Dimensional analysis Flashcards

1
Q

When doing cubic relationship qs

A
  1. You know that 1 (cm) = 5.32 n for example
  2. c(cm³) means volume so a cubic centimeter is 3D space, so you need to think in three directions (length, width, height).
  3. cube the conversion factor
  4. e.g 5.32×5.32×5.32=150.56
  5. you just multiply your given volume (6.42 cm³) by 150.72 to convert it to cubic nogs.
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2
Q

when trying to find mass of metal in a compound i do…

Ca makes up 20.1% of the mass of the calcium-containing compound calcium bromide, CaBr2. If there are 38.3 g of calcium present in a sample of calcium bromide, what is the total mass of the sample?

A
  1. Ca makes up 20.1% of the total mass of (CaBr₂).
    - means that for every 100 g of CaBr = 20.1 g of it is calcium.
    - If calcium is 20.1% of the total mass, and you know the amount of calcium (38.3 grams)
    - 0.201×X=38.3
    - 3.83/0.201
    - x =190.45
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3
Q

Determine the value of a:

log a = 3.253

A
  • a is the number whose logarithm (base 10) = 3.253.
  • To find a, we need to reverse the logarithm
  • ## a=10 ^ 3.253
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4
Q

Simplify: 𝑎^5/𝑎^−2

A
  1. we subtract the exponents:
  2. Subtracting a negative is the same as adding:
  3. 5−(−2)=5+2=a^7.
    4.
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5
Q

how to solve If 42% of a number is 18, what is the number?

A
  1. We know that 42% of x is 18.
  2. To find x, divide both sides of the equation by 0.42
  3. 18/0.42
  4. x=42.86
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6
Q

calculating pH based on hydronium ion concentration and vice versa

A
  • pH=−log[H30+]
  • f you’re given a logarithmic equation and you want to solve for what’s inside the logarithm [H30+], you have to “undo” the log.
  • log [H30+] = −5.53 means H30+ —> 10 ^−5.53
    .
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7
Q

unit of measurment

A

Length: meter (m)
Mass: kilogram (kg)
Time: second (s)
Volume: liter (L)

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8
Q

sig fig rules

A
  • Non-zero digits are always significant.
  • Zeros between non-zero digits are significant.
  • Leading zeros (before non-zero digits) are NOT significant.
  • Trailing zeros after a decimal point are significant.
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9
Q

examples of sig figs

A

0.00560 → 3 significant figures (5, 6, 0).
1200 → 2 significant figures (1, 2).

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10
Q

Solve these
**Addition: **
12.34+0.006+1.2 (Round to the correct number of significant figures.)
**Subtraction: **
100.00−0.567 (Round appropriately.)
**Division: **
125.0÷2.5

A
  • 13.5 BECAUSE round to 2 dp (least precise term is 1.2 with 1 decimal place)
  • 99.433 BECAUSE round to 3 dp (least precise term is 0.567)
  • 50 BECAUSE round to 3 significant figures (least precise input, 2.5, has 2 sig figs
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11
Q
A
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