Developing Fuels Flashcards
Standard conditions?
RTP stands for ‘room tempreture and pressure’.
Temp - 298K (25 degrees celsius),
Pressure - 100kpa,
If aq solutions are used, conc must be - 1 mol dm-3
All chemicals must be in standard states - states they would be under standard conditions.
E.g. Carbon must be a solid, hydrogen must be a gas and water must be liquid.
Formula for working out number of moles at RTP?
number of moles = volume in dm3 / 24,
or,
number of moles = volume in cm3 / 24000.
E.g. how many moles are there in 6.0dm3 of oxygen gas at RTP?
6 / 24 = 0.25 mol.
How to work out gas volumes using a balanced equation?
You can work out the amount of gas produced in a reaction using the balanced equation.
This can be done before an experiment, to see how large the apparatus needs to be.
E.g. what volume of gas is produced when 16g of sodium is reacted with excess water at RTP?
Excess water means all the sodium will react.
2Na + 2H2O —> 2NaOH + H2
Ar Na = 23
Moles = mass / ar.
16g / 23 = 0.696
From equation, we know 2 moles of Na produces 1 moles of H2.
So 0.696 / 2 = 0.348 of H2.
So volume of H2 = 0.348 x 24 = 8.35dm3 (use volume in dm3 = moles x 24dm3).
10dm3 of methanol vapour is burned in 12dm3 of oxygen. What volume of each reactant and product will be present at constant temperature and pressure?
2CH3OH + 3O2 + 2CO2 + 4H2O?
2CH3OH + 3O2 + 2CO2 + 4H2O
From the equation, we know that 2 moles of methanol react completely with 3 moles of oxygen.
This means that 10dm3 of methanol reacts completely with (10 / 2 = 5. 5 x 3 = 15dm3 of oxygen.
Methanol is therefore in excess in the reactants.
12dm3 of oxygen reacts completely with (12 / 3 = 4. 4 x 2 = 8dm3) of methanol, so 2dm3 of methanol is left over.
2 moles of methanol produces 2 moles of CO2 and 4 moles of water vapour. Therefore, 8dm3 of methanol will produce (8 / 2 = 4. 4 x 2 = 8dm3) of CO2 and (8/2 = 4. 4 x 4= 16dm3) of water vapour.
So once the reaction is complete, there will be 2dm3 of methanol, no oxygen, 8dm3 of carbon dioxide and 16dm3 of water vapour.
Ideal gas equation?
This is used to find the number of moles in a certain volume at any temperature and pressure (not just RTP).
pV = nRT.
p - pressure (Pa) V - volume (m3) n - number of moles R - 8.314 (J K-1 mol - 1) (gas constant is on data sheet) T - temperature (K).
Conversions?
K = Celsius + 273
1cm3 = 1x10-6 m3
1dm3 = 1 x10-3 m3
Jmol-1 / 1000 = KJmol-1
1cm3 = 1g
How to use a gas syringe?
Attach gas syringe to the opening of a reaction vessel (usually a bung in a conical flask(.
This will show total volume of gas produced.
If more than one gas is given off, it won’t show how much of each there is. So you can work this out using balanced equation like on previous flashcard.
Really vigorous reactions can blow the plunger out so be careful.
Enthalpy change?
When chemical reactions happen, some bonds are broken and some are made. This causes a change in energy.
Enthalpy change (🔺H) is the heat energy transferred in a reaction at a constant pressure. Units of delta H are KJ mol-1.
You can find the enthalpy change through experiments or in data books (usually under standard conditions).
You write 🔺H with a little circle next to it to show enthalpy change under standard conditions.
Enthalpy definition?
Heat energy stored in a chemical system (chemical potential energy).
It can’t be measured directly.
However, we can measure energy absorbed/released to surroundings.
Exothermic and endothermic?
Exothermic - give out energy so the 🔺H is negative.
Oxidation is usually exothermic (like combustion of methane and oxidation of carbohydrates).
Endothermic - take in energy so the 🔺H is positive.
The thermal decomposition of calcium carbonate is endothermic and the main reactions of photosynthesis are SLO endothermic.
Calculating enthalpy changes?
You need energy to break bonds - this is endothermic.
