Deloatch Training (IICRC WRT) Study Deck Flashcards
Prepare for the IICRC Water Restoration Technician (WRT) Certification Exam. For the full class, visit https://www.deloatchtraining.com/ With special thanks to Bruce and Joanna Deloatch
Third party experts are commonly referred to as Indoor Environmental
Professionals, or ________.
Chapter 3
IEP’s
Restorers must maintain their safety certified equipment properly. This includes
replacing ___________ that are damaged, replacing damaged inlet and outlet
__________, and checking for ______________ electrical plugs.
Chapter 8
cords
screens
grounded
If a structure cannot be warmed to a temperature where LGRs would be effective,
the most efficient type of dehumidifier to use would be: refrigerant / desiccant
Chapter 8
Dessicant
Whenever carpet must be disengaged from the tackless strip, a ___________
_________ and carpet awl must be used.
Chapter 4
- Knee Kicker
Class 1 water intrusions involve the ________ amount of water absorption, with
less than ____% of the area surfaces being wet porous materials.
Chapter 8
least
5%
When carpet delamination (the loss of integrity in the adhesives used to laminate
the _____________________ and ________________________ backings) has occurred,
further damage is very likely. For this reason, when extensive carpet delamination
is discovered, technicians must call it to the attention of all materially interested
parties, document the condition and suggest __________________.
Chapter 3
- Primary
- Secondary
- Replacement
Which of these surface temperatures would promote the most rapid evaporation?
a. 60 degrees
b. 70 degrees
c. 80 degrees
Chapter 7
C. 80 Degrees
When water intrusion results from a grossly unsanitary source or carries
___________________ (disease causing) agents, it is said to be Category 3.
Chapter 3
Pathogenic
Remove the vinyl (flooring) and discard it if the _____________________ is
saturated and/or damaged; vinyl is a vapor barrier and the time required to dry underlayment will be dramatically reduced if the vinyl is removed.
Chapter 9
Sub Floor
Wet materials present in a Class 4 water intrusion require a ________ time to dry.
Water has saturated deeply into the materials and is held or trapped as bound
water. Low evaporation materials have ______________ absorption of water.
Chapter 8
longer
Significant
If the rate of evaporation is allowed to exceed the rate of dehumidification,
____________________ ________________ can occur.
Chapter 8
Secondary Damage
__________________occurs when liquid changes to a vapor. Occurs as energy is
increased.
Chapter 7
Evaporation
Describe a Closed Drying System
Chapter 7
Using mechanical dehumidification only
Use your Psychrometric Chart to complete the following calculation:
80°F at 60% RH = _____________________ GPP
Chapter 7
92
When using low grain refrigerant (LGR) dehumidifiers that remove 72 pints at
AHAM test conditions, the number installed initially on a Class 2 water loss with 18,000 cubic ft. is:
Refrigerant Formula (always divide)
1. Cubic Footage ÷ Chart Factor = Total PPD (Pints Per Day) Removal Recommendation
2. Total PPD Removal Recommendation ÷ Dehumidifier AHAM Rating = # of Dehumidifiers
Refrigerant Formula (always divide)
Chapter 8
5 LGR Dehumidifiers
18000/50=360/72=5
Restorers will know the drying job is dry and done when moisture meters verify that the structure has reached the ___________ _________.
Chapter 10
Drying Goals
The ultimate goal is to find the “edge” of water migration, which moves in a threedimensional path throughout the structure. This is accomplished across carpeted
surfaces using a ______________ _______________, and across most hard surfaces
using a ____________________________ (non-penetrating) moisture meter.
Chapter 3
- Moisture Sensor
- Non Invaisive
- Evaporation will increase when
Chapter 7
- Wet materials are made warmer
- Drier air is used
- Air is moved rapidy across the wet surface
____________________ ______________________ is defined as the amount of
moisture contained in an air sample, as compared to the maximum amount the air
could hold at that temperature.
Chapter 7
Relative Humidity
Losses where regulated or hazardous materials have contaminated the structure
do not change the _______________________ of water.
Chapter 3
Category
Hygroscopic materials gain and lose moisture continually in an effort to
___________________ with the water content in the surrounding air mass. The
more hygroscopic the material, the faster it will collect water vapor, and the easier
it will suffer ________________________ damage.
