Core Practical 1 Flashcards

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1
Q

what is this practical about

A

measuring the acceleration of a free falling object

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2
Q

what are the two equations that will allow us to calculate the acceleration due to gravity

A
  • s = (at^2 / 2) + ut

- v^2 = u^2 + 2as

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3
Q

if u = 0ms-1 and acceleration = gravity, what would those two equations become

A
  • s = (gt^2 / 2) + 0

- v^2 = 0 + 2gs

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4
Q

what would s be more accurately called in this practical and how would the formulas be rewritten

A
  • it would be height (h)
  • h = gt^2 / 2
  • v^2 = 2gh
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5
Q

in method 1 what is the ball bearing held up by and at what height

A
  • it is held up by an electromagnet

- at height h

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6
Q

what happens when the switch is thrown

A
  • the circuit is broken

- so the electromagnet stops working and the ball begins to fall

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7
Q

what begins the instant the circuit is broken

A

the stopwatch in the circuit starts timing

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8
Q

what does the ball bearing fall into eventually

A

the trap door

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9
Q

what happens when the ball falls on the trap door

A
  • the lower circuit is broken

- which ten stops the timer

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10
Q

what is h measured with

A

a meter ruler

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11
Q

why is the timing repeated several times

A
  • so that an average of t can be calculated

- with a range on uncertainty if need be

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12
Q

what variable would you be changing in order to get an array of results when repeating the experiment even more and why

A
  • the height

- so you can draw a graph of t^2 against h

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13
Q

how would you find the gradient of the line

A
  • h = gt^2 / 2
  • rearrange for t^ to give 2h / g
  • so the gradient will bee 2 / g
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14
Q

what is the concept of method 2 simply put

A

a cylinder is dropped down a clear plastic tube

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15
Q

why is the cylinder dropped through a tube

A
  • so that it cuts through a beam

- in which the total time that it took to cross the beam can be measured

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16
Q

what are the two things that are manually measured in this method

A
  • l, the length of the cylinder

- h, the height of the top of the plastic tube above the light gate

17
Q

after you have repeated it several times to get an average for t, how would you calculate the velocity of the cylinder passing through the light gate

A

v = l / t

18
Q

what would be the gradient of the line if a graph of v^@ against h was plotted

A
  • v^2 = 2gh
  • its already arranged for v^2
  • so the gradient is 2g
19
Q

why have the gradients in both methods been like so

A
  • because you dont include the h in your gradient
  • as that is what already has a axis
  • it is effectively taken out
20
Q

if you have no special equipment what method would you use

A
  • you would use the same principle as method 1
  • measure the time it takes for an object to fall a measured height with a stopwatch
  • repeat for an average time
  • repeat with varying heights using a meter rule