D1 Solubility Flashcards

1
Q

what can a small change in molecular structure have an effect on? what can these small changes be? give examples

A
  • solubility
  • eg. addition / removal of a functional group
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2
Q

which is more soluble in water: benzene or phenol?

A

phenol is > 100 times more soluble

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3
Q

what structural feature of molecules can play a part in determining solubility?

A

molecular shape (isomerism)

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4
Q

how does isomerism affect solubility?

A
  • unsymmetrical, non-linear molecules cannot pack together as well
  • water can then get in and disperse these molecules
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5
Q

explain the changes in solubility in the image

A

solubility increases in propyl hydroxybenzoate as hydroxyl group is moved from the para to the meta to the ortho position

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6
Q

solute substituents alter solubility. state 2 reasons why solubility changes happen

A
  • solute-solute (I.e. intermolecular) interactions change
  • solute-solvent interactions change
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7
Q

what does ‘like dissolves like’ mean?

A
  • water is a good solvent for polar solutes (eg. sugars, electrolytes)
  • liquid paraffin is a good solvent for many water-insoluble, organic compounds
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8
Q

3 examples of polar solvents

A

water
methanol
acetic acid

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9
Q

describe solvents in terms of relative permittivity

A
  • polar solvents have a high relative permittivity (formerly known as the dielectric constant)
  • non-polar solvents have a much lower relative permittivity
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10
Q

describe three actions of polar solvents

A
  • dissolve ionic solutes by reducing the force of attraction between oppositely charged ions in crystalline solids (eg. sodium bicarbonate)
  • can break covalent bonds
  • can solvate molecules and ions (I.e. drug salts) through dipole-dipole forces
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11
Q

in the image, the Na+ ion should be in between the 4 water dipoles. explain the rest of the image

A
  • water is considered to be a dipole which allows it to associate with he positive sodium ions and negative negative N in the ring
  • hydrogen bonding is also particularly important
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12
Q

how can drug structure be altered? describe the example of ranitidine

A
  • through salt formation
  • ranitidine (free base) has a low aqueous solubility, unstable to light and has a sulphurous odour
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13
Q

if ranitidine reacts with HCl, what is formed? explain its solubility

A
  • the salt ranitidine HCl
  • odourless, stable and has a great aqueous solubility
  • ranitidine HCl will ionise and hence has a greater solubility
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14
Q

give 4 examples of semi-polar solvents

A

acetone
methanol
ethanol
other alcohols

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15
Q

what can semi-polar solvents dissolve?

A

polar and non-polar substances

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16
Q

what can semi-polar solvents induce?

A
  • a degree of polarity in non-polar solvent molecules
  • eg. benzene (which is soluble in ethanol)
17
Q

3 examples of non-polar solvents

A

hexane
pentane
oils and fats

18
Q

why can non-polar solvents not dissolve ionic or polar solutes?

A
  • low dielectric constant
  • lack of H-bonding groups (due to no polarity or loosely bound hydrogens)
19
Q

what can / can’t non-polar solvents do?

A
  • can’t dissolve ionic or polar solutes
  • can dissolve non-polar compounds
  • unable to break covalent bonds
20
Q

list some solvents in order of decreasing polarity

A

water
glycols
methanol, ethanol
aldehydes, ketones
hexane, benzene
mineral oil

21
Q

list some solutes in order of decreasing aqueous solubility

A

inorganic salts, organic salts
sugars, tannins
castor oil, waxes
weak electrolytes, phenols, alkaloids
liquid paraffin, fixed oils

22
Q

explain the relationship between pH and ionisation

A
  • the solubility of weak acids and bases is influenced by pH
  • by modifying the pH we can alter the solubility of a drug
  • a pH change could improve solubility of lead to precipitation
23
Q

weak acids and bases only ionise to an equilibrium. give an example of a molecule that would fully ionise and why

A
  • other molecules only ionise to equilibrium because they are weak electrolytes
  • H-F would fully ionise as it is a strong electrolyte
24
Q

explain this graph showing the relationship between ionisation and pH

A
  • pKa is pH at which electrolyte is 50% ionised and 50% unionised
  • basic drug most ionised in acidic pH (received proton) meaning it is most stable in acidic pH
  • if a basic compound is put into a basic environment, it can’t receive protons due to the high pH
  • acidic drugs are the opposite
25
Q

describe the general 1 and 2 pH unit rules in terms of acidic drug ionisations

A
  • at 1 pH unit below the pKa, you will only get 10% ionisation for acidic drugs
  • 2 pH units down, 0-1% ionisation
  • at 1 pH unit up from the pKa pH, 90% of acidic drug is ionised
  • 2 units up, 99-100% ionisation

(opposite for basic drugs)

26
Q

4 examples of weakly acidic drugs

A

phenobarbital (phenobarbitone)
phenytoin
warfarin
NSAIDs

27
Q

what is the Henderson-Hasselbalch equation for weak acids?

28
Q

from the Henderson-Hasselbalch equation for weak acids, what equation is derived for finding the pH at which a drug will start to precipitate?

29
Q

why is the S component of this equation important?

A

because the precipitation of drugs in dosage forms, particularly parenteral, is problematic

30
Q

2 examples of weakly basic drugs

A

ranitidine
cimetidine

31
Q

what condition will weakly basic drugs be in if they are ionised species?

A

hydrated and more soluble

32
Q

what is the Henderson-Hasselbalch equation for weak bases?

33
Q

what solubility equation for basic drugs can be derived from the Henderson-Hasselbalch equation?

34
Q

2 examples of amphoteric drugs

A

oxytetracycline
nitrazepam

35
Q

describe amphoteric drugs

A
  • contain both acidic and basic groups so these drugs will have 2 or more pKa values
  • will be ionised at all pH values
36
Q

what is the isoelectric point and its formula?

A
  • the pH at which the drug carries no net electric charge
  • there is equal dissociation of an acidic and basic group
37
Q

which equations should be used to calculate solubility of amphoteric drugs?

A
  • amphoteric drugs are least soluble at the isoelectric point (no net charge)
  • at pH values below the isoelectric point, use the ‘basic drugs’ equation
  • at pH values above the isoelectric point, use the ‘acidic drugs’ equation