current electricity Flashcards
the phase between drift velocity/steady current and electric fiel or potential
pi
180 degrees
Ohm’s law can be applied to
- A. A.C
- B. D.C
both
The specific resistance of a conductor increases with:
Increase in temperature
Because specific resistance is independent of dimensions of a wire.
The resistance of a wire is 11 Ohm. Its length is increased by 10% stretching. The new resistance will be
2n + n2/100 ; n=10%
210% + (1010/100)
20 + 1 = 21 %
11 + 0.21 -> 11.2
The slope of current-voltage graph gives us:
Conductance
1/R
The deviation of I-V graph from the straight line is due to
increase in temp and increase in R
what is the practical unit of power
horse power
what is the cgs unit of power
Erf sec-1
Under what condition is the e.m.f. of a cell equal to its terminal voltage?
when no current is drawn from cell
The potential difference between the terminals of a battery will equal the emf of the battery when there is no current in the battery. At this time, the potential drop across the internal resistance is zero. This only happens when there is no load placed on the battery that includes measuring the potential difference with a voltmeter. The terminal voltage will exceed the emf of the battery when current is driven backward through the battery, in at its positive terminal and out at its negative terminal.
Heat produced by current I in the wire of resistance R is?
Power = I2R. To convert power to energy we need to multiply it with time. So heat produced (energy) = I2Rt.
Two electric bulbs rated P1 watt V volts, and P2 watt V volts are connected in series and applied across V volts. The total power will be
Power will be (p1 + p2) watt when connected in parallel and P1P2 / (P1 + P2) when connected in series.
Increase in the temperature for a substance results in?
Resistance may increase or decrease with the increase in temperature. For conductors it increase and for semi-conductors and insulators it decreases.
The potential difference between the terminals of battery in open circuit is 2.2 V. When it is connected across a resistance of 5.0 ohm, the potential falls to 1.8 V. What is the current of the battery?
when you draw current from a battery, the terminal voltage decreases. For example: when you start your car with the headlights on, they dim while you’re cranking the engine. This is why the model for a battery is an ideal voltage source (voltage constant regardless of output current) in series with the “internal resistance Ri “. Thus, the “open circuit voltage = 2.2V is the value of the ideal voltage source upstream from Ri. When you connect 5Ω across the terminals and read 1.8V you know the current in the 5Ω is
I = V/R = 1.8V/5Ω = 0.36A
Therefore that 0.36A Ri must be the cause of the voltage drop from 2.2V to 1.8V
=2.2-1.8 = 0.4V
0.4V = 0.36 × Ri
Ri = 0.4/0.36 = 40/36 = 10/9 Ω = 1.11111…..Ω
For a metallic wire, the ratio of voltage to corresponding current is?
For a metallic wire with increase in temperature the resistance of the wire increases hence the ratio of voltage to corresponding current increases with rise in temperature
E is EMF of a battery. What will be the potential drop across terminals an external resistance R = r (internal resistance) is connected across it?
E = Ir + Ir
of r = R
E = 2IR
E = 2V
V = E/2