DIHYBRID INHERITANCE Flashcards

1
Q

Dihybrid inheritance

A
  • inheritance of two unlinked genes

- i,e colour and shape RRYY

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2
Q

dihybrid punnet square

A

ADD PICTURE

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3
Q

dihybrid mendelian ratios

A

9:3:3:1 (unlinked)

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4
Q

what is a dihybrid test cross for?

A
  • to work out whether unknown is heterozygous or homozygous
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5
Q

linkage

A

two genes are on the same chromosome therefore they are inherited together

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6
Q

recombinants (2)

A
  • produced by crossing over during meiosis prophase I
  • genes are swapped producing new linked combinations
  • i.e AB could become aB
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7
Q

how to recognise linkage

A

when it doesn’t follow a mendelian ratio

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8
Q

crossover value

A

(number of recombinants/number of progeny) x 100

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9
Q

what does a chi^2 (x^2) test do? (2)

A
  • it ascertains whether results slightly off of a mendelian ratio are due to chance or biological factors
  • it tests the null hypothesis
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10
Q

null hypothesis

A

there is no significant difference between the observed and expected results, and any deviation is due to chance

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11
Q

Mendelian ratios assume there is no difference in… (3)

A
  • number of different types of gametes
  • probability of each gamete type fusing with another
  • viability of the embryos regardless of genotype
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12
Q

how to draw chi^2 table (ADD NO OF STEPS)

A

ADD PICTURE

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13
Q

degrees of freedom

A
  • in crosses degree of freedom = number of classes - 1

- i.e 4 phenotypes? so 3 degrees of freedom

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14
Q

probability (2)

A
  • use 5% or 0.05

- if predicted results occur 5% or more, any deviation is chance based

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15
Q

critical value

A

found by using degrees of freedom and probability in table

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16
Q

conclusion (if chi^2 > critical value)

A
  • the value of x is > critical value
  • the probability of chance is <5%
  • the null hypothesis is rejected
  • there is a significant difference between the observed and expected results
  • inheritance isn’t mendelian and there must be another biological factor (such as linkage) as it is not due to chance
17
Q

conclusion (if chi^2 < critical value) (5)

A
  • The value of x is < critical value
  • the probability of chance is > 5%
  • the null hypothesis is accepted
  • there is no significant difference between the observed and expected results
  • inheritance is mendelian and any variance is due to chance