Dynamics (Kinematics) Flashcards
Displacement (s)
Distance moved from a point in given direction. It is a vector.
Velocity (v), and its equation
The rate of change of displacement with time. It is a vector. Equation = change in speed/ time.
Acceleration (a), and its equation and units
The rate of change of velocity with time. It is a vector. Its units are ms^-2. Equation = change in velocity/ time.
Uniform acceleration
Uniform acceleration is where the velocity of an object moving along a straight line changes at a constant rate. (the acceleration is constant).
Non-uniform acceleration
Non-uniform acceleration is where the direction of the motion of an object changes, or its speed changes, at a varying rate.
When can Suvat be used
When acceleration is constant
What does Suvat stand for
s- displacement
u- initial velocity
v- final velocity
a- constant acceleration
t- time
Acceleration due to gravity
For something under freefall assuming no air resistance: F=ma so mg=ma g=a
Ball Bearing Freefall Method RP
Method
When the current to the magnet switches off, the ball drops and the timer starts
When the ball hits the trapdoor, the timer stops
Measure distance with metre ruler
S=ut+1/2at^2 graph analysis
Straight line graph through origin of speed against time^2 graph
Gradient= 1/2a
Vertical Projectiles
When projectile is thrown vertically upwards
Use Suvat
choose upwards as positive direction
a= -9.81
at highest point v=0
Horizontal Projectiles
Where projectile is projected perpendicular to the vertical
Does not affect vertical motion
Think of vertical and horizontal components separately.
Solving Horizontal Projectile
1, draw diagram
2, consider vertical first (downwards positive)
3, suvat (a= 9.81)
4, then horizontal use. s= d/ t
Non-Horizontal projectiles
1, draw diagram
2, find initial velocities even if unknown variables (trig or pythag)
3, vertical direction (a= -9.81, u= vertical side, top of curve v= 0, end of curve v= -u, s=0
4, horizontal direction s= d/t
Effect of air resistance on a falling object
At instant of release- 0 speed so 0 AR (a=g=9.81)
Later- speed increased so AR increased, resultant force down so a down
Eventually- AR increases until equal to weight, resultant force= 0, so a=0 and v is constant (terminal velocity).