correcting ametropia Flashcards
Bring object from infinity to the fat point
myopia correction
Minus lens
Virtual image to the left of the lens
Positive lens
Converges beam
Image on the right
Real image
Bring object from infinity to the far point
Hyperopia correction
To function as correcting lens….
The lens secondary focal point F’ coincides with the far point of the eye
To correct myopia
-decrease the optical power and thus we use a diverging minus lens
To correct hyperopia
-increase optical power, and this we use a converging, positive lens
Because the spectacles are not in contact with the eye, what is involved
Vergence
The unit of vergence is
Diopters
What is the refractive index of the eye?
1.336
Are F and F’ the same?
No they are different because of different RI
How do you find vergence in a medium other than air
n/l
The vergence L of a ray bundle is
- the wavefront curvature
- the reciprocal of the distance L required to converge to a point
- for a collimated ray bundle, vergence is 0
- for propagation to the right, if the bundle converges, vergence is positive, while if the beam diverges, negative
The required power of a lens to produce the SAME optical effect at a different location
Effective (downstream) optical power
Which needs to have more power, spectacles far away from the eye, or one that is closer?
One that is closer