Dosage Compensation Flashcards
What is epigenetics?
The study of mitotically heritable changes in gene function that cannot be explained by changes in DNA sequence. (NOT novel mutations in genome)
What are the 2 major mechanisms of epigenetic regulation?
o Methylation of DNA
o Modification of histone proteins
o Both of these modifications modulate the transcriptional potential of genes (i.e. they regulate gene expression)
What is DNA Methylation?
- The formation of 5-methylcytosine
o When DNA methyl transferase catalyzes addition of methyl group onto cytosine - Occurs in CpG islands which are typically found in the upstream regulatory regions of eukaryotic genes (promoters)
- It is associated with REPRESSION of transcription
o i.e. genes where the promoter has been methylated are typically inactive.
- Responsible for genomic imprinting
How does DNA Methylation block transcription?
-Doesn’t interfere with H bonding between bases-
o Represses gene expression through 2 mechanisms:
- Prevents binding of transcription factors to promoter by adding methyl group into major groove of DNA so transcription factor doesn’t recognize promoter - Recruits MBD proteins which recruit chromatin remodeling proteins leading to formation of “repressive” chromatin
What is genomic imprinting?
DNA methylation of either the maternal or paternal allele of an autosomal gene results in the origin of the allele determining its phenotype.
What are 2 examples of genomic imprinting?
Prader-Willi syndrome
Angelman Syndrome
Prader-Willi Syndrome
o Characterized by uncontrolled appetite
o Results from deletions in the q11-q13 region of chromosome 15 on the PATERNAL chromosome
o HOW?
- Deletion in q11-q13 region of chromosome 15 leads to loss of 2 genes - In EVERY HUMAN maternal copy of gene SNRPN is methylated - In EVERY HUMAN paternal copy of gene UBE3A is methylated - This means that in all humans those 2 genes are hemizygous, because they only active on one chromosome - Loss of SNRPN function = Prader-Willi syndrome - So if paternal deleted, SNRPN only on maternal chromosome where it is methylated.. so its function is lost.
Angelman Syndrome
o Characterized by behavioral issues
o Results from deletions in the q11-q13 region of MATERNAL chromosome 15…
o HOW?
- Deletion in q11-q13 region of chromosome 15 leads to loss of 2 genes - In EVERY HUMAN maternal copy of gene SNRPN is methylated - In EVERY HUMAN paternal copy of gene UBE3A is methylated - This means that in all humans those 2 genes are hemizygous, because they only active on one chromosome - Loss of UBE3A function = Angelman syndrome - So if maternal deleted, UBE3A function lost
Chromatin Structure
- DNA is complexed by histone proteins (H2A, H2B, H3 & H4) into nucleosomes
- Nucleosomes condense together to form chromatin
- Chromatin structure is dynamic
- Degree to which nucleosomes are packed can regulate transcription
What is repressive chromatin?
Condensed chromatin when nucleosomes are tightly packed. Represses transcription
What is Open Chromatin?
Permissive, loose nucleosome packing. Increases transcription.
2 types of post-translational histone modification
o Methylation = Adds methyl group - condenses chromatin
o Acetylation = Adds acetyl group - opens chromatin
SWI/SNF Chromatin Remodeler
o Methylation of lysine 9 on Histone 3 (H3K9Me) by Hp1 compacts chromatin into heterochromatin.
o SWI/SNF chromatin remodeler recognizes acetylation of lysine 9 on Histone 3 (H3K9Ac) opens up chromatin structure and makes it easy for basal factors to access promoter region of genes in that area
2 strategies for dosage compensation
- Increased transcription of X chromosome (Drosophila)
2. Inactivation of 1 X chromosome (Mammals)
What are the 5 Male Sex Lethal proteins which form the MSL complex?
- MLE (maleless) – RNA helicase
- MSL1 (male sex lethal 1) – Binds chromatin
- MSL2 – Binds chromatin
- MSL3 – Binds methylated histones
- MOF (males absent on first) – Histone acetyltransferase
- MSL proteins localize to the X chromosome in male flies
- Loss of any one MSL proteins greatly reduces binding of the others to X
o i.e. all 5 need to be there for the complex to form