operation of squaring.

*the frustum can be seen to have been cut from a pyramid of height 12 and base 4. This had seqt (7x2)/12 = 7/6 hands per cubit.

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32
Q

RMP problems 56-59

A

concern pyramids as shown by triangles illustrating them. Pyramid builders used seqts to maintain constant slopes in their constructions.

let pyramid have height h cubits and angle of slope theta. Then seqt = 5 1/4 = (7x70)/h and h= (280/3) = 93 1/3 cubits. Now tan theta= height/ 0.5base = (280/3)/70 = 4/3 and theta = tan -1 (4/3) = 53 to the nearest degree

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33
Q

notes on what questions may come up

A

problem 15 of the rhind papyrus, implicit values of Pi, finding the area of a circle

diagram of problem 48 on the Rhind papyrus finding areas of the circle: only one that does not have the red ink, all it has is a diagram of the square circumscribing an irregular polygon which is possibly an octagon with a number 9 script inside of it. underneath are the multiplications of 9 x 9 and 8 by 8. Approximates area.
fraction notation in egyptian

  • *7 marks is on Egyptian mathematics
  • *16 marks on Mesopotamia?
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34
Q

MESOPOTAMIA and BABYLONIA

A

The land between the rivers

3000 BC Sumerian civilization flourished the fertile crescent between the Tigris and Euphrates rivers, now in Iraq. Babylonian refers to any people occupying the region up to 539 BC, then Babylon fell to Persia. Babylonian maths continued through persia and greek rule up to Christianity.

3000 BC SUmerians
2500BC cuneiform script sexagesimal, place-value number system
1800-1600BC old babylonian
539 BC Persia defeats Babylon
330 BC Alxander the Greats conquest
312 BC+ Seleucid period:0 symbol
1849 AD Rawlinson deciphers cuneiform
1935 AD+ Neugebauers pioneering work

*history of Mesopotamia is a story of Invaders who attracted by the richness of the Land conquered their predecessors only to be overcome by new Intruders

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35
Q

cuneiform

A

the Babylonians inscribe their numbers in clay using a triangular stylus, producing a wedge-shaped script known as cuneiform.

Babylonic cuneiform (wedge-shaped) script made by
impressing triangular stylus into moist clay, then baking.

inscribed with the clay is still moist and baked hard in an oven or by The Heat Of The Sun

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36
Q

babylonian references

A

our knowledge of that mathematics rests on 400 also clay tablets either TABLE TEXTS OR PROBLEM TEXTS from the old Babylonian period (1800 -1600) BC

*published in 20th-century by assyriologists such as:
Thureau-Dangin, Sachs, Neugebauer (last century and a half)

*Exhibits of Babylonian Cuneiform Tablets
National Museums: Berlin, London, Paris
US Universities: Columbia, Pennsylvania, Yale

inscribed on bottom, sides etc

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37
Q

place value and number system in babylonian

A

what number means related to where placed

unit symbols were placed immediately to the right of those for the 10s
number system base 60

*the greatest mathematical achievement was a sexagesima place value number system

38
Q

sexagesimal number system

A

*used by babylonians employed two symbols: a thin vertical wedge | for one and a broad horizontal wedge < for ten.

Numbers up to 59 were written as the approximate number of 10 symbols, followed closely by that of unit symbols. It’s extended to sexagesimal fractions, but lacked a 0 and their sexagesima point.

*it was SEXAGESIMAL which means it was to the base 60 and employed POSITIONAL NOTATION

39
Q

Babylonians : 0

A

early Babylonians had no 0 symbol, and did not formally separate sets of decimal places or indicate the sexagesimal decimal point. Today we use:

0, zero
, decimal place=
; sexigesimal point

when transcribing into Modern sexy decimal notation.

since the Babylonians had no sexagesimal point, they operated a floating sexagesimal point, which gave them unprecedented flexibility in their calculations, because there was no symbolic distinction between whole numbers and fractions.

