Differentiation Flashcards
Limit
the value a function approaches, when its variable tends towards a certain value
df/dx = f’(x) =
lim f(x+h) - f(x) / h
h–>0
Using first principles, find the derivative of f(x) = x^3 - 4x.
f(x+h) = (x+h)^3 - 4(x+h)
= x^3 + 3hx^2 + (3h^2 - 4)x + h^3 - 4h
lim h–> (3x^2 + 3hx + h^2 - 4)
= 3x^2 - 4
d/dx (ax^n) =
anx ^ n-1
For sums of different terms,
differentiate
each term seperately
.
.
For products or quotients,
do not differentiate
simplify first
y = x^4(x^5 - 3x^-2) + 2 differentiate
9x^8 - 6x
To find equations of tangents/normals at a point
use differentiation to find and evaluate the gradient of the curve, then substitute into y - y1 = m(x - x1)
A curve has equation y = x^3 - 5x^2 - x^3/2 + 22
tangent and normal at the point (4, -2)
tangent
y = 5x-22
normal
y = -x/5 - 6/5
A curve has equation y = a/x.
The normal to the curve at x = 3 is parallel to x - 3y + 6 = 0.
Find the value of the constant a.
m = 1/3
gradient is -3
a = 27
rate of change at f’(x) > 0
increasing
rate of change at f’(x) < 0
decreasing
rate of change at f’(x) = 0
stationary
rate of change of the gradient
second derivative
d2y/dx2