Diastereocontrol in Acyclic systems 1 Flashcards

1
Q

Describe molecular orbitals for Pi-bond

A
  1. P-orbital lobes within the antibonding pi* orbital are bent outwards
  2. This has stereoelectronic implication for the chemistry of the C=O bond
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2
Q

What are the stereoelectronic implications of the molecular orbital bending

A
  1. The lowest conformation of acetaldehyde is one in which a C-H bond eclipses the C=O group as this gives the best orbital alignment for two stabilising sigmaC-H–>pi*-O interactions
  2. This hyperconjugative interaction is also part of the reason that ketones are less reactive than aldehydes as there are more of these interactions to stabilise the C=O group
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3
Q

What is the approach trajectory of nucleophiles to C=O bonds

A
  1. Burgi-Duntz angle
  2. 107+-2 Degrees
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4
Q

Why is the Burgi-Duntz angle the approach trajectory

A
  1. Maximises bonding
  2. Minimises antibonding
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5
Q

What is the conformation of an acetaldehyde undergoing nucleophilic attack

A
  1. Not the same as its ground state lowest energy conformation
  2. A staggered reactive conformation is adopted
  3. Enables a sigma* C-H–>pi*C-O LUMO-lowering interaction which makes the C=O bond a better acceptor of electron density
  4. Anti periplanar relationship between nuc and C-H bond lowers LUMO
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6
Q

What model is used to explain addition of nucleophiles to alpha-chiral aldehydes/ketones

A
  1. Felkin-Anh model
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7
Q

What dictates the Felkin-Anh model

A
  1. Alpha-substituents are electronically similar but differentiated by size
  2. TSs are reactant like (early) rather than product-like (late)
  3. Reaction occurs via the most reactive conformation of the carbonyl compound (sigma* orbital perpendicular to C=O bond)
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8
Q

What are the rules of the FA model

A
  1. The largest group is placed perpendicular to C=O to minimise steric interaction with incoming nucleophile- lowers LUMO
  2. Nuc approaches at 107 degrees
  3. Nucleophile approaches antiperiplanar to the C-L bond to give the best stereoelectronic interaction between the sigma-donor (sigmaNu-c) and sigma acceptor (sigma*C-L)
  4. Nuc prefers attack alongside the smaller group S than the medium group M for steric reasons
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9
Q

What happens when an electronegative heteroatom substituents on the alpha-stereocentre

A
  1. For aldehydes/ketones with heteroatom (x) alpha-substituents (e.g. O,N,S,Hal) the most reactive conformation is one where the C-X bond is perpendicular to the C=O group
  2. C-X bonds are generally better sigma-acceptors than C-H or C-C bonds (lower energy sigma*C-X orbitals) and offer greater hyperconjugative stabilisation in the transition state
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10
Q

What elements have the best acceptor ability of sigma bonds

A
  1. Acceptor ability of sigma bonds increases when going to the end of a period and down the group
  2. Enhancement of the acceptor ability of sigma bonds within periods parallels the increase in electronegativity of X
  3. whereas augmentation of acceptor ability in groups is opposite to the changes in electronegativity of X and is a consequence of lowering the energy of sigma*C-X orbitals
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11
Q

What is the Cornforth-Evans model

A
  1. Alternative to FA model based on dipole-dipole interactions
  2. says most reactive conformation is one in which the C=O group and polar C-X bond are opposed in order to minimise dipole-dipole repulsion
  3. In simple cases will lead to same prediction as polar F-A model
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12
Q

What is the cram chelate model

A
  1. Chelation effects can overturn the polar FA model
  2. Cram chelate model used when aldehydes/ketones bear an alpha-heteroatom substituent capable of chelation to a metal ion
  3. Predicts the opposite diastereomer to the polar F-A model
  4. R group is antiperiplanar to Nu
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13
Q

What are common alpha-heteroatom substituent groups that result in chelation

A
  1. Almost always -OR groups
  2. But can occur with other lewis basic moieties (OH,SR,NR2)
  3. OSiR3 tend to chelate very poorly or not at all
  4. Mg2+, Zn2+, Cu2+, Al3+, Ce3+ Ti4+ are all excellent chelators and Li+ as have high charge densities
  5. Na+ and K+ are poor chelators as low charge density
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14
Q

Are syn and anti descriptors product or mechanism dependent

A
  1. Soft descriptors
  2. Depend on how the chemist chooses to define the main carbon chain
  3. Product not mechanism dependent `
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15
Q

What does the partitioning between Cram chelate and polar FA pathways depend on

A
  1. dependent on the O-protecting groups
  2. Also dependent on the solvent and strongly Lewis basic solvents can suppress chelation by competing for the lewis acidic metal
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16
Q

What is examples of solvents which are strongly chelating

A
  1. THF- strongly coordinating to metals so less chelating for molecule
  2. Et2O is not
17
Q

Describe the Frater-seebach alkylation of beta-hydroxyl carbonyl compounds

A
  1. Involves diastereoselective alkylation of chelated dianion
  2. steric effects override torsional effects
  3. Reaction occurs on the opposite face to the Me group - even though TS has small amount of twist-boat character
18
Q

Describe 1,3 induction in C=O additions

A
  1. A stereogenic centre at the beta-position can also strongly influence diastereoselectivity in c=o additions
  2. But only when the stereocentre bears an electronegative substituent -OH or OR
  3. Two general models to describe diastereoselectivity, both predict same diastereomer
19
Q

What are the models to describe diastereoselectivity for addition to beta position

A
  1. Chelation control - half-chair conformation, avoid twist-boat TS
  2. Dipole control- zig-zag conformation of the main chain, dipole minimisation - but difficult so focus on chelation control
20
Q

What dictates what model applies for diastereoselectivity for addition to beta position

A
  1. Nature of lewis acid and identity of O-protecting group dictate if chelation is possible
  2. BF3 is monodentate and incapable of chelation - dipole model more suitable
  3. Steric effects only play a minor role in 1,3 induction
21
Q

What product is produced when an aldehyde reacts with organometallic nucleophile and with ketone and hydride nucleophile

A
  1. 1,3-anti product
  2. 1,3-syn product
22
Q

Describe 1,3 reduction in beta ketone- in narasaka-prasad reduction

A
  1. diastereoselective reduction of beta-hydroxy ketones to syn-1,3-diols
  2. Add Et2BOMe, NaBH4 to beta hydroxy ketone
  3. Thought to occur via a chelate formed upon exchange of the methoxy substituent on boron by the substrate alcohol
  4. Followed by intermolecular delivery of hydride from NaBH4
  5. Formation of chairlike TS
23
Q

What often combines with reduction of 1,3-beta hydroxy ketones to syn-1,3-diols

A
  1. Combination with the aldol reaction
  2. Provide access to 1,3-diol
24
Q

How can the 1,3-anti product of beta-hydroxy ketone reduction be produced

A
  1. Evans-saksena reduction
  2. Uses Me4N+BH(OAc)3- as the reducing agent
  3. Substrate directed reaction
25
Q

What is another method to produce the 1,3-anti product of beta-hydroxy ketone reduction be produced

A
  1. SmI2 as a Lewis acid catalyst
  2. Aldehyde as reducing agent
  3. Can differentiate between the two resulting hydroxyl groups- one of them is selectively protected by the aldehyde in the process