Thus &laquo_space;could be 20, 1200=(20x60), 72,000=(20x60^2), (1/3)=(20 x (1/60)) or (1/180)=(20x(1/60^2)) etc

*from about 300 BC a 0 symbol, two small oblique wedges, came into use for intermediate positions only

40
Q

six decimal cuneiform approximation to root 2*

A

This is found on YBC 7289 ( Yale)

|<

41
Q

Babylonian mathematical operations:*

A

the Babylonians divided by a number by multiplying by its reciprocal, found from a table text, which usually only included reciprocals of Regular sexagesimals.

42
Q

REGULAR SEXGESIMALS

*

A

a regular sexagesimal is a positive integer whose reciprocal has finite sexagesimal expansion or a positive integer of the form 2^x 3^y 5^z for some non-negative integers x,y,z.

125 is a regular sexagesima l:
because 1/125 has finite sexagesimal expansion 0;0,28,48
alternatively 125=5^3 can be expressed in the form 2^x 3^y 5^z

7 is not:
1/7 has infinite recurring sexagesimal expansion 0;(8, 34, 17) overlined()

7 cannot be expressed in the form 2^x 3^y 5^z

43
Q

strengths of the Babylonian number system

*

A
  • every number, large, small, integer, fraction can be written using the two cuneiform symbols | and <
  • computations with sexagesimal fractions are performed in an identical way to those with integers
  • 9 of the first 10 positive integers are regular sexagesimals
  • allowed any number however large or small to be expressed and computations with fractions could be performed in the same way as those with whole numbers
44
Q

weaknesses of the Babylonian number system

*

A
  • ambiguity caused by lack of a 0 symbol and, to a lesser extent, a sexagesimal point
  • Poor cipherization- 59 needs 14 symbols

same number for x60

we denote ; for where sexagesimal point used to be

45
Q

3 old Babylonian tablets

A

BM13901

YBC7289

plimpton 322

obverse and reverse

7% egyptian maths
16% babylonian

  • must be able to write a paragraph about all three tablets
  • regular sexagesimal and by either definition in plimpton 322 as they only use regular sexagesimals to be exact

16 marks 1800 bc old babylonian period

46
Q

Plimpton 322

A

Babylonian tablet.

Columbia University, NEW YORK 12.7 cm by 8.8 cm;right half of larger tablet;4 columns, each of 15 numerals, top left damaged;right column labels Rows 1 to 15.
if x,a,c are the first entries on a given row, a is the shortest, c is the longest side of a right-angled triangle ABC with x =sec^2 A= c^2/(c^2-a^2).

Side b is not on the tablet but is sqrt(c^2-a^2). The x’s (A’s) decrease steadily from top 2.0 (45°) to bottom 1.4, (32 degrees)

  • Boyer corrected 4 errors:difference in writing
  • shows that the early Babylonians were aware of Pythagorean triples and knew some number theory.
47
Q

BM13901

A

Babylonian tablet

British Museum 12 cm by 20 cm problem text, analysed by Neugerbauer 1937.

comprises 24 graded quadratic problems with Solutions, three of the 11 on the reverse missing due to damage

becoming more complex;involving several squares

*one of the three tablets we must write a paragraph about

48
Q

YBC7289

Neugebauer & Sachs

A

Babylonian tablet
Yale University;outline of square and diagonals with three numbers marked: 30 by NW side; 1;24,51,10 (root 2 to 6 d.p) on diagonal; 42;25,35 (30 root(2) diagonal to 4dp) below diagonal.
YALE BABYLONIAN COLLECTION YBC

Neugebauer & Sachs

*it is a round geometrical diagram text 7.6 cm in diameter, showing a square with its diagonals drawn, and three inscribed cuneiform numbers: 30 (three broad wedges) along NW side ; 1;24,51,10 on the horizontal diagonal; and an upward sloping 42;25,35 below this. despite superficial damage, all numerals are clearly legible. The 30 is the length of a side of the square.

The
1;24,51,10 = 1 + (24/60) + (51/60^2) + (10/60^3) = 1.414213 6dp is an approximation to root 2 to 6 decimal places. The Babylonians knew that the diagonal of a square is root 2 times an edge.

Here we note that (The
(1;24,51,10 )x 30 = 42;25,35 is the upward sloping number below the diagonal.

