DNA & Genomics Flashcards

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1
Q

5’ cap

A

[structure]
- addition of 5’ methyl guanosine nucleoside triphosphate to the first nucleotide by 5’-5’ triphosphate linkage, forming 5’ methylguanosine cap
- addition of 5’ methylguanosine cap is catalysed by guanylyl transferase
- 5’ cap is added after transcription of the First 20-40 nucleotides
[function]
- facilitates the export of mature mRNA from nucleus into cytoplasm
- protects mRNA from 5’ exonucleases, thus confers stability to the mRNA
- facilitates in binding of ribosomes to mRNA

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2
Q

3’ poly-A tail

A

[structure]
- polyadenylation signal sequence, AAAAAU,is a signal for transcription termination and polyadenation of the 3’ end of mRNA
- 200 adenine residues are added to the 3’ end of the pre-mRNA, forming the 3’ poly-A tail
- formation of poly-A tail is catalysed by poly-A polymerase
[function]
- facilitates the export of mature mRNA from nucleus into the cytoplasm
- slows down degradation by 3’ exonucleases; the longer the poly-A tail, the longer the half life of mRNA

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3
Q

Difference in structure between ribosome and RNA polymerase

A
  • Ribosome consists of 2 subunits whereas RNA polymerase consists of large molecule of protein with many subunits
  • Ribosome is made up of proteins and ribosomal RNA whereas RNA polymerase is made up of protein only
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4
Q

List three ways in which the process of transcription is different from the process of translation

A
  • Transcription uses DNA as a template to synthesise mRNA while translation uses mRNA as template to synthesise polypeptide chains
  • Transcription results in the formation of phosphodiester bonds catalysed by RNA polymerase while translation results in the formation of peptide bonds cant alters by peptidyl transferase
  • Transcription uses ribonucleotides as monomers to build up into polymers while translation uses amino acids as monomers to build up into polymers
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5
Q

Explain the reason for the production of Okazaki fragments

A
  • DNA is anti parallel as DNA polymerase adds nucleotides in the 5’ to 3’ direction on both sides of the replication fork
  • One daughter strand is synthesised towards the fork while the other is synthesised away from the replication fork
  • Hence, resulting in the lagging strand being synthesised discontinuously via okazaki fragments
  • Multiple primers need to be added to provide each fragment with a 3’ OH end for the addition of bases
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6
Q

Describe how replication of the lagging strand template occurs

A
  • The lagging strand is synthesised discontinuously, via a series of Okazaki fragments away from the replication fork, catalysed by DNA polymerase III
  • Each okazaki fragment needs to be primed separately, where primase catalyses the synthesis of the RNA primers
  • RNA primers are excised and replaced with deoxyribonucletides by another DNA polymerase
  • DNA ligases catalyses the formation of phosphodiester bond between two okazi fragments
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7
Q

Explain why transcription and translation are able to occur simultaneously in a bacterial cell such as E.coli

A

Bacterial cells do not contain nuclear envelope hence RNA polymerases involved in transcription and ribosomes involved in translation are all found in the cytoplasm

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8
Q

Explain how the information to synthesise polypeptides is coded for by DNA

A
  • Transcription occurs using one strand of DNA as template to synthesise mRNA via complementary base pairing by RNA polymerase
  • mRNA is translated by ribosomes to form the polypeptide chain
  • Each codon on the mRNA codes for an amino acid, therefore the DNA sequence of a gene determines the primary structure of a polypeptide chain
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9
Q

State what is meant by semi-conservative DNA replication

A
  • The two strands of the parental molecule separate by breaking hydrogen bonds between complementary bases
  • Each strand acts as template for synthesis of newly synthesised strand
  • The daughter DNA molecule contained one strand which is conserved from the parental molecule and the other newly synthesised strand
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