DNA 1 Flashcards
1
Q
Structure of DNA
A
- Double helix
- DNA strands are antiparallel
- Each strand consists of long chain of nucleotides, each comprising of a deoxyribose sugar, phosphate group and nitrogeneous base
- Nitrogeneous base can be A/T/C/G
- Each strand contains a sugar phosphate backbone - comprising of nucleotides arranged in sequence, held together by phosphodiester bonds between C3 of the sugar of 1 nucleotide and C5 of the sugar of another nucleotide
2
Q
Roles of DNA
A
- Storage of genetic information
- Directs protein synthesis
3
Q
Semi-conservative replication
A
- 2 parental DNA strands separate due to breaking of hydrogen bonds between complementary bases.
- Each strand acts as a template for the synthesis of a complementary daughter strand
- Each new DNA molecule consists of 1 newly synthesised DNA strand and 1 original DNA strand
4
Q
Describe how replication of lagging strand occurs
A
- The lagging strand is synthesised discontinuously, resulting in Okazaki fragments, as the 2 parental strands are antiparallel
- Due to the shape of active site and enzyme specificity, DNA polymerase works only from the 5’ to 3’ direction
- Hence, DNA polymerase can only add DNA nucleotides to 3’ -OH end of an existing strand
- Removal of RNA primer of each Okazaki fragments results in gaps which are subsequently sealed by DNA ligase, which catalyses the formation of phosphodiester bonds between adjacent nucleotides
5
Q
Describe how the end replication problem arises
A
- During DNA replication, DNA polymerase requires a free 3’ -OH end of an existing strand to add nucleotides
- RNA primer is synthesised to provide the free 3’ -OH end for addition of nucleotides. RNA primer is then replaced by DNA nucleotides
- However, RNA primer at the 5’ end of the newly synthesised strand cannot be replaced by DNA nucleotides as there is no free 3’ -OH end
- Since DNA polymerase is unable to complete replication at the 5’ end of lagging strands, this creates a 3’ overhang at the end of the chromosome
- Due to the end replication problem, the ends of chromosomes shorten with each round of DNA replication
- Since telomeres are found at the ends of the chromosomes, shortening of chromosomal ends leads to shortening of the telomeres without any deleterious effect
6
Q
Describe the structure of eukaryotic genome
A
- Negatively charged DNA wounds around a histone octamer, consisting of 2 molecules of H2A, H2B, H3 and H4 each, forming a nucleosome
- Individual nucleosomes are connected by strands of linker DNA, forming a 10nm nucleohistone complex
- With the aid of H1 histones, the string of nucleosomes coils to form a 30nm chromatin fibre
- The 30nm chromatin fibre folds to form looped domains attached to a base of scaffolding proteins, forming the 300nm chromatin fibre, which is then further coiled and compacted to form a chromatid of a highly condensed chromosome structure
7
Q
Suggest 2 reasons why replication of a human chromosome would take so long
A
- Length of DNA in humans is longer
- DNA is wound around histones to form nucleosomes, hence decondensing has
to take place first