6.dp equiv

1;24,51,10 ~1.414213
root 2 ~ 1.414214

30root2 ~42.426407

42;25,35 ~ 42.426389

49
Q

Babylonian tablet
BM13901

problem 5

A

problem: I add the area and 4/3 of the side of my Square: 0;55. what is the side?

solution:
4/3 1;20. Halve 0;40. Square 0;26;40. Add on 0;55:1;21;40. Square root: 1;10. Subtract 0;40 (that was squared), 0;30 is the side.

this problem and its solution show the Babylonian sexagesima place value arithmetic coping admirably with fractions, addition, subtraction, multiplication, division and square roots, and exhibits that rhetorical algebra sentences not symbols at work in finding the solution. This is to the quadratic equation x^2+(4/3)x = 11/12. The sol x=0.5 is reached by an accepted, but unexplained verbal algorism, typical of Babylonian recipe methods.

The Babylonians knew not of negative numbers, so only the positive square root of 49/36 is given. resulting in just one root of the equation the positive one. The solution of general quadratic equations marks the high point of the Babylonian algebra

50
Q

root 2 in YB7289

A

Here we note that (The
(1;24,51,10 )x 30 = 42;25,35 is the upward sloping number below the diagonal.

multiplication by 30 is easily performed in sexagesimal arithmetic, being essentially division by 2. the tablet shows the effectiveness of the Babylonians number system in obtaining this excellent approximation of root 2 perhaps by a square root algorithm it suggests that they knew a special case of Pythagoras’s theorem, where are where are irrational numbers and had great interest in geometry per se.

*this tablet gives an approximation to route to accurate to almost 6 decimal places

51
Q

plimpton 322 analysis

PYTHAGOREAN TRIPLES

A

first column entries decrease Steadily. heading of the second contains the word width and third column diagonal. let x a c be first 3 numbers in a row of table text plimpton 322 not 11th. Then x,a,c(b) can be written in terms of Regular sexagesima with p and q, p>q. thus:

x=(p^2+q^2)^2/(2pq)^2
a=p^2-q^2
c=p^2+q^2
b=2pq

Given a and c, then p and q can be found from eq p= root( 0.5(c+a)) and q= root( 0.5(c-a)), and x calculated; x can also be found directly from a and c using equation x=c^2/(c^2-a^2)

 On line 1, a=119, c=169 FInd p,q,x:
we have c+a= 288=2p^2
and
c-a=50=2q^2
, from which we deduce that p = 12 and q = 5, both regular sexagesimals. Thus

x=(p^2+q^2)^2/(2pq)^2 = (169^2)/(2(12)(5))^2 = (169/120)^2=28561/14400=1;59,0,15

. In theory, all first entries x on plimpton 322 are exact, since P and Q are regular sexagesimals. In practice, all that can be read of the first row x in the damage top left corner is the final 15.

52
Q

Regular sexagesimals

A

a positive integer is a regular sexagesima if it’s reciprocal has a finite sexagesima expansion or it has the form 2^x3^y5^z, where x,y,z are non-negative integers.

53
Q

Regular sexagesimals: is 7?

A

the sexagesimal expansion of 1/7:
1 divided by 7 is 0, remainder 1; 1x60 divided by 7 is 8 remainder 4; 4x60 divided by 7 is 34 remainder 2; 2x60 divided by 7 is 17 remainder 1. From here the process repeats, showing 1/7 has infinite repeating decimal 0;(8,34,17) overlined and by the first criterion it is not a regular sexagesima clearly 7 is not have the required form 2^x3^y5^z for non negative integers x,y,z and so by the second criterion is not a regular sexagesima

54
Q

Regular sexagesimals: is 51840

A

The sexagesimal expansion of 1/51840; 1 divided by 51840 is 0, reminder 51840; 1x60 divided by 51840 is 0 remainder 51840; 60x60 divided by 51840 is 0, remainder 51840; 60x60x60 divided by 51840 is 4 remainder 8640; 60 x 8640 divided by 51840 is 10. Thus 1/51840 is 0;0,0,4,10
and is a finite sexagesimal expansion. and by the first criterion is a regular sexagesimal. Also 51840=2^7 3^4 5^1

55
Q

The smallest sexagesimal over 200 is 216

A

216=2^3 3^3

by listing in order one primefactor of each after 200 other than 2,3,5,

56
Q

Regular sexagesimals: is 216?

