Dosage Compensation Flashcards

1
Q

What is epigenetics?

A

The study of mitotically heritable changes in gene function that cannot be explained by changes in DNA sequence. (NOT novel mutations in genome)

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2
Q

What are the 2 major mechanisms of epigenetic regulation?

A

o Methylation of DNA
o Modification of histone proteins

o Both of these modifications modulate the transcriptional potential of genes (i.e. they regulate gene expression)

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3
Q

What is DNA Methylation?

A
  • The formation of 5-methylcytosine
    o When DNA methyl transferase catalyzes addition of methyl group onto cytosine
  • Occurs in CpG islands which are typically found in the upstream regulatory regions of eukaryotic genes (promoters)
  • It is associated with REPRESSION of transcription

o i.e. genes where the promoter has been methylated are typically inactive.
- Responsible for genomic imprinting

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4
Q

How does DNA Methylation block transcription?

A

-Doesn’t interfere with H bonding between bases-

o Represses gene expression through 2 mechanisms:

   - Prevents binding of transcription factors to promoter by adding methyl group into major groove of DNA so transcription factor doesn’t recognize promoter
   - Recruits MBD proteins which recruit chromatin remodeling proteins leading to formation of “repressive” chromatin
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5
Q

What is genomic imprinting?

A

DNA methylation of either the maternal or paternal allele of an autosomal gene results in the origin of the allele determining its phenotype.

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6
Q

What are 2 examples of genomic imprinting?

A

Prader-Willi syndrome

Angelman Syndrome

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7
Q

Prader-Willi Syndrome

A

o Characterized by uncontrolled appetite
o Results from deletions in the q11-q13 region of chromosome 15 on the PATERNAL chromosome

o HOW?

   - Deletion in q11-q13 region of chromosome 15 leads to loss of 2 genes
   - In EVERY HUMAN maternal copy of gene SNRPN is methylated
   - In EVERY HUMAN paternal copy of gene UBE3A is methylated
   - This means that in all humans those 2 genes are hemizygous, because they only active on one chromosome
   - Loss of SNRPN function = Prader-Willi syndrome
   - So if paternal deleted, SNRPN only on maternal chromosome where it is methylated.. so its function is lost.
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8
Q

Angelman Syndrome

A

o Characterized by behavioral issues
o Results from deletions in the q11-q13 region of MATERNAL chromosome 15…

o HOW?

   - Deletion in q11-q13 region of chromosome 15 leads to loss of 2 genes
   - In EVERY HUMAN maternal copy of gene SNRPN is methylated
   - In EVERY HUMAN paternal copy of gene UBE3A is methylated
   - This means that in all humans those 2 genes are hemizygous, because they only active on one chromosome
   - Loss of UBE3A function = Angelman syndrome
   - So if maternal deleted, UBE3A function lost
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9
Q

Chromatin Structure

A
  • DNA is complexed by histone proteins (H2A, H2B, H3 & H4) into nucleosomes
  • Nucleosomes condense together to form chromatin
  • Chromatin structure is dynamic
  • Degree to which nucleosomes are packed can regulate transcription
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10
Q

What is repressive chromatin?

A

Condensed chromatin when nucleosomes are tightly packed. Represses transcription

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11
Q

What is Open Chromatin?

A

Permissive, loose nucleosome packing. Increases transcription.

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12
Q

2 types of post-translational histone modification

A

o Methylation = Adds methyl group - condenses chromatin

o Acetylation = Adds acetyl group - opens chromatin

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13
Q

SWI/SNF Chromatin Remodeler

A

o Methylation of lysine 9 on Histone 3 (H3K9Me) by Hp1 compacts chromatin into heterochromatin.

o SWI/SNF chromatin remodeler recognizes acetylation of lysine 9 on Histone 3 (H3K9Ac) opens up chromatin structure and makes it easy for basal factors to access promoter region of genes in that area

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14
Q

2 strategies for dosage compensation

A
  1. Increased transcription of X chromosome (Drosophila)

2. Inactivation of 1 X chromosome (Mammals)

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15
Q

What are the 5 Male Sex Lethal proteins which form the MSL complex?

A
  1. MLE (maleless) – RNA helicase
  2. MSL1 (male sex lethal 1) – Binds chromatin
  3. MSL2 – Binds chromatin
  4. MSL3 – Binds methylated histones
  5. MOF (males absent on first) – Histone acetyltransferase
  • MSL proteins localize to the X chromosome in male flies
  • Loss of any one MSL proteins greatly reduces binding of the others to X
    o i.e. all 5 need to be there for the complex to form
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16
Q

What are the key players in Drosophila Compensation?

A
  1. MSL proteins in the MSL Complex

2. Non-protein coding RNAs (rox1 & rox2)

17
Q

Evidence for an RNA component of the MSL complex

A
  1. MLE protein contains an RNA binding domain (therefore it must have an RNA mol to bind to)
  2. Treatment with RNAse abolishes binding of MLE protein to X chromosome
18
Q

rox RNA

A
  • rox RNAs don’t encode proteins and co-localize with MSL proteins on the X chromosome in males
  • rox1 and rox2 are redundant (i.e. you don’t need both)
19
Q

What is the process of the MSL complex formation?

A

o First transcription of rox RNA
o Binds to X chromosome from which its transcribed
o Leads to recruitment of MLE protein (has RNA binding domain)
o Once MLE is bound, the other 4 proteins in the complex bind

20
Q

Mechanism of dosage compensation in Drosophila

A
  • Binding of MSL complex leads to hyperacetylation of H4K16 in males
    o This is catalyzed by MOF which is a histone acetyl-transferase.
  • Because of this Males have high levels of a specific histone marker (H4K16Ac) on the nucleosomes along the entire length of the X chromosome
  • This marker is recognized by chromatin remodelers which open up the chromatin structure
    o Because this histone marker is present on all nucleosomes along the entire chromosomes, the entire chromosome is opened.
  • This allows basal transcription machinery to more easily access gene promoters
  • So transcription rate of genes on male X chromosome is higher (2x level of single x chromosome in females).
21
Q

What prevents dosage compensation from occurring in Drosophila females?

A
  • Sxl binds to the 3’ UTR of the MSL2 mRNA blocking translation = no MSL2 protein produced -> no dosage compensation occurs.
22
Q

What are the parallels between dosage compensation in Drosophila and in mammals?

A
  1. Involves determining number of X chromosomes
  2. Involves X-linked non-protein coding RNAs (in mammals = Xist & Tsix)
  3. Xist work in cis (meaning they bind to the X chromosome from which they are transcribed)
  4. Leads to large scale modification of Lys residues in histone tails along the entire length of X chromosome in mammals
23
Q

What is the mechanism of X chromosome inactivation in mammals?

A
  • Large non-coding RNA’S are overlapping
  • No free Xist RNA in the nucleus because transcription of Tsix leads to dsRNA (because it overlaps with Xist) so it is degraded
  • In Xa (active X chromosome) Xist expression is turned off and Tsix is left on
  • In Xi (inactivated X chromosome) Xist expression is left on and Tsix is turned off.
    o Means that Xist is transcribed and not ‘mopped up’ to form dsRNA by Tsix.
  • Xist remains attached to X chromosome it was transcribed from and serves as scaffold to recruit PRC2 complex which deposits a specific histone marker (Tri-methylation of H3K27)
  • PRC1 complex (chromatin remodeler) recognizes histone marker and it compacts chromatin down to form barr body (highly dense and transcriptionally silent)