Chapter 3
- Equalize
- Secondary
Every cubic foot of standing water present in a structure contains __________
gallons (28.3 liters), and each gallon (3.8 liters) of water weighs 8.34 pounds (3.8
kg).
Chapter 4
7.48
The contract clearly states the agreement between the building owner and the
restoration contractor. The form specifies who is responsible for payment and
should be signed _________ work begins.
Chapter 3
Before
Dehumidification reduces the _______________________ content of the air.
Chapter 8
moisture
What does a Sterilizer do?
Chapter 5
Kills all organisms and spores
What does a Disinfectant do?
Chapter 5
Lowers Organisms to safe Level
Most antimicrobials require that the area of application be vacated by ___________
and pets during application and for a period of time after application.
Chapter 5
Occupants
___________________ is the temperature at which air becomes saturated with
moisture and can hold no more water vapor.
Chapter 7
Dew Point
If a structure had affected air at 85 F at 65% RH, the most efficient type of
dehumidifier to use would be a (choose one): refrigerant / desiccant
Chapter 8
Refrigerant
Airflow in the wall cavity increases the rate of ____________________ and allows
the wall to dry from both inside and out
Chapter 9
Evaporation
The numerical value from a moisture meter can be documented and used to
monitor progress. For this reason, the amount of moisture absorbed by semiporous structural materials is measured most accurately with a moisture
___________, not a moisture sensor.
Chapter 6
Meter
During the drying process, all of the gypsum’s original strength is restored. In fact, the dried gypsum will normally be slightly _________________ than before wetting.
Chapter 9
stronger
The ability for water vapor to diffuse through a solid material is expressed as the material’s __________________.
Chapter 7
Permeance
Federal regulations apply to handling or disturbing of _________ based paint and
asbestos.
Chapter 3
Lead
Water vapor pressure is the force that drives higher concentrations of humidity from one space to another in an attempt to seek _________________ with lower concentrations of water vapor.
Chapter 7
Equalibrium
What is the name of this drying system?
- Outside Humidity is Lower
- Outside Temperature is NOT above 70 Degrees Fahrenheit
Chapter 7
Combo
If the carpet is to be re-installed, technicians should avoid cutting carpet seams
unless it is absolutely___________________.
Chapter 4
Necesary
_________________ represents the “was-wood” material with the least engineering, and thus the most natural fiber bonding. It is ________________ to swelling and delamination due to its wood veneer assemblies which are glued under extreme pressure.
Chapter 9
- Plywood
- Resistant
Cupping will generally be the first indication of abnormal moisture levels in
hardwood flooring as the ________________ and sides of the board absorb moisture
Chapter 9
Bottom
Establishing a _________ __________ is the best way to set restorative drying
goals.
Chapter 6
Dry Standard
. __________________occurs when vapor changes to a liquid. Occurs as energy is
removed.
Chapter 7
Condensation
As with any contaminant, mold should be removed or contained before any air movers are placed in the structure. Blowing air can spread mold spores from the _____________________ area to the ________________ rooms.
Chapter 10
- Affected
- Unaffected
To evaluate the progress of structural drying projects, restorers should measure:
- Moisture in ____________ being dried (moisture content readings)
- _____ being used to dry affected materials (psychrometric readings)
- _____ produced by mechanical systems (dehumidifiers)
Chapter 6
- Materials
- Air
- Air
Which drying system is best?
Outside
95 Degrees / 45% RH
Affected Area
80 Degrees / 50% RH
Chapter 7
Closed
Outside 92 GPP, Inside 76 GPP, More Humidity Outside
The best way to prevent odors and retard microbial growth in a wet structure is to ensure that all materials are dried ____________ and ____________________.
Chapter 10
- Thoroughly
- Rapidly
Install ____ air mover for each ___________ area before you calculate additional air
movers for the square feet of surfaces and for room offsets.
Chapter 8
1
affected
Because of their non-invasive nature and quick surveying capabilities, noninvasive meters are the most effective tools for locating abnormal moisture behind
and beneath finishing materials such as ___________ _______________ and resilient
___________ floor coverings.
Chapter 6
- Ceramic Tile
- Vinyl
Partial floating of carpet can be a way to achieve drying of all surfaces
simultaneously and allows _____________ dry air to have more contact with wet
flooring.
Chapter 9
Warm
Wet particle board would normally be ________________________ and replaced.
Chapter 9
Removed
Plastic Laminate Flooring is made of MDF and has a resin saturated appearance layer. Normally _________________ in water restoration due to its construction and installation components.
Chapter 9
removed
Vapor pressure, dew point and humidity ratio (GPP) are ___________ ___________
to each other. When one increases, the other two _____________. When one
decreases, the other two _____________.
Chapter 7
- Directly Related
- Decrease
- Increase
When using desiccant dehumidification in a Class 4 water loss in a 2,000 square ft. structure with a 9-foot ceiling height, the initial CFM required is:
Desiccant Formula (divide by 60 for base CFM. Then multiply by ACH)
1. Cubic Footage × Chart Factor (ACH) ÷ 60 = Total CFM Recommendation
2. Total CFM Recommendation ÷ Dehumidifier CFM Rating = # of Dehumidifiers
Chapter 8
900 CFM
20009=180003=54000/60=900 CFM
When using conventional refrigerant dehumidifiers that remove 125 pints at
AHAM test conditions, the number installed initially on a Class 1 water loss with 25,000 cubic ft. is:
Refrigerant Formula (always divide)
1. Cubic Footage ÷ Chart Factor = Total PPD (Pints Per Day) Removal Recommendation
2. Total PPD Removal Recommendation ÷ Dehumidifier AHAM Rating = # of Dehumidifiers
Chapter 8
2 Conventional Dehumidifiers
25000/100=250/125=2
When using conventional refrigerant dehumidifiers in a “Class 2” water loss
containing 15,000 cubic ft., the initial AHAM-rated capacity required is:
Refrigerant Formula (always divide)
1. Cubic Footage ÷ Chart Factor = Total PPD (Pints Per Day) Removal Recommendation
2. Total PPD Removal Recommendation ÷ Dehumidifier AHAM Rating = # of Dehumidifiers
Chapter 8
375 PPD
(15000/40=375)
Which of the two conditions above has the lowest vapor pressure?
a. 80°F at 60% RH = 92 GPP, .615 Vapor Pressure
b. 53°F at 80% RH = 48 GPP, .315 Vapor Pressure
Chapter 7
B. .315
Use your Psychrometric Chart to complete the following calculation:
53°F at 80% RH = _____________________ GPP
Chapter 7
48
What is the temperature in degrees Fahrenheit if the humidity ratio is
70 GPP, and the relative humidity is 60%?
Chapter 7
72 Degrees
Which drying system is best?
Outside
40 Degrees / 70% RH
Affected Area
75 Degrees / 40% RH
Chapter 7
Closed/Combo
Outside 25 GPP, Inside 51GPP, Lower than 70 Degrees. Could Burp the space to lower humidity
A room with water damage measures 16 feet × 12 feet.
Water has wetted all of the flooring in the room.
* The flooring is wet in an offset measuring
10 feet × 4 feet.
* Water is wicking up the walls less than 2
feet except for Wall A, measuring
12 feet × 8 feet.
* Water came down from above to wet all of
Wall A but not the ceiling.
The number of air movers to install will be:
________ for the room.
________ for the floors.
________ for the walls.
________ for the offset.
The total number of air movers required is ____ – ____.
Chapter 8
7-8
* Room: 1
* Floor: 1 for every 50-70 Sqft of affected wet floor (1612=192+(104)=232
232/70 = 3.314 (min) Round up to 4
232/50 = 4.65 (max) Round up to 5
* One airmover for every 10-150 Sqft of wet ceiling and Wall areas above 24” (less than 100 sqft add 1) (8-2)=6*12=72/100=.72 Round up to 1
* add one for every wall inset and offset greater than 18” 1
Which drying system is best?
Outside
75 Degrees / 20% RH
Affected Area
70 Degrees / 60% RH
Chapter 7
Open/Closed/Combo
Outside 26 GPP, Inside 65 GPP, Above 70 Degrees AND Lower Humidity Could use Open if weather and Security not an issue. Could also Burp the space to lower humidity.
What is the surface temperature at which condensation would become a
risk for air which is 80°F at 60%? _______________________
Chapter 7
64-65 Degrees