A

1/216 regular sexagesimal expansion

1 divided by 216 is 0, remainder 216; 60 divided by 216 is 0 remainder 216; 60x60 divided by 216 is 16 remainder 144; 144x60 divided by 216 is 40.

Thus it is0;0,0,16,40.

57
Q

plimpton 322 notes

A

*15 rows, 4 rows, broken off corner?

the first 3 entries on a general row of plimpton 322, eleventh excepted, are for some regular hexadecimals p an q:
(p^2+q^2)^2/(4p^2q^2)
p^2-q^2
p^2+q^2

the first of these is c^2/(c^2-a^2), where a and c are respectively the second and third entries on the row.

Given p^2-q^2=319 and p^2+q^2=481. adding and subtracting these equations we find that 2p^2=800, 2q^2=162, p=20 and q=9. Both regular sexagesimals.

58
Q

calculate in sexagesimal form the first entry on the 6th of plimpton 322

A

(481)^2/(2x400x81)

(481)^2/(360^2)=1, remainder 101,761;
(101,761x60)/(360)^2 =47, remainder 14,460;
(14,460)x60/(360)^2 =6, remainder 90,000;
90,000 x60/(360)^2=41, remainder 86,400;
(86,400) x 60/(360)^2 =40

the first entry on row 6 of Plimpton 322 is

1;47,6,41,40

59
Q

Babylonian problem BM 13901 problem 2

A

Subtract side of square from the area: 14,30

write down 1
Divide by 2 0;30
Multiply 0;30 and 0;30: 0;15
Add 14,30 : 14,30;15
This is 29;30 squared
Add 0;30 (which was squared) to 29;30:30,
The side of square
MODERN 
x^2-1x=870
Subtract side of square from area: 870
Write down 1
Divide by two ½
Multiply ½ and ½ : ¼
Add 870 : 870¼
This is 29½ squared
Add ½ (which was squared) to 29½ : 30,
(The) side of square.
60
Q

DECIPHERING CUNEIFORM

A

The key to reading Babylonic cuneiform was found in
1846 by Henry Creswicke Rawlinson, British Consul
in Baghdad, who deciphered the Old Persian part of a
trilingual cuneiform text on the Behistun Cliff. Later he
deciphered the Elamite and Babylonian parts of the text,
and noticed the sexagesimal place-value number system.

THE BEHISTUN CLIFF

This monumental, thirteen panel inscription of 516 BC,
cut on a sheer rock face, high above an ancient caravan
route in west Iran, records the victories of Darius the
Great and depicts him addressing a group of prisoners.

61
Q

SOLVING

Babylonian problem BM 13901

A
x^2 - bx = c
Write down b
Divide by two ½b
Multiply ½b and ½b : ¼b^2
Add c : ¼b^2 + c
This is root(¼b^2 + c) squared
Add ½b (which was squared) to root(¼b^2 + c)

x = ½ b + root(¼b^2 + c)

62
Q

Babylonian problem BM 13901

in an exam paper youll be given such a problem, first of all explain it: halving squaring it etc what method is being done

A

first of all explain it: halving squaring it etc what method is being done

then comments and explanations: eg problem 2

  • Quadratics not uncommon in Babylonian mathematics (unheard in Egyptian)
  • Specific numerical problem- never general
  • Sexagesimal place-value number system effective- no trouble performing the operations roots, adding etc
  • Rhetorical algebra- didnt have a formula but wrote out in words, long-hand
  • Algorithmic/recipe solution, no explanation
  • Only positive square root recognized-one solution
  • Areas and sides subtracted, not practical- wouldn’t normally do this, not a practical solution
  • Exact square root suggests use in scribal training- teaching contexts and exercises from the nice square roots
  • Verbal commentary possibly given to trainee scribes
63
Q

BABYLONIAN TABLETS WHAT DO THEY LOOK LIKE

A

BM13901
rectangular tablet with many problems

obverse?