Energy is released when bonds are made - this is exothermic.
The enthalpy chnage is the overall effect of these two. If you need more energy to break bonds than I’d released when bonds are made, the 🔺H is positive.
Stronger bonds have higher bond enthalpies.
Enthalpy change of reaction = totally energy absorbed to break bonds - total energy released by making bonds.
Average bond enthalpies are published in data books to help calculate them. You might be asked to work enthalpy out by getting a small chart with the bonds and then the average bond enthalpies and a balanced equation.
Calculate the overall enthalpy change for this reaction: N2 + 3H2 —> 2NH3.
N—-N = 945kJ mol-1 H-H = 436KJ mol-1 H-N = 391KJ mol-1
The amount of bonds broken is the reactants.
So 1 N—-N bond is broken = 945
3 H-H bonds are broken = 1308.
Add them = 2253.
Then the amount of bonds formed is the products.
So 6 N-H bonds are formed = 2346.
2253 - 2346 = -93 so the reactions is exothermic.
Average bond enthalpies are not exact?
Water has two O-H bonds but the amount of energy needed to break each of them are different.
Average bond enthalpies are actually the energy needed to break one mole of bonds in the gas phase, average over many different compounds.
How is bond enthalpy related to bond length?
In covalent molecules, the positive nuclei are attracted to the shared electrons.
There isn’t just an attraction between the nuclei and the shared electrons. The two positively charged nuclei also repel each other, as do the electrons.
The distance between the two nuclei is the distance where the attractive and repulsive forces balance eachother.
The stronger the attraction between the atoms, the higher the bond enthalpy and the shorter the bond length. If there’s more attraction, the nuclei are pulled closer.
So, double bonds have a greater enthalpy and shorter length. Triple bonds have an even greater enthalpy and shorter length.
Enthalpy profile diagram?
Reactants have high enthalpy and products have a lower enthalpy = enthalpy change is exothermic. Heat is lost to surroundings.
Reactants have low enthalpy and products have a higher enthalpy = enthalpy change is endothermic. Heat is lost from surroundings.
🔺H is the arrow from the products to the reactants.
Activation energy (Ea) is the little bump on the graph. This is required to break the bonds in the reactants and so the reaction can proceed. E.g. a match doesn’t strike on its own.
The less enthalpy a substance has, the more stable it is.
Determining the 🔺H of a reaction using calorimetry?
Insulated beaker (polystyrene cup with lid on and thermometer in).
We measure the temperature of the solution inside the cup.
E.g. Mg + CuSO4 —> MgSO4 + Cu
The Mg is in excess because we are measuring the temperature chnage of the solution (CuSO4) and we need to make sure the CuSO4 is fully reacted.
Record the cm3 and concentration of the solution your measuring the temperature change of.
Work out moles (m = c x v).
Record the initial temperature of the solution.
Add the Mg in excess.
Record the highest temperature produced.
Work out the change in temperature.
Use calculation: q = mc🔺T
The m should be 100, I think.
Then rearrange the equation.
🔺T = -q / mol (-q is used for exothermic and q is used for endothermic).
Finding the enthalpy change of a reaction with two solutions?
In a neutralisation reaction, you will be given 2 aq solutions to react.
Record concentrations and volumes of both the solutions.
Work out moles.
Use a closed, polystyrene cup and thermometer. Closed system.
Record the initial temperatures of both the solutions. Record maximum temperature when you react the solutions together.
Record the change in temperature.
Use calculation: q = mc🔺T
Mass of solution should be combined mass of both the solutions (50).
Then rearrange the equation: 🔺H = -q / mol (-q is used for exothermic and q is endothermic).
Determining the enthalpy change of combustion using calorimetry?
Insulated beaker (metal can or glass beaker). There should be a lid on.
Inside should be a known vol of water. We use density to calculate mass of the water.
Record temperature of water.
Record mass of the thing being burnt. Burn the thing under the metal can/glass beaker. The mass of the water will drop because it’s being evaporated.
Record new mass of thing being burnt and temperature of water.
Record change in temperature and change in mass of the thing being burnt.
Use calculation: q = mc🔺T
M is just the amount of grams.
Then use 🔺T = -q/q / mol.