Dc and Ac Circuites Flashcards
Direct current
Comes out of battery
Magnitude stay constant over time
I=q/t
Electromotive force (EMF)
E
(voltage) drives current
Emf source-battery
Allow charges to flow from one end to another
Kitchhoff’s loop rule
sum of V across a closed circuit has to = sum of V gains across circuit
V drops across all of R in the circuit will = V gained by the battery
Conservation of E
Resistance of conductor
R
Measure of particular conductor’s resistance to current flow
R - device used to intentionally cause V drop in circuit
Resistivity of material
Ro
Measure of its resistance to I flow
If material has higher resistivity, then applying given potential difference across it will produce lower I
Resistance of R depends on resistivity of material
R=ro*L/A, L- length of R, A- cross- sectional area through which I flow.
Ohm’s law
V across R - proportional to I passing through it
V=I*R
R- proportionality constant
Units of R - ohm= 1 v/ a
Resistors in series
When 2/> R in series, I has no choice but to pass through all of them.
R total or equivalent = R1+ R2…
Resistors in parallel
When 2/> R in parallel configuration, C is split btwn different parts, V across each path - same.
1/Req=1/R1+1/R2….
Internal resistance
R of battery
Contributes to R total
Usually = 0
When not 0, it will reduce effective potential of battery
When battery has internal r, terminal V of battery< battery EMF: V= emf - Ir
I= Emf/(R+r)
Capacitor
Two conductors with V btwn them, in short distance apart, used to store electrical E.
When 2 in charged conductors are connected to opposite terminals of battery, equal amounts of + and - charge move to each of conductorsrs
Capacitance
C
amount of charge that C can hold depends on C
C= Q/V
SI units Farad: 1 F= 1C/V
E stored by capacitor
PE
When battery is hooked to uncharged C, it must do work in charging C.
electrical PE of C increases as W done on it
PE stored in fully charged C, U= 1/2CV^2
Parallel plate capacitor
Consists of 2 flat conducting plates, with surface area A, separated by distance d.
Capacitors in series
When 2/> in series, each C has to store same amount of charge
V=Q/Ceq
Each series C individually stores same amount of charge: V=V1+V2=Q/C1+Q/C2
1/Ceq=1/C1+1/C2
Capacitors in parallel
V drops across C in parallel are same
Total charge stored divided btwn 2 C in parallel
Q=VC1+VC2=V(C1+C2)
Ceq=C1+C2