YBC7289
YALE circlular tablet with diamond shape in middle
1,24,51,10
42,2,5,35

side 30 written

plimpton 322
landscape tablet with rows(4? labelled)

64
Q

Babylonian table text

A

even the oldest tablets attest the high level of computational skill arithmetic process as being carried out with the aid of table texts

showing multiplication tables, tables of reciprocals, squares, cubes, square roots and exponentials..

exponentials were used together with linear interpolation to solve problems on compound interest while reciprocal tables were used to reduce division to multiplication.

65
Q

Algebra Babylonian

A

algebra did the most impressive mathematics by 2000 BC they had developed an extensive rhetorical algebra, solve quadratic equations by a method equivalent to substitution in a general formula, solved simple cubic and quartic equations and mustard simultaneous equations with several unknowns.

although general algebraic methods were understood they were only illustrated by particular cases.

Babylonian geometry was not formal but closely related to Practical menstruation. They found areas and volumes of basic geometric figures, but not all of their rules were correct. They knew Pythagoras’s theorem, although most likely not approve. Calculations of circumferences and areas of circles usually implied a value of Pi of 3, but in one example a better approximation was implied.

66
Q

what was Babylonian mathematics about

A

the overwhelming impression is the study of numbers, and techniques for solving problems involving numbers. Where the numbers arise from where the land measurement, economic questions, geometrical objects, or just abstractly seems a relatively secondary matter.

67
Q

cuneiform: 23

A

&laquo_space;|||

68
Q

cuneiform: 609

A

??

69
Q

cuneiform: 1000

A

16 x 60 + 40x1

.|

70
Q

cuneiform: 610

A

keeps deleting but

10*60 + 10

71
Q

PLIMPTON 322 notes 2

A

some mistakes made by the scribe

titles at the top:
___ width diagonal

15 rows

EXAM:
we should be able to work out the number which is missing given a row :third side of triangle isn’t on the tablet, by pythagoras and then work out the angle.

The middle side (adjacent) is missing from the tablet for the right angles triangles.

The number that isn’t on the tablet is a regular sexagesimal.
because reciprocal has finite expansion.

72
Q

PLIMPTON 322

FIRST ROW IMPRESSIONS

A

width a = 1 , 59 = 119
diagonal c = 2 , 49 = 169

b^2 = c^2 - a^2 = 169^2 - 119^2
= 120^2

b = 120 = 2^3 . 3^1 . 5^1

A roughly equal to 45 degrees (nearest)

73
Q

PLIMPTON 322

THE GRAND DESIGN

A

column 1 2 3 4

c^2/(c^2- a^2) a c row

c^2/(c^2- a^2) , diagonal c , width, (row number on right)

ordered in decreasing angles

b^2= c^2-a^2 : b isnt on the tablet, has form 2^x3^y5^z

74
Q

PLIMPTON 322

fifth row

A

972 / 722 = 1 ; 48 , 54 , 1 , 40 65 97 5

a~ 42 degrees
b=72 = 2^33^25^0
97^2/72^2=1;48,54,1,40 ~ 1.813007716…

75
Q

PYTHAGOREAN TRIPLES

way of constructing sides of right angled triangled

in the exam:

A

Pythagorean triple:
a = p^2 - q^2 ;
b = 2pq ;
c = p^2 + q^2

p,q are regular sexagesimals qith p>q
side not on tablet:
b=2pq

you’ll be given the two numbers on the middle of the row and you calculate p and q given a and c.

first entry on the row is
(p^2+q^2)^2/4p^2q^2
=
(c^2/b^2)

which is always finite sexagesimal expansion

76
Q

GENERAL ROW OF PLIMPTON 322

A

except eleventh

(p^2+q^2)^2/4p^2q^2 (c^2/b^2) p^2- q^2 = a p^2 + q^2 = c row

fifth row

p=9 q=4
(9^2+4^2)^2/4 .9^2.4^2 9^2-4^2 9^2 + 4^2 5

77
Q

questions?

A

see booklet

see past exam papers

78
Q

PUBLISHED YBC7289 and PLIMPTON 322

A

in MATHEMATICAL CUNEIFORM TEXTS

by Neugebauer & Sachs

published these tablets

79
Q

cuneiform: 25

A

&laquo_space;|||

80
Q

sexagesimal expansion: 3/4

A

0;45

81
Q

sexagesimal expansion: 1/59

A

0;1,1,1,1,1,…

infinite so irregular sexagesimal

82
Q

analyse the following Babylonian problem and its solution: I have added the area and two-thirds of the side of my Square, and it is 0;35. What is the side of my Square?
solution:
two-thirds is 0;40 half of this is 0;20, you multiply by 0;20 and it is 0;6,40 , you add to 0;35 and it is 0;41,40, which has 0;50 as its square root. The 0;20 which you have multiplied by itself, you subtract from 0;50, and 0;30 is the side of the square.

A

this is solving quadratic equation x^2 +px=q

where p = 0;40, q= 0 ;35. Recipe Leads first to (0.5p)^2 thensqrt((0.5p)^2+q), the side.

83
Q

verify the solution given below to:
x + y = p and x y = q
where p & q are bigger than 0 and (p/2)^2 >q

to which quadratic equation is this problem equivalent? Use method to solve x + y = 6;30 and xy = 7;30

A

solution:
let z^2=(p/2)^2-q. Then x=(p/2)/+z, y=(p/2)-z. clearly x and y satisfy the equations, which are equivalent to the quadratic equation x^2-(p+q)x+q=0. With p=6;30 and q=7;30, z=7/4 and x=5, y = 1.5 or vice versa

84
Q

the Babylonians solve quadratic equations with positive roots studying three types:

1) x^2+px=q
2) x^2=px+q
3) x^2+q=px

where p &q bigger than 0. Type 3 however was only studied in the equivalent form:
x+y=q & xy=q.
Which type of quadratic equation is missing, and why?

A

x^2+px+q=0

is missing as it has no positive roots

85
Q

which feature of Babylonian mathematics first appeared in the Seleucid period. Explain the term

A

0 symbol

the Seleucid period 312-63 bc

Seleucus, one of Alexander’s leading generals, became satrap (governor) of Babylonia in 321, two years after the death of Alexander.

86
Q

one Seleucid tablet give the solution to the following problem:

A reed stands upright against the wall. It stop slides down 3 units, while its Lower End slides along 9 units how long is the reed?

A

using Pythagoras’s theorem.

*shows that the early Babylonians were aware of Pythagorean triples and knew some number theory.

87
Q

implicit value of Pi given as a ratio of the perimeter of a regular hexagon to the circumference of its circumcircle

A

0;57,36

3(1/8)

Area=(8/9 diameter)^2
`~256/81 * r^2

6% increase

by squaring and doubling

88
Q

62 in cuneiform

A

1*60 + 2

||
Big space in between

89
Q

74

A

> ||||

90
Q

4871

A

1,21,11

it is | “less than”“less than”| “less than”|

160^2 +(2160) +11

91
Q

BM 13901: Problem 2
Commentary

Subtract side of square from area: 14,30
Write down 1
Divide by two 0 ; 30
Multiply 0 ; 30 and 0 ; 30 : 0 ; 15
Add 14,30 : 14,30 ; 15
This is 29 ; 30 squared
Add 0 ; 30 (which was squared) to 29 ; 30 : 30,,
(The) side of square.
A

BM 13901: Problem 2
Commentary
Quadratics not uncommon in Babylonian mathematics
Specific numerical problem
Sexagesimal place-value number system effective
Rhetorical algebra
Algorithmic/recipe solution, no explanation
Only positive square root recognized
Areas and sides subtracted, not practical
Exact square root suggests use in scribal training
Verbal commentary possibly given to trainee scribes

92
Q

One of the most remarkable documents of

Old Babylonian mathematics

A

One of the most remarkable documents of
Old Babylonian mathematics
O. Neugebauer

on PLIMPTON 322