Coordination Ved Sir Lectr1

Question 1

Summarise the application of electroneutrality principle

Answer 1

1. Thermodynamic stability of non TM

Question 2

I Berilium and magnesium which one will form CN. 6 and why

Answer 2

Mg because of vacent 3d orbital ,so Beprefer only CN. 4

Question 3

Cobalt,nicely,copper,zinc,lithium ,berilium prefer CN.

Answer 3

4

Question 4

Denticity of hydrazine

Answer 4

1

Question 5

Denticity depends upon the

Answer 5

1. No of dinar sites
2. Chelate ring

Question 6

Stability orer of chelate ring

Answer 6

5>6>…..less stable but formed 4>…not formed 7

Question 7

Why C ≡ O is not ambidentate ligand

Answer 7

The energy level of oxygen is very low

Question 8

On going from 3d<4d<5d what will be increases

Answer 8

Inertness [ effective increase ]

Question 9

In non transition metal
Labile
Inert

Answer 9

+1,+2
+3 borderline
+4,+5,+6

Question 10

Entropy koine se mechanism me increase karti hai

Answer 10

Dissociative me

Question 11

Substitution in square planer complex

Answer 11

It has TBP geometry
The equatorial position occupy by leaving group, leaving group ke opposite wala Trans ligand , incoming ligand

Question 12

Square planer complex labile hote hai to at low concentration of nucleophile they react with solvent and after that they remove solvent and react with nucleophile order of reaction

Answer 12

Rate = 1st order + 2nd order

Question 13

Square planer +nucleophile ( excess)
Order of rxn

Answer 13

Pseudo 1st order

Question 14

npt =
Nucleophilicity parametre

Answer 14

Log( k2) y / (k)s