EA Math Practice Flashcards

1
Q

If Randy has twice as many coins as Alice, and if Maria has 7 times as many coins as Alice, what is the combined number of coins that all three of them have?

(1) Alice has 4 fewer coins than Randy.

(2) Maria has 20 more coins than Randy.

A

R = 2A
M = 7A

A + 4 = R
R + 20 = M

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2
Q
A
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3
Q
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4
Q
A

Remember to make equations where possible

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5
Q
A
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6
Q

Simplify 14.25 / 91.25

A

(a) Find a simple fraction that is closest, e.g. in this case 1/6. Know that 1/6 is 0.1666. Adjust for actual numbers slightly if possible.
(b) Simplify (in this case divide by 25). Then do the above. The smaller numbers will make adjusting easier

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7
Q

Last year, all registered voters in Kumannia voted for the Revolutionary Party or for the Status Quo Party. This year, the number of Revolutionary voters increased 10%, while the number of Status Quo voters increased 5%. No other votes were cast. If the number of total voters increased 8%, what fraction of voters voted Revolutionary this year?

A

Two tricks:
- Watch for x + y = 100%
- Sub in an easy number

Here make the total for last year 100. So T = R + (100-R).

This year 1.1R + 1.05(100-R) = 108.

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8
Q

A grocery store sells two varieties of jellybean jars, and each type of jellybean jar contains only red and yellow jellybeans. If Jar B contains 20% more red jellybeans than Jar A, but 10% fewer yellow jellybeans, and Jar A contains twice as many red jellybeans as yellow jellybeans, by what percent is the number of jellybeans in Jar B larger than the number of jelly beans in Jar A?

A

Very simple if:
- Assume some number (e.g. here Jar A has 100 red)
- Make a simple table

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9
Q

A feed store sells two varieties of birdseed: Brand A, which is 40% millet and 60% sunflower, and Brand B, which is 65% millet and 35% sunflower. If a customer purchases a mix of the two types of birdseed that is 50% millet, what percent of the mix is Brand A?

A

Here assume some number (100) for the amount of Brand B.

0.4(x) + 0.65(100) = 0.5 (x + 100)

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10
Q

A string of 10 lightbulbs is wired in such a way that if any individual lightbulb fails, the entire string fails. If for each individual lightbulb the probability of failing during time period T is 0.06, what is the probability that the string of lightbulbs will fail during time period T ?

A

This is tricky. I initially answered 0.6^10. However, this is the probability that all fail. (Logically, I should have known this was incorrect as the probability gets smaller as the number of bulbs increases).

Instead the answer is 1 − (0.94)^10

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11
Q

If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?

A

This was hard.

Easies solution might be more manual. (1086) to reflect the total number of options divided by 3! because the order does not matter.

Note I tried using the standard equation for a combination (3 of 5 spots) but this fails to fully account for 2 options per seat. The result 10 must be multipled by 2 for each seat (i.e. 3 times)

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