Doppler Ultrasound Flashcards

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1
Q

State the Doppler Equation.

A
f_d=[2*f_t*v*cos(theta)]/c
f_d=f_r-f_t
f_d = Doppler shift frequency
f_t = transmitted frequency
f_r = received frequency
v = velocity of target
c = speed of sound in medium
theta = angle between beam and target motion
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2
Q

Briefly explain how a CW-Doppler probe measures velocity.

A
  • 1 element continuously emits, 1 continuously receives.
  • Emitted and received signals are mixed together and high passed filtered to remove the signal from the ultrasound.
  • Remaining frequencies arise from Doppler shift caused by moving targets.
  • velocity is calculated using Doppler equation, 1540 SoS, and user defined angle correction.
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3
Q

Explain how quadrature demodulation gives directional information from the Doppler signal.

A
  • Quadrature signal created by phase shifting transmitted signal by pi/2.
  • Quadrature and in-phase signal both separately mixed with received signal to create imaginary and real components of signal respectively.
  • After filtering the relative phase on the real to imaginary signals will depend on whether the target tissue velocity is positive or negative.
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4
Q

Explain how directional information can be sent to audio speakers in CW-Doppler.

A
  • Forward flow can be sent by mixing the imaginary part with the pi/2 phase shifted real part.
  • Reverse flow can be sent by mixing the real part with the pi/2 phase shifted imaginary part.
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5
Q

Explain what the “Wall Thump” filter is, and its purpose in CW-Doppler.

A
  • Scattering coefficients of wall tissues are 10-100 times larger than those of RBCs.
  • Wall motion is much slower, and so has lower Doppler frequency.
  • High-pass filtering the Doppler signal (once demodulated) removes the low velocity motion of the walls, leaving only the blood signal.
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6
Q

How is a Doppler spectrogram formed from the Doppler signal?

A
  • Fast-Fourier transform of the signal will give the frequency peaks of the signal.
  • The frequency of the peak will give the velocity of the target, and the height of the peak (Power density) will give the number of targets at that velocity.
  • Pixels at that velocity for that time will be made brighter proportional to their power density.
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7
Q

What are the main differences between PW and CW Doppler?

A
  • CW Doppler has long sensitive region that is a function of the probe geometry and, generally not, user definable.
  • CW-Doppler is more sensitive than PW and doesn’t suffer from aliasing.
  • PW-Doppler has a sensitive region that is definable for both depth and length.
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8
Q

What are the two methods for assessing velocity using PW-Doppler?

A
  • Phase-Domain

- Time-Domain

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9
Q

Explain how phase domain systems measure velocity in PW-Doppler.

A
  • Similar to CW demodulation, but the short duration of the received wave compared to the reference signal means that the frequency cannot be accurately measured.
  • The amplitude of the mixed signal will vary as the phase of the received wave varies. This varying amplitude varies at the Doppler frequency, and can be measured,
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10
Q

Why does “Downshifting” in PW-Doppler mean that the real Doppler effect is not measured?

A
  • Attenuation of ultrasound in tissue increases with frequency.
  • Higher frequencies are attenuated faster, and so the pulses are downshifted as they propagate, which is greater than the Doppler shift.
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11
Q

How does a time-domain system measure velocity?

A
  • RF data is interrogated and the time difference between the same echo allows the determination of the distance traveled.
  • Time between the the pulses (1/PRF=PRI) is known and so the velocity can be calculated.
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12
Q

How would simultaneous Doppler be performed for a small depth and low PRF?

A
  • B-mode pulse sent out after each Doppler pulse.
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13
Q

How would simultaneous Doppler be performed for a high PRF?

A
  • A few B-mode pulses after a large group of Doppler pulses.
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14
Q

How would simultaneous Doppler be performed for a large depth and low PRF?

A
  • Gaps in Doppler trace filled by interpolation.
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15
Q

Explain what is meant by intrinsic spectral broadening.

A
  • Finite beam width will focus on the target at different angles.
  • Difference in actual angle and angle correct will cause variation in measured velocities.
  • This range increases with increasing Doppler angle.
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16
Q

How is a Doppler pulse different from a conventional B-mode pulse?

A
  • Longer in duration

- Typically between 4-8 cycles

17
Q

How is a colour Doppler image acquired?

A
  • Each Doppler D-line is divided into “range gates”.
  • Mean Doppler shift frequency is obtained for each gate, and velocity is calculated.
  • D-Line runs parallel to colour box.