Confidence Intervals Flashcards
What do CI work out?
A range of likely values for the true but unknown population parameter based on sample data, together with a measure of confidence / likelihood that the range contains the true value.
A CI is wider if…
1) more confidence
2) greater variance
3) smaller sample size n
CV for 90% CI for normal
+- 1.645
CV for 95% CI for normal
+- 1.960
CV for 99% CI for normal
+- 2.575
CI for M is given by…
M belongs to [X bar +-CV Se(X bar)]
Where Standard error = sqrt sigma^2 or S^2 / n
What does a 90% CI for M mean?
90% of occasions M is inside the interval. 10% of the time we find M < or > the limits.
Finding CI for M: if X is normal but sigma^2 unknown, from what distribution do we get the CV from?
T distribution with n-1 DOF.
If the underlying distribution is a Bernoulli trial, what distribution do we get the CV from for CI for M?
Usually would use M=p and sigma^2 = p(1-p) but obviously we don’t know p otherwise we wouldn’t be constructing a CI for M as its exact value would be known. So we use S^2 (p(1-p) based on sample data) and as long as n>25/30 invoke CLT = approx normal.
If n=21 and we do not know the underlying distribution, what can we do?
1) do nothing
2) assume normality - then if sigma^2 unknown = t distribution
What do we assume before constructing difference in means CI?
That X1 and X2 are independent random samples (so covariance = 0)
CI for M1 - M2
(X1 bar - X2 bar) +- CV Se(X1 bar - X2 bar)
Standard error = sqrt (sigma1^2 / n1 + sigma2^2 / n2) if sigmas known.
Suppose distribution of X1 & X2 is unknown, sigmas unknown, n1 & n2 > 25/30. What distribution?
Invoke CLT = approx normal.
CV from Z tables.
Use S1^2 and S2^2.
Suppose X1 & X2 normal, sigmas unknown. What test?
T test.
If sigmas equal, pool sample variance & CV from t with DOF = n1+n2 - 2
If sigmas not equal, do not pool variances, CV from t with DOF see complex formula.
What condition must be satisfied to construct CI for the variance of a distribution?
X MUST be normally distributed