Day 2 Flashcards

1
Q

Mass fraction

A

Mass solute/mass sol’n

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2
Q

Pressure

A

Pabs = Patm + Pg
Pabs = Patm - Pvac
P = (rho)(g)(h)
P= F/A

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3
Q

Specific volume

A

1/rho
v/m

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4
Q

%H2O Dry Basis

A

x H2O wet/ 1- x H2O wet

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5
Q

%H2O Wet Basis

A

x dry / x dry + 1

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6
Q

OMB and CMB of Evap

A

Omb: F = L + V
Cmb: Fxf = Lxl

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7
Q

Omb and cmb of crystallization

A

Omb: F = V + C + L
Cmb: Fxf = Cxc + Lxl
Solute bal: F(1-xf) = C(1-xc) + L (1-xl)

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8
Q

Xc and Xl of crystallization

A

Xc = 1 or = MM anhydrous / MM crystal
Xl = solubility = g solute/ g solute + 100

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9
Q

% yield of crystals

A

Cxc/ Fxf x100

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10
Q

% xss

A

xs/theo x 100

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11
Q

O2 supply

A

supp = theo + xss
supp = theo (1+%xss)

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12
Q

O2 Theo

A

C + H/4 + S - O2

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13
Q

O2 Free

A

O2 free = O2 xss + CO/2 + H2/2

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14
Q

Proximate analysis

A

M VCM FC Ash

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15
Q

Modified Analysis

A

M Ctotal netH N S CW Ash

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16
Q

Calderwoon eqn

A

Ctotal = 5.88 + 2.206 (CV-0.094S) + 0.0053 (80-100 VCM/FC) ^1.55

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17
Q

Dulongs

A

CV = 0.338C + 1.44 net H + 0.094S

net H = H - O/8

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18
Q

Ultimate analysis

A

Ctotal
H = net H + (M+CW) (2/18)
O = (M+CW) (16/18)
N
Ash
S

19
Q

Analysis @ VCM

A

C,VCM = Ctotal - FC
N
S
CW
Net H

20
Q

CV, Fuel

A

CV, Fuel = 33.8 MJ/kg + CV, VCM

21
Q

Raoult’s Law

A

Pi = Pi°Xi
Pt = summation Pi°(Xi)

Psoln = Psolvent (Xsolvent)

22
Q

Yi

A

Pi⁰Xi / Pt

23
Q

Distribution Coefficient

A

Ki = Yi/Xi

Fig. 13-9

24
Q

Relative Volatility

A

αAB = Pa⁰/Pb⁰

     = Ya(1-Xa) 
         ———
         Xa(1-Ya)
25
Q

Batch Distillation

A

ln A1 αAB ln B1
— = —
A2 B2

At feed: A1 B1
At residue: A2 B2
At distillate: Da Db

26
Q

Flash/Equilibrium Distillation

A

y= -(1-f)(x) Xf
——— + ——
f f

f = fraction vaporized
m = -(1-f)/f

Use αAB to get x or y

27
Q

Steam Distillation

A

ns/nb = (Pt-Pb⁰)/Pb⁰

28
Q

Simple Continuous Distillation

A

αAB = Da Bb
—— × ——-
Ba Db

29
Q

Slope of q line

A

M = q/ q-1

30
Q

q line distillation with reflux

A

q = 1 + Cp(Tb-Tf)
————
λv

31
Q

Reflux Ratio

A

R = L/D

32
Q

Enriching/ Rectifying Line

A

Xb

b = Xd / R+1

33
Q

Feed Line

A

Xf

34
Q

Stripping Section

A

V = L+D

35
Q

Minimum Reflux Ratio

A

Infinite stages, D»>L

R,min Xd - y’
——— = ———
R,min +1 Xd - x’

36
Q

Total Reflux Ratio

A

Infinite Reflux, L»>D

               log  Xd (1-Xb)
                      ————
                       Xb (1-Xd) Nmin =    ————————
                     log αAB
37
Q

Retentions in Leaching

A

M soln M solvent
——— or —————
M inert M inert

x = y = M solute (or solvent)
—————
M sol’n

38
Q

N theo leaching

A

X1 - Y2
log —————
Xn - Yn+1
N theo = ———————— + 1
X1 - Xn
log —————
Y2 - Yn+1

39
Q

Y2 in N theo leaching

A

L
Y2= — (X1 - Xn) + Yn+1
V

40
Q

N actual = N theo / % efficiency

A
41
Q

Partition Ratio / Kd value

A

Kd = CE/CR

42
Q

Solute on Raffinate at nth stage/ remained at liquid phase

A

( B ) ^n
A,Rn = A,F ( ———— )
( Kd(S) + B )

43
Q

Total mass transferred to mass transferred by molecular diffusion

A

Sherwood Number

44
Q

Ratio of the molecular momentum diffusion to the molecular mass diffusivity

A

Schmidt Number