DNA and genes, protein synthesis Flashcards

1
Q

Differences between Eukaryotic + prokaryotic DNA

A

E = Longer, linear and associated with histones

P= Shorter, circular and not associated with histones

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2
Q

Define gene

A

A base sequence of DNA that codes for the amino acid sequence of a polypeptide and a functional RNA

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3
Q

Locus is …

A

the position of a gene on a chromosome

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4
Q

3 features of a genetic code

A
  1. Degenerate
  2. Universal
  3. Non-overlapping
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5
Q

Genetic code being degenerate means…

A

more than one triplet of bases can code for the same amino acid

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6
Q

Advantage of genetic code being degenerate

A

If mutation occurs even though the triplet of bases will be different , it may still code for the same amino acid and have no effect

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7
Q

Genetic code being universal means…

A

same triplet of bases codes for the same amino acid in all organisms

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8
Q

Genetic code being non - overlapping

A

Each base in a gene is only part of one triplet of bases that codes for one amino acid. Thus, each codon/triplet of bases is read as a discrete unit.

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9
Q

Introns are

A

sections of DNA that do not code for polypeptides

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10
Q

Exons

A

sequences of DNA that do code for amino acid

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11
Q

Genome is…

A

an organisms complete set of genes in a cell (never changes unless mutation)

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12
Q

Proteome is …

A

the full range of proteins that a cell is able to produce ( changes constantly)

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13
Q

Process of transcription

A
  1. DNA helicase unwinds DNA helix to expose the bases by breaking the hydrogen bonds.
  2. One strand acts as a template. Free mRNA nucleotides in the nucleus align opposite exposed complementary DNA bases.
  3. DNA polymerase joins together the RNA nucleotides to create a new RNA polymer chain
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14
Q

What happens after transcription in eukaryotes

A

Introns are spliced out by splicesome

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15
Q

Process of translation

A
  1. mRNA leaves the nucleus and attaches to a ribosome in the cytoplasm. The ribosome attaches at the start codon,
  2. tRNA with the complementary anticodon aligns opposite the mRNA.
  3. Ribosome will move along one codon on the mRNA to enable another complementary tRNA to attach to the next codon on the mRNA
  4. The two amino acids join to form a peptide bond. (Catalysed by an enzyme + ATP). tRNA then deattaches and leaves.
  5. This continues to happen until it reaches the stop codon. Ribosome detaches+ translation